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Question 1 of 4
A factory produces 250250 cans within a minute. How long will it take to make 20002000 cans?
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A rate is a ratio of two different units.
Quad boxes are used to easily find rates
(Use cross product method)
First, fill up the quad boxes with the three known values and have the unknown value be xx.
Cans |
Min |
250250 |
11 |
20002000 |
xx |
Next, equate the two columns and solve for xx.
25020002502000 |
== |
1x1x |
|
250(x)250(x) |
== |
1(2000)1(2000) |
Cross multiply |
250x250x÷250÷250 |
== |
20002000÷250÷250 |
Divide both sides by 250250 |
xx |
== |
88 |
Since xx is under the minmin column in the quad boxes, the value will be 8 minutes8 minutes.
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Question 2 of 4
A factory produces 250250 cans within a minute. How many cans can they produce in an 88-hour shift?
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A rate is a ratio of two different units.
Quad boxes are used to easily find rates
(Use cross product method)
First, convert the hours into minutes
1 hour1 hour |
== |
60 minutes60 minutes |
Next, fill up the quad boxes with the three known values and have the unknown value be xx.
Cans |
Min |
250250 |
11 |
xx |
480480 |
Finally, equate the two columns and solve for xx.
250x250x |
== |
14801480 |
|
1(x)1(x) |
== |
250(480)250(480) |
Cross multiply |
xx |
== |
120 000120 000 |
Since xx is under the canscans column in the quad boxes, the value will be 120 000 cans120 000 cans.
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Question 3 of 4
A jet flies at a speed of 680 km/hour680 km/hour. How far can it travel within 3030 minutes?
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A rate is a ratio of two different units.
Quad boxes are used to easily find rates
(Use cross product method)
First, convert the hours into minutes
1 hour1 hour |
== |
60 minutes60 minutes |
Next, fill up the quad boxes with the three known values and have the unknown value be xx.
km |
Min |
680680 |
6060 |
xx |
3030 |
Finally, equate the two columns and solve for xx.
680x680x |
== |
60306030 |
|
60(x)60(x) |
== |
680(30)680(30) |
Cross multiply |
60x60x÷60÷60 |
== |
20 40020 400÷60÷60 |
Divide both sides by 6060 |
xx |
== |
340340 |
Since xx is under the kmkm column in the quad boxes, the value will be 340 kilometres340 kilometres.
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Question 4 of 4
A man has been driving at 70 km/hour70 km/hour for 99 hours. How far did he travel?
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Speed-Distance-Time Formula
Speed=DistanceTimeSpeed=DistanceTime
First, derive the formula to solve for the distance.
SpeedSpeed |
== |
DistanceTimeDistanceTime |
|
DistanceDistance |
== |
Speed⋅TimeSpeed⋅Time |
Cross multiply |
Next, substitute the known values to the derived formula.
SpeedSpeed |
== |
70 kmhour70 kmhour |
|
TimeTime |
== |
9 hours9 hours |
DistanceDistance |
== |
Speed⋅TimeSpeed⋅Time |
|
|
== |
70kmhour⋅9hours70kmhour⋅9hours |
Substitute known values |
|
|
== |
630 km630 km |
Hours cancel out |
Distance=630 kmDistance=630 km