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Factorise Trinomials (Quadratics) w Coefficient more than 1>
Factorise Trinomials (Quadratics) w Coefficient more than 1 (2)Factorise Trinomials (Quadratics) w Coefficient more than 1 (2)
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Question 1 of 4
1. Question
Factorise.`5x^2+22x+8`Hint
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When factorising trinomials, use the Cross Method.Use the cross method to factorise `5x^2+22x+8`Start by drawing a cross.
Now, find two values that will multiply into `5x^2` and write them on the left side of the cross.`5x` and `x` fits this description.
Next, find two numbers that will multiply into `8` and, when cross-multiplied to the values to the left side, will add up to `22x`.Product Sum when Cross-Multiplied `2` and `4` `8` `(5xtimes4)+(xtimes2)=22x` `8` and `1` `8` `(5xtimes1)+(xtimes8)=13x` `2` and `4` fits this description.Now, write `2` and `4` on the right side of the cross.
Finally, group the values in a row with a bracket and combine the brackets.
Therefore, the factorised expression is `(5x+2)(x+4)`.`(5x+2)(x+4)` -
Question 2 of 4
2. Question
Factorise.`3x^2-26x+35`Hint
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When factorising trinomials, use the Cross Method.Use the cross method to factorise `3x^2-26x+35`Start by drawing a cross.Now, find two values that will multiply into `3x^2` and write them on the left side of the cross.`3x` and `x` fits this description.
Next, find two numbers that will multiply into `35` and, when cross-multiplied to the values to the left side, will add up to `-26x`.Product Sum when Cross-Multiplied `-7` and `-5` `35` `[3xtimes(-5)]+[xtimes(-7)]=-22x` `-5` and `-7` `35` `[3xtimes(-7)]+[xtimes(-5)]=-26x` `-5` and `-7` fits this description.Now, write `-5` and `-7` on the right side of the cross.
Finally, group the values in a row with a bracket and combine the brackets.
Therefore, the factorised expression is `(3x-5)(x-7)`.`(3x-5)(x-7)` -
Question 3 of 4
3. Question
Factorise.`6x^2-17x-3`Hint
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When factorising trinomials, use the Cross Method.Use the cross method to factorise `6x^2-17x-3`Start by drawing a cross.Now, find two values that will multiply into `6x^2` and write them on the left side of the cross.`6x` and `x` fits this description.
Next, find two numbers that will multiply into `-3` and, when cross-multiplied to the values to the left side, will add up to `-17x`.Product Sum when Cross-Multiplied `1` and `-3` `-3` `[6xtimes(-3)]+(xtimes1)=-17x` `3` and `-1` `-3` `(6xtimes1)+[xtimes(-6)]=-5x` `1` and `-3` fits this description.Now, write `1` and `-3` on the right side of the cross.
Finally, group the values in a row with a bracket and combine the brackets.
Therefore, the factorised expression is `(6x+1)(x-3)`.`(6x+1)(x-3)` -
Question 4 of 4
4. Question
Factorise.`5u^2+19u+12`Hint
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When factorising trinomials, use the Cross Method.Use the cross method to factorise `5u^2+19u+12`Start by drawing a cross.Now, find two values that will multiply into `5u^2` and write them on the left side of the cross.`5u` and `u` fits this description.
Next, find two numbers that will multiply into `12` and, when cross-multiplied to the values to the left side, will add up to `19u`.Product Sum when Cross-Multiplied `2` and `6` `12` `(5utimes6)+(utimes2)=32u` `3` and `4` `12` `(5utimes4)+(utimes3)=23u` `4` and `3` `12` `(5utimes3)+(utimes4)=19u` `1` and `12` `12` `(5utimes12)+(utimes1)=61u` `4` and `3` fits this description.Now, write `4` and `3` on the right side of the cross.
Finally, group the values in a row with a bracket and combine the brackets.
Therefore, the factorised expression is `(5u+4)(u+3)`.`(5u+4)(u+3)`
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