Find the Hypotenuse 3
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Question 1 of 3
1. Question
Solve for `x`.
Round off answer to `1` decimal place- (10.6)m
Hint
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Finding the Hypo$$\large\textbf{+}$$enuse
Use $$\large\textbf{+}$$
$${\color{#00880a}{c}}^2={\color{#9a00c7}{a}}^2 \hspace{1mm} \large\textbf{+} \hspace{1mm} \normalsize{{\color{#007DDC}{b}}^2}$$The longest side of a right triangle is called a hypotenuse (`c`). It is also the side opposite the right angle.Label the values, and then substitute them into Pythagoras’ Theorem.
`c=x``a=8` m`b=7` m$${\color{#00880a}{c}}^2$$ `=` $${\color{#9a00c7}{a}}^2 + {\color{#007DDC}{b}}^2$$ Pythagoras’ Theorem $${\color{#00880a}{x}}^2$$ `=` $${\color{#9a00c7}{8}}^2 + {\color{#007DDC}{7}}^2$$ `x^2` `=` `64+49` `x^2` `=` `113` `sqrt(x^2)` `=` `sqrt113` Get the square root of both sides `x` `=` `10.63014` m `x` `=` `10.6` m Round off to `1` decimal place `10.6` m -
Question 2 of 3
2. Question
Solve for `y`.
Round off answer to `2` decimal places- (21.93)m
Hint
Help VideoCorrect
Fantastic!
Incorrect
Finding the Hypo$$\large\textbf{+}$$enuse
Use $$\large\textbf{+}$$
$${\color{#00880a}{c}}^2={\color{#9a00c7}{a}}^2 \hspace{1mm} \large\textbf{+} \hspace{1mm} \normalsize{{\color{#007DDC}{b}}^2}$$The longest side of a right triangle is called a hypotenuse (`c`). It is also the side opposite the right angle.Label the values, and then substitute them into Pythagoras’ Theorem.
`c=y``a=9` m`b=20` m$${\color{#00880a}{c}}^2$$ `=` $${\color{#9a00c7}{a}}^2 + {\color{#007DDC}{b}}^2$$ Pythagoras’ Theorem $${\color{#00880a}{y}}^2$$ `=` $${\color{#9a00c7}{9}}^2 + {\color{#007DDC}{20}}^2$$ `y^2` `=` `81+400` `y^2` `=` `481` `sqrt(y^2)` `=` `sqrt481` Get the square root of both sides `y` `=` `21.9317…` m `y` `=` `21.93` m Round off to `1` decimal place `21.93` m -
Question 3 of 3
3. Question
Solve for `m`.
Round off answer to `2` decimal places- (30.61)km
Hint
Help VideoCorrect
Correct!
Incorrect
Finding the Hypo$$\large\textbf{+}$$enuse
Use $$\large\textbf{+}$$
$${\color{#00880a}{c}}^2={\color{#9a00c7}{a}}^2 \hspace{1mm} \large\textbf{+} \hspace{1mm} \normalsize{{\color{#007DDC}{b}}^2}$$The longest side of a right triangle is called a hypotenuse (`c`). It is also the side opposite the right angle.Label the values, and then substitute them into Pythagoras’ Theorem.
`c=m``a=19` km`b=24` km$${\color{#00880a}{c}}^2$$ `=` $${\color{#9a00c7}{a}}^2 + {\color{#007DDC}{b}}^2$$ Pythagoras’ Theorem $${\color{#00880a}{m}}^2$$ `=` $${\color{#9a00c7}{19}}^2 + {\color{#007DDC}{24}}^2$$ `m^2` `=` `361+576` `m^2` `=` `937` `sqrt(m^2)` `=` `sqrt937` Get the square root of both sides `m` `=` `30.610457…` km `m` `=` `30.61` km Round off to `1` decimal place `30.61` km
Quizzes
- Find the Hypotenuse 1
- Find the Hypotenuse 2
- Find the Hypotenuse 3
- Find a Side 1
- Find a Side 2
- Find a Side 3
- Pythagoras Problems 1
- Pythagoras Problems 2
- Pythagoras Problems 3
- Pythagoras Theorem Mixed Review 1
- Pythagoras Theorem Mixed Review 2
- Pythagoras Theorem Mixed Review 3
- Pythagoras Theorem Mixed Review 4