Information
You have already completed the quiz before. Hence you can not start it again.
You must sign in or sign up to start the quiz.
You have to finish following quiz, to start this quiz:
Loading...
-
Question 1 of 3
Find tanθtanθ given the following
sinθ=-2129sinθ=−2129
cosθcosθ>>00
Write fractions in the format “a/b”
Incorrect
Loaded: 0%
Progress: 0%
0:00
First, draw a triangle that satisfies sinθ=2129sinθ=2129 (the sign is disregarded in this process)
Using the triangle above, use the Pythagoras’ Theorem to solve for xx
a2a2++b2b2 |
== |
c2c2 |
Pythagoras’ Theorem |
212212++x2x2 |
== |
292292 |
Substitute values |
441+x2441+x2 |
== |
841841 |
441+x2441+x2 -411−411 |
== |
841841 -411−411 |
Subtract 441441 from both sides |
x2x2 |
== |
400400 |
√x2√x2 |
== |
√400√400 |
Get the square root of both sides |
xx |
== |
±20±20 |
Recall the right triangle to find the value of tanθtanθ
tanθtanθ |
== |
oppositeadjacentoppositeadjacent |
|
|
== |
21202120 |
Remember that tanθ=sinθcosθtanθ=sinθcosθ
sinθ=-2129sinθ=−2129
cosθcosθ>>00
Since sinθsinθ is negative and cosθcosθ is positive, tanθtanθ is negative
Therefore, tanθ=-2120tanθ=−2120
-
Question 2 of 3
Find cosθcosθ given the following
sinθ=-35sinθ=−35
3π23π2<<θθ<<2π2π
Write fractions in the format “a/b”
Incorrect
Loaded: 0%
Progress: 0%
0:00
First, draw a triangle that satisfies sinθ=35sinθ=35 (the sign is disregarded in this process)
Using the triangle above, use the Pythagoras’ Theorem to solve for xx
a2a2++b2b2 |
== |
c2c2 |
Pythagoras’ Theorem |
3232++x2x2 |
== |
5252 |
Substitute values |
9+x29+x2 |
== |
2525 |
9+x29+x2 -9−9 |
== |
2525 -9−9 |
Subtract 99 from both sides |
x2x2 |
== |
1616 |
√x2√x2 |
= |
√16 |
Get the square root of both sides |
x |
= |
±4 |
Recall the right triangle to find the value of cosθ
cosθ |
= |
adjacenthypotenuse |
|
|
= |
45 |
Identify the appropriate quadrants in the unit circle to find the sign of cosθ
In the fourth quadrant, cosθ is positive
Therefore, cosθ=45
-
Question 3 of 3
Find sinθ given the following
Write fractions in the format “a/b”
Incorrect
Loaded: 0%
Progress: 0%
0:00
First, draw a triangle that satisfies cosθ=513 (the sign is disregarded in this process)
Using the triangle above, use the Pythagoras’ Theorem to solve for x
a2+b2 |
= |
c2 |
Pythagoras’ Theorem |
y2+52 |
= |
132 |
Substitute values |
y2+25 |
= |
169 |
y2+25 -25 |
= |
169 -25 |
Subtract 25 from both sides |
y2 |
= |
144 |
√y2 |
= |
√144 |
Get the square root of both sides |
y |
= |
±12 |
Recall the right triangle to find the value of sinθ
sinθ |
= |
oppositehypotenuse |
|
|
= |
1213 |
Identify the appropriate quadrants in the unit circle to find the sign of cosθ
In the third quadrant, sinθ is negative
Therefore, sinθ=-1213