Two Step Equations 4
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Question 1 of 5
1. Question
Solve`y/(-5) +6=-4`- `y=` (50)
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Inverse Operations
When moving a term to the other side of an equation, the operation is inversed.To solve for `y`, it needs to be alone on one side.Start by moving `6` to the other side by subtracting `6` from both sides of the equation.$$\frac{\color{#00880A}{y}}{-5}+6$$ `=` `-4` $$\frac{\color{#00880A}{y}}{-5}+6\color{#CC0000}{-6}$$ `=` `-4` `-6` $$\frac{\color{#00880A}{y}}{-5}$$ `=` `-10` `6-6` cancels out Next, remove `1/(-5)` by multiplying both sides of the equation by `-5`.$$\frac{\color{#00880A}{y}}{-5}$$ `=` `-10` $$\frac{\color{#00880A}{y}}{-5}\color{#CC0000}{\times-5}$$ `=` `-10``xx-5` `y` `=` `50` `1/(-5) times-5` cancels out Check our workTo confirm our answer, substitute `y=50` to the original equation.`y/(-5) +6` `=` `-4` `50/(-5) +6` `=` `-4` Substitute `y=50` `-10+6` `=` `-4` `-4` `=` `-4` Since the equation is true, the answer is correct.`y=50` -
Question 2 of 5
2. Question
Solve for `x``x/6+2=9`- `x=` (42)
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To solve for `x`, get `x` by itselfSubtract `2` from both sides of the equation`frac{x}{6}+2` `-2` `=` `9` `-2` `frac{x}{6}``+2` `-2` `=` `9` `-2` `2-2` cancels out `frac{x}{6}` `=` `7` Finally, multiply both sides of the equation by `6``frac{x}{6}``times6` `=` `7``times6` `frac{6x}{6}` `=` `7``times6` `x` `=` `42` The coefficient `6/6` cancels out `x=42` -
Question 3 of 5
3. Question
Solve for `x``x/7-2=3`- `x=` (35)
Hint
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To solve for `x`, get `x` by itselfAdd `2` to both sides of the equation`frac{x}{7}-2` `+2` `=` `3` `+2` `frac{x}{7}``-2` `+2` `=` `3` `+2` `-2+2` cancels out `frac{x}{7}` `=` `5` Finally, multiply both sides of the equation by `7``frac{x}{7}``times7` `=` `5``times7` Multiply both sides by `7` `frac{7x}{7}` `=` `5``times7` `x` `=` `35` The coefficient `7/7` cancels out `x=35` -
Question 4 of 5
4. Question
Solve for `a``a/10+4=12`- `a=` (80)
Hint
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To solve for `a`, get `a` by itselfSubtract `4` from both sides of the equation`frac{a}{10}+4` `-4` `=` `12` `-4` `frac{a}{10}``+4` `-4` `=` `12` `-4` `4-4` cancels out `frac{a}{10}` `=` `8` Finally, multiply both sides of the equation by `10``frac{a}{10}``times10` `=` `8``times10` `frac{10a}{10}` `=` `8``times10` `a` `=` `80` The coefficient `10/10` cancels out `a=80` -
Question 5 of 5
5. Question
Solve for `v``v/7 + 1=3`- `v=` (14)
Correct
Fantastic!
Incorrect
To solve for `v`, get `v` by itselfSubtract `1` from both sides of the equation`v/7 + 1` `-1` `=` `3` `-1` `v/7``+1` `-1` `=` `3` `-1` `1-1` cancels out `v/7` `=` `2` Finally, multiply both sides of the equation by `7``v/7``xx 7` `=` `2``xx 7` `(7v)/7` `=` `2``xx 7` `v` `=` `14` The coefficient `7/7` cancels out `v=14`
Quizzes
- One Step Equations – Add and Subtract 1
- One Step Equations – Add and Subtract 2
- One Step Equations – Add and Subtract 3
- One Step Equations – Add and Subtract 4
- One Step Equations – Multiply and Divide 1
- One Step Equations – Multiply and Divide 2
- One Step Equations – Multiply and Divide 3
- One Step Equations – Multiply and Divide 4
- Two Step Equations 1
- Two Step Equations 2
- Two Step Equations 3
- Two Step Equations 4
- Multi-Step Equations 1
- Multi-Step Equations 2
- Solve Equations using the Distributive Property 1
- Solve Equations using the Distributive Property 2
- Solve Equations using the Distributive Property 3
- Equations with Variables on Both Sides 1
- Equations with Variables on Both Sides 2
- Equations with Variables on Both Sides 3
- Equations with Variables on Both Sides (Fractions) 1
- Equations with Variables on Both Sides (Fractions) 2
- Solve Equations with Variables on Both Sides using the Distributive Property 1
- Solve Equations with Variables on Both Sides using the Distributive Property 2
- Solve Equations with Variables on Both Sides using the Distributive Property 3
- Solve Equations with Variables on Both Sides using the Distributive Property 4
- Equation Word Problems 1
- Equation Word Problems 2
- Equation Word Problems 3
- Equation Word Problems 4
- Equation Word Problems (Age)
- Equation Word Problems (Money)
- Equation Word Problems (Harder)
- Equation Problems with Substitution
- Equation Problems (Geometry) 1
- Equation Problems (Geometry) 2
- Equation Problems (Perimeter)
- Equation Problems (Area)
- Change the Subject of an Equation 1
- Change the Subject of an Equation 2
- Change the Subject of an Equation 3