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Question 1 of 4
8%8% of an amount is $40$40. Find the original amount.
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First, use a rectangle and list down the values: percentages on the left side and amounts on the right side.
Known value=$40Known value=$40
Percentage of known value=8%Percentage of known value=8%
Percentage of total value=100%Percentage of total value=100%
Total value=?Total value=?
Proportion MethodProportion Method
To find the missing value, cross-multiply the fraction of the percentages by the fraction of the given and total value.
Let the original amount be xx
81008100 |
== |
40x40x |
81008100 |
== |
40x40x |
|
8×x8×x |
== |
40×10040×100 |
Cross multiply |
8x8x |
== |
40004000 |
8x8x÷8÷8 |
== |
4000÷84000÷8 |
Divide both sides by 88 |
xx |
== |
500500 |
Hence, $40$40 is 8%8% of $500_$500−−−−
1% Method -Unitary Method1% Method −Unitary Method
First, find the 1%1% of the total value by dividing both known values by 88.
8%8% |
== |
$40$40 |
|
88÷8÷8 |
== |
4040÷8÷8 |
Divide both sides by 88 |
11 |
== |
55 |
Hence, 1%1% of the original amount is $5$5.
To find the total value, which is 100%100% of the value, multiply the 1%1% value, which is 55, by 100100.
100%100% |
== |
5×1005×100 |
|
== |
500500 |
Hence, $40$40 is 8%8% of $500_$500−−−−
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Question 2 of 4
5%5% of an amount is $135$135. Find the original amount.
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First, use a rectangle and list down the values: percentages on the left side and amounts on the right side.
Known value=$135Known value=$135
Percentage of known value=5%Percentage of known value=5%
Percentage of total value=100%Percentage of total value=100%
Total value=?Total value=?
Proportion MethodProportion Method
To find the missing value, cross-multiply the fraction of the percentages by the fraction of the given and total value.
Let the original amount be xx
51005100 |
== |
135x135x |
|
5×x5×x |
== |
135×100135×100 |
Cross multiply |
5x5x |
== |
13,50013,500 |
5x5x÷5÷5 |
== |
13,500÷513,500÷5 |
Divide both sides by 55 |
xx |
== |
27002700 |
Hence, $135$135 is 5%5% of $2700_$2700−−−−−
1% Method -Unitary Method1% Method −Unitary Method
First, find the 1%1% of the total value by dividing both known values by 55.
5%5% |
== |
$135$135 |
|
55÷5÷5 |
== |
135135÷5÷5 |
Divide both sides by 55 |
11 |
== |
2727 |
Hence, 1%1% of the original amount is $27$27.
To find the total value, which is 100%100% of the value, multiply the 1%1% value, which is 2727, by 100100.
100%100% |
== |
27×10027×100 |
|
== |
27002700 |
Hence, $135$135 is 5%5% of $2700_$2700−−−−−
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Question 3 of 4
3%3% of an amount is 180 kg180 kg. Find the original amount.
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First, use a rectangle and list down the values: percentages on the left side and amounts on the right side.
Known value=180 kgKnown value=180 kg
Percentage of known value=3%Percentage of known value=3%
Percentage of total value=100%Percentage of total value=100%
Total value=?Total value=?
Proportion MethodProportion Method
To find the missing value, cross-multiply the fraction of the percentages by the fraction of the given and total value.
Let the original amount be xx
31003100 |
== |
180x180x |
|
3×x3×x |
== |
180×100180×100 |
Cross multiply |
3x3x |
== |
18,00018,000 |
3x3x÷3÷3 |
== |
18,000÷318,000÷3 |
Divide both sides by 33 |
xx |
== |
60006000 |
Hence, 180kg180kg is 3%3% of 6000kg_6000kg−−−−−−−
1% Method -Unitary Method1% Method −Unitary Method
First, find the 1%1% of the total value by dividing both known values by 33.
3%3% |
== |
180 kg180 kg |
|
33÷3÷3 |
== |
180180÷3÷3 |
Divide both sides by 33 |
11 |
== |
6060 |
Hence, 1%1% of the original amount is 60 kg60 kg.
To find the total value, which is 100%100% of the value, multiply the 1%1% value, which is 6060, by 100100.
100%100% |
== |
60×10060×100 |
|
== |
60006000 |
Hence, 180kg180kg is 3%3% of 6000kg_6000kg−−−−−−−
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Question 4 of 4
A school has 657657 students who travel to school by bus. If this represents 73%73% of the students, how many students does the school have?
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First, summarise the data and draw a diagram for easier understanding of the problem
Number of students taking the bus=657Number of students taking the bus=657
Percentage of students taking the bus=73%Percentage of students taking the bus=73%
Percentage of total number of students=100%Percentage of total number of students=100%
Total number of students=?Total number of students=?
Proportion MethodProportion Method
To find the missing value, cross-multiply the fraction of the percentages by the fraction of the given and total value.
Let the original amount be xx
7310073100 |
== |
657x657x |
|
73×x73×x |
== |
657×100657×100 |
Cross multiply |
73x73x |
== |
65,70065,700 |
73x73x÷73÷73 |
== |
65,700÷7365,700÷73 |
Divide both sides by 7373 |
xx |
== |
900900 |
Hence, the total number of students is 900_900−−−
1% Method -Unitary Method1% Method −Unitary Method
First, find the 1%1% of the total number of students by dividing both known values by 7373.
73%73% |
== |
657 students657 students |
|
7373÷73÷73 |
== |
657657÷73÷73 |
Divide both sides by 7373 |
11 |
== |
99 |
Hence, 1%1% of the original amount is 9 students9 students.
To find the total number of students, which is 100%100% of the value, multiply the 1%1% value, which is 99, by 100100.
100%100% |
== |
9×1009×100 |
|
== |
900900 |
Hence, the total number of students is 900_900−−−