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Question 1 of 4
Add the following
18+2318+23
Write the fraction in the format “a/b”
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Add fractions with unlike denominators by transforming the fractions so that they have the like denominators
Method One
Start with listing out multiples of 88 and 33
Multiples of 88:
816243240816243240
Multiples of 33:
369121518212427369121518212427
The LCDLCD of 88 and 33 is 2424
Use the LCDLCD as the denominator for both fractions then proceed with adding.
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18+2318+23 |
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== |
1×38×3+2×83×81×38×3+2×83×8 |
Multiply each fraction so that their denominator becomes 2424 |
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== |
324+1624324+1624 |
Add the numerators |
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== |
19241924 |
Keep the same denominator |
Method Two
First, multiply the two denominators. Use the product as a denominator for a new fraction.
To get the numerator, cross multiply the given addition problem and add the products.
18+23 |
= |
(1×3)+(8×2)24 |
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= |
3+1624 |
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= |
1924 |
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Question 2 of 4
Subtract the following
1316-38
Write the fraction in the format “a/b”
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Subtract fractions with unlike denominators by transforming the fractions so that they have the like denominators
Start with listing out multiples of 16 and 8
The LCD of 16 and 8 is 16
Use the LCD as the denominator for both fractions then proceed with subtracting.
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1316-38 |
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= |
1316−3×28×2 |
Multiply by 2 so that the denominator becomes 16 |
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= |
1316−616 |
Subtract the numerators |
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= |
716 |
Keep the same denominator |
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Question 3 of 4
Add the following. Simplify if needed.
17+17
Write fractions in the format “a/b”
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To add fractions with like denominators, add the numerators
and keep the same denominator.
Since the denominators are the same, add only the numerators
17+17 |
= |
27 |
Keep the same denominator |
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Question 4 of 4
Subtract the following
45-12
Write the fraction in the format “a/b”
Incorrect
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Subtract fractions with unlike denominators by transforming the fractions so that they have the like denominators
Method One
Start with listing out multiples of 5 and 2
Use the LCD as the denominator for both fractions then proceed with subtracting.
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45-12 |
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= |
4×25×2−1×52×5 |
Multiply each fraction so that their denominator becomes 20 |
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= |
810−510 |
Subtract the numerators |
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= |
310 |
Keep the same denominator |
Method Two
First, multiply the two denominators. Use the product as a denominator for a new fraction.
To get the numerator, cross multiply the given addition problem and subtract the products.
45−12 |
= |
(4×2)−(5×1)10 |
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= |
8-510 |
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= |
310 |