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Volume of Composite Shapes 1Volume of Composite Shapes 1
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Question 1 of 5
1. Question
Find the volume of the figure- Volume = (25200) cm3
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Volume of a Rectangular Prism
Volume =length×width×depthLabelling the given lengths
Smaller Rectanglelength=30width=20depth=12Larger Rectanglelength=60width=25 (55-30)depth=12First, find the area of the smaller rectangleArea = length×width = 30×20=600 cm2 Next, find the area of the larger rectangleArea = length×width = 60×25=1500 cm2 Next, add the area of the smaller rectangle and the area of the larger rectangle= 600+1500 Plug in the two areas = 2100 cm2 Finally, multiply the area by the depth to find the volumeVolume = area×depth Finding the volume = 2100×12 Plug in the known lengths = 25200 cm3 The given measurements are in centimetres, so the volume is measured as centimetres cubedVolume=25200 cm3 -
Question 2 of 5
2. Question
Find the volume of the figureRound your answer to the nearest whole numberUse π=3.141592654- Volume = (31616, 31605, 31625) cm3
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Volume of a Rectangular Prism
Volume =length×breadth×heightVolume of a Cone
Volume=13×π×radius2×heightLabelling the given lengths
Coneradius=18height=62Rectangular Prismlength=46breadth=46height=5First, find the area of the rectangleArea = length×breadth = 46×46=2116 cm2 Next, multiply the area by the height to find the volumeVolume = area×height Finding the volume = 2116×5 Plug in the known lengths = 10580 cm3 Next, use the formula to find the volume of the coneUse π=3.141592654 See π explainedVolume = 13×π×radius2×height = 13×3.141592654×182×62 = 21036.10441 cm3 Finally, add the volume of the cube and the volume of the cone= 10580+21036.10441 Plug in the two volumes = 31616.10441 = 31616 cm3 Rounded to the nearest whole number The given measurements are in centimetres, so the volume is measured as centimetres cubedVolume=31616 cm3The answer will depend on which π you use.In this solution we used: π=3.141592654.Using Answer π=3.141592654 31616 cm3 π=3.14 31605 cm3 π=227 31625 cm3 -
Question 3 of 5
3. Question
Find the volume of the figureRound your answer to 2 decimal placesUse π=3.141592654- Volume = (179.07, 178.98, 179.14) cm3
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Volume of a Hemisphere
Volume=12×43×π×radius3Volume of a Cone
Volume=13×π×radius2×heightLabelling the given lengths
radius=?diameter=6height=13We need to add volume of the hemisphere and the coneFirst, recall that the radius is equal to half of the diameterradius = 12×6 radius = 3 Next, use the formula to find the volume of the hemisphereUse π=3.141592654 See π explainedVolume = 12×43×π×radius3 = 12×43×3.141592654×33 = 56.54866 cm3 Next, use the formula to find the volume of the coneUse π=3.141592654 See π explainedVolume = 13×π×radius2×height = 13×3.141592654×32×13 = 122.52211 cm3 Finally, add the volume of the sphere and the volume of the cone= 56.54866+122.52211 Plug in the two volumes = 179.07078 = 179.07 cm3 Rounded to 2 decimal places The given measurements are in centimetres, so the volume is measured as centimetres cubedVolume=179.07 cm3The answer will depend on which π you use.In this solution we used: π=3.141592654.Using Answer π=3.141592654 179.07 cm3 π=3.14 178.98 cm3 π=227 179.14 cm3 -
Question 4 of 5
4. Question
Find the volume of the figureNote: The cylinder is hollowRound your answer to 2 decimal placesUse π=3.141592654- Volume = (2211.68, 2210.56, 2212.57) cm3
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Volume of a Cylinder
Volume=π×radius2×heightLabelling the given lengths
Outer Cylinderradius=?diameter=12height=22Inner Cylinderradius=2height=22We need to find the volume of the figure, not including its hollow partFirst, recall that the radius is equal to half of the diameterradius = 12×12 radius(Larger Circle) = 6 Next, use the formula to find the area of the Outer CircleUse π=3.141592654 See π explainedArea = π×radius2 = 3.141592654×62 = 113.09733 cm2 Next, find the area of the Inner CircleUse π=3.141592654 See π explainedArea = π×radius2 = 3.141592654×22 = 12.56637 cm2 Now, subtract the area of the Inner Circle from the Outer Circle= 113.09733-12.56637 Plug in the two areas = 100.53096 cm2 Finally, multiply the area by the height to find the volumeVolume = area×height Finding the volume = 100.53096×22 Plug in the known lengths = 2211.68122 = 2211.68 cm3 Rounded to 2 decimal places The given measurements are in centimetres, so the volume is measured as centimetres cubedVolume=2211.68 cm3The answer will depend on which π you use.In this solution we used: π=3.141592654.Using Answer π=3.141592654 2211.68 cm3 π=3.14 2210.56 cm3 π=227 2212.57 cm3 -
Question 5 of 5
5. Question
Find the volume of the figureRound your answer to two decimal places- Volume = (508.94, 508.68, 509.14) cm3
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Volume of a Cylinder
Volume=π×radius2×heightLabelling the given lengths
Short Cylindersradius=?diameter=12height=2Long Cylinderradius=?diameter=3height=8First, recall that the radius is equal to half of the diameterradius = 12×12 radius(short cylinders) = 6 radius = 12×3 radius(long cylinder) = 1.5 Next, use the formula to find the volume of the two short cylindersUse π=3.141592654 See π explainedVolume = 3.141592654×radius2×height = 3.141592654×62×2 = 226.19467 Since there are two short cylinders, we multiply our answer by two.Volume = 226.19467×2 = 452.38934 cm3 Now, use the formula to find the volume of the long cylinderUse π=3.141592654 See π explainedVolume = 3.141592654×radius2×height = 3.141592654×1.52×8 = 56.54866 cm3 Finally, add the volume of the two short cylinders and the volume of the long cylinder= 452.38934+56.54866 Plug in the two volumes = 508.938 = 508.94 cm3 Rounded to 2 decimal places The given measurements are in centimetres, so the volume is measured as centimetres cubedVolume=508.94 cm3The answer will depend on which π you use.In this solution we used: π=3.141592654.Using Answer π=3.141592654 508.94 cm3 π=3.14 508.68 cm3 π=227 509.14 cm3
Quizzes
- Volume of Shapes 1
- Volume of Shapes 2
- Volume of Shapes 3
- Volume of Shapes 4
- Volume of Composite Shapes 1
- Volume of Composite Shapes 2
- Surface Area of Shapes 1
- Surface Area of Shapes 2
- Surface Area of Shapes 3
- Surface Area and Volume Mixed Review 1
- Surface Area and Volume Mixed Review 2
- Surface Area and Volume Mixed Review 3
- Surface Area and Volume Mixed Review 4