Minimum Spanning Trees 2
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Question 1 of 5
1. Question
Find the length of the minumum spanning tree of this network.- (42)
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Kruskal’s Algorithm is a method of finding a minimum spanning tree by selecting the edges by least to most.First, draw a diagram to plot the vertices of the network.Next, list down the edges with the values going from least to most. Since we only need `5` edges to make a spanning tree for this network, pick the `5` edges with the least value.`AB` `=` `7` `AE` `=` `8` `CD` `=` `8` `BF` `=` `9` `CE` `=` `10` `BC` `=` `12` `FC` `=` `13` `ED` `=` `14` `FE` `=` `15` Now draw the `5` edges with the lowest values in the diagramNotice that all the vertices are now connected and we have `5` edges, one less than the number of vertices.This diagram fits the criteria of a spanning tree and is also using the edges with the minimum weights.Finally, get the sum of the edges of the spanning tree.minimum length `=` `7+8+8+9+10` `=` `42` `42` -
Question 2 of 5
2. Question
Find the length of the minimum spanning tree of this network.- (82)
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Kruskal’s Algorithm is a method of finding a minimum spanning tree by selecting the edges by least to most.First, draw a diagram to plot the vertices of the network.Next, list down the edges with the values going from least to most. Since we only need `6` edges to make a spanning tree for this network, pick the `6` edges with the least value.`EF` `=` `10` `FG` `=` `10` `GC` `=` `12` `BG` `=` `14` `AE` `=` `16` `BC` `=` `16` `FD` `=` `20` `ED` `=` `22` `EB` `=` `38` `DC` `=` `40` Notice that `AE` has a lower value than `FD`, but since using `AE` will create a cycle, we will be using the next least valued edge, which is `FD`Now draw the `6` edges with the lowest values in the diagramNotice that all the vertices are now connected and we have `5` edges, one less than the number of vertices.This diagram fits the criteria of a spanning tree and is also using the edges with the minimum weights.Finally, get the sum of the edges of the spanning tree.minimum length `=` `10+10+12+14+16+20` `=` `82` `82` -
Question 3 of 5
3. Question
This network shows the lengths of the pipes needed to connect each location in metres. What is the smallest connection distance between all these points in metres?- (220) `\text(m)`
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Kruskal’s Algorithm is a method of finding a minimum spanning tree by selecting the edges by least to most.We can use Kruskal’s Algorithm to find the minimum spanning tree of this network.Start by drawing a diagram to plot the vertices of the network.Next, list down the edges with the values going from least to most. Since we only need `6` edges to make a spanning tree for this network, pick the `6` edges with the least value.`10 \text(m)` `10 \text(m)` `30 \text(m)` `50 \text(m)` `60 \text(m)` `60 \text(m)` `70 \text(m)` `80 \text(m)` `85 \text(m)` `90 \text(m)` `100 \text(m)` Now draw the `6` edges with the lowest values in the diagramNotice that all the vertices are now connected and we have `6` edges, one less than the number of vertices.This diagram fits the criteria of a spanning tree and is also using the edges with the minimum weights.Finally, get the sum of the edges of the spanning tree.minimum length `=` `10+10+30+50+60+60` `=` `220 \text(m)` Therefore, the least length of pipes that can be used to connect all the locations is `220 \text(m)`.`220 \text(m)` -
Question 4 of 5
4. Question
This network shows the cost of each fiber optic cable used to connect each location in dollars. What is the minimal cost to connect all of these locations?- `$` (7500)
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Kruskal’s Algorithm is a method of finding a minimum spanning tree by selecting the edges by least to most.We can use Kruskal’s Algorithm to find the minimum spanning tree of this network.Start by drawing a diagram to plot the vertices of the network.Next, list down the edges with the values going from least to most. Since we only need `6` edges to make a spanning tree for this network, pick the `6` edges with the least value.`$800` `$900` `$1000` `$1100` `$1400` `$1800` `$1900` `$3200` `$3500` `$4000` `$5600` `$5900` Notice that the edge with the value of `$1400` has a lower cost that the edges costing `$1800` and `$1900`, but since using the edge costing `$1400` will create a cycle, we will be using the next two least valued edges instead.Now draw the `6` edges with the lowest values in the diagramNotice that all the vertices are now connected and we have `6` edges, one less than the number of vertices.This diagram fits the criteria of a spanning tree and is also using the edges with the minimum weights.Finally, get the sum of the edges of the spanning tree.minimum length `=` `800+900+1000+1100+1800+1900` `=` `$7500` Therefore, the least cost of fiber optic cables that can be used to connect all the locations is `$7500`.`$7500` -
Question 5 of 5
5. Question
The diagram shows a plan for a golf course including a pump `P` to distribute the water to the whole course. What is the minimum length of hose in metres that can be used to distribute the water from the pump to all the locations?- (670) `\text(m)`
Hint
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Fantastic!
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Kruskal’s Algorithm is a method of finding a minimum spanning tree by selecting the edges by least to most.We can use Kruskal’s Algorithm to find the minimum spanning tree of this network.Start by drawing a diagram to plot the vertices of the network.Next, list down the edges with the values going from least to most. Since we only need `6` edges to make a spanning tree for this network, pick the `6` edges with the least value.`80 \text(m)` `90 \text(m)` `100 \text(m)` `105 \text(m)` `110 \text(m)` `115 \text(m)` `120 \text(m)` `140 \text(m)` `170 \text(m)` `185 \text(m)` `195 \text(m)` `210 \text(m)` Notice that the edges with the lengths of `115`, `120`, `140` and `170` metres has a lower lengths than than the edge that is `185` metres long, but since using the edges with the lengths of `115`, `120`, `140` and `170` metres will create a cycle, we will be using the edge that is `185` metres long instead.Now draw the `6` edges with the lowest values in the diagramNotice that all the vertices are now connected and we have `6` edges, one less than the number of vertices.This diagram fits the criteria of a spanning tree and is also using the edges with the minimum weights.Finally, get the sum of the edges of the spanning tree.minimum length `=` `80+90+100+105+110+185` `=` `670 \text(m)` Therefore, the least length of water hose that can be used to provide water to all the locations is `670 \text(metres)` long.`670 \text(m)`
Quizzes
- Vertices and Edges
- Degrees 1
- Degrees 2
- Degrees 3
- Drawing A Network 1
- Drawing A Network 2
- Completing a Table from a Network Diagram
- Network from Maps and Plans
- Identifying Paths and Cycles
- Eulerian Trails and Circuits 1
- Eulerian Trails and Circuits 2
- Identifying Spanning Trees
- Minimum Spanning Trees 1
- Minimum Spanning Trees 2
- Shortest Path 1
- Shortest Path 2