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Question 1 of 5
Rationalise the denominator:
54√354√3
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For the answer to be in simplest form, the denominator should be a rational number.
Multiply the numerator and the denominator by √3√3
54√354√3 |
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54√3×54√3×√3√3√3√3 |
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5×√34√3×√35×√34√3×√3 |
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5√34√95√34√9 |
Apply Multiplication Property |
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5√34×35√34×3 |
√9=3√9=3 |
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5√3125√312 |
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Question 2 of 5
Rationalise the denominator:
√5x2√8√5x2√8
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For the answer to be in simplest form, the denominator should be a rational number.
Multiply the numerator and the denominator by √8√8
√5x2√8√5x2√8 |
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√5x2√8×√5x2√8×√8√8√8√8 |
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√5x2×√8√8×√8√5x2×√8√8×√8 |
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√40x28√40x28 |
Apply Multiplication Property |
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√4x2×108√4x2×108 |
Simplify the numerator |
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2x√1082x√108 |
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x√104x√104 |
Reduce to lowest terms |
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Question 3 of 5
Rationalise the denominator:
8√53√28√53√2
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For the answer to be in simplest form, the denominator should be a rational number.
Multiply the numerator and the denominator by √2√2
8√53√28√53√2 |
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8√53√2×8√53√2×√2√2 |
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8√5×√23√2×√2 |
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8√103√4 |
Apply Multiplication Property |
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8√103×2 |
√4=2 |
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8√106 |
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4√103 |
Simplify the fraction |
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Question 4 of 5
Rationalise the denominator:
√3+1√7
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For the answer to be in simplest form, the denominator should be a rational number.
Multiply the numerator and the denominator by √7
√3+1√7 |
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√3+1√7×√7√7 |
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(√3+1)×√7√7×√7 |
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√7×√3+√7×1√7×√7 |
Apply Distributive Property |
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√21+√7√49 |
Apply Multiplication Property |
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√21+√77 |
√49=7 |
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Question 5 of 5
Rationalise the denominator:
15+√3+15-√3
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We can add two fractions by finding a common denominator. One common denominator is always the two denominators multiplied.
For the answer to be in simplest form, the denominator should be a rational number.
Find a common denominator by multiplying the denominators.
Write the fraction sum using the common denominator
15+√3+15-√3 |
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1(5+√3)+1(5-√3)(5+√3)(5-√3) |
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5+√3+5-√325-5√3+5√3-√3×√3 |
Expand the brackets |
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1025-√3×√3 |
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1025-3 |
√3×√3=3 |
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1022 |