Ratios 3

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Ratios 3

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Question 1 of 4

1. Question
Simplify

$\frac{2}{3} : 1$ $2/3:1$
- (2) $:$ $:$ (3)
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A ratio compares quantities of the same type given in the same units.

Remove the fraction by cancelling out the denominator

$\frac{2}{3}$ $2/3$ $:$ $:$ $1$ $1$

$\frac{2}{3}$ $2/3$ $\times 3$ $times3$ $:$ $:$ $1$ $1$ $\times 3$ $times3$ Multiply both sides by $3$ $3$

$2$ $2$ $:$ $:$ $3$ $3$ $\frac{3}{3} = 1$ $3/3=1$

$2 : 3$ $2:3$
Question 2 of 4

2. Question
Simplify

$2 \frac{1}{3} : 1$ $2 1/3:1$
- (7) $:$ $:$ (3)
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A ratio compares quantities of the same type given in the same units.

First, convert the mixed fraction into an improper fraction

$2 \frac{1}{3}$ $2 1/3$ $:$ $:$ $1$ $1$

$\frac{7}{3}$ $7/3$ $:$ $:$ $1$ $1$

Next, remove the fraction by cancelling out the denominator

$\frac{7}{3}$ $7/3$ $:$ $:$ $1$ $1$

$\frac{7}{3}$ $7/3$ $\times 3$ $times3$ $:$ $:$ $1$ $1$ $\times 3$ $times3$ Multiply both sides by $3$ $3$

$7$ $7$ $:$ $:$ $3$ $3$ $\frac{3}{3} = 1$ $3/3=1$

$7 : 3$ $7:3$
Question 3 of 4

3. Question
Find the ratio of the shaded boxes to the unshaded boxes.
- (3) $:$ $:$ (5)
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A ratio compares quantities of the same type given in the same units.

First, count the number of shaded and unshaded boxes.

$Shaded Boxes$ $\text(Shaded Boxes)$ $=$ $=$ $9$ $9$

$Unshaded Boxes$ $\text(Unshaded Boxes)$ $=$ $=$ $15$ $15$

Next, write the values as a ratio and simplify

$9$ $9$ $:$ $:$ $15$ $15$

$9$ $9$ $\div 3$ $divide3$ $:$ $:$ $15$ $15$ $\div 3$ $divide3$ $3$ $3$ is the highest common factor

$3$ $3$ $:$ $:$ $5$ $5$

$3 : 5$ $3:5$
Question 4 of 4

4. Question
Simplify

$1 \frac{1}{2} min : 10 sec$ $1 1/2 \text(min):10 \text(sec)$
- (9) $:$ $:$ (1)
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A ratio compares quantities of the same type given in the same units.

First, convert the minutes into seconds

$1 minute$ $1 \text(minute)$ $=$ $=$ $60 seconds$ $60 \text(seconds)$

$1.5 \times \frac{60}{1}$ $1.5xx(60)/1$ $=$ $=$ $90$ $90$

$90$ $90$ $:$ $:$ $10$ $10$

Finally, divide both sides by their highest common factor

$90$ $90$ $:$ $:$ $10$ $10$

$90$ $90$ $\div 10$ $divide10$ $:$ $:$ $10$ $10$ $\div 10$ $divide10$ $10$ $10$ is the highest common factor

$9$ $9$ $:$ $:$ $1$ $1$

$9 : 1$ $9:1$

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1. Question

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2. Question

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3. Question

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4. Question

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Quizzes

$\frac{2}{3}$ $2/3$	$:$ $:$	$1$ $1$

$\frac{2}{3}$ $2/3$ $\times 3$ $times3$	$:$ $:$	$1$ $1$ $\times 3$ $times3$	Multiply both sides by $3$ $3$

$2$ $2$	$:$ $:$	$3$ $3$	$\frac{3}{3} = 1$ $3/3=1$

$2 \frac{1}{3}$ $2 1/3$	$:$ $:$	$1$ $1$

$\frac{7}{3}$ $7/3$	$:$ $:$	$1$ $1$

$Shaded Boxes$ $\text(Shaded Boxes)$	$=$ $=$	$9$ $9$
$Unshaded Boxes$ $\text(Unshaded Boxes)$	$=$ $=$	$15$ $15$

$1.5 \times \frac{60}{1}$ $1.5xx(60)/1$	$=$ $=$	$90$ $90$

$90$ $90$	$:$ $:$	$10$ $10$