Solve Equations with Variables on Both Sides using the Distributive Property 2

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Question 1 of 5

Solve

$7(m+2)+2(6-2m)=4m$

$m=$ (26)

Question 2 of 5

Solve

$2(y+3)+5(y+2)=4(9-4y)-3(16-3y)$

$y=$ (-2)

Question 3 of 5

Solve for

$x$

$6(x+2)-4(x-1)=20$

$x=$ (2)

Question 4 of 5

Solve for

$v$

$-8v+7(v+8)=32-7v$

$v=$ (-4)

Question 5 of 5

Solve for

$k$

$11-5k=4+7(1-5k)$

$k=$ (0)

$7$ $($ $m$ $+2)+$ $2$ $(6-2$ $m$ $)$	$=$	$4$ $m$
$7$ $m$ $+$ $7$ $(2)+$ $2$ $(6)+$ $2$ $(-2$ $m$ $)$	$=$	$4$ $m$
$7$ $m$ $+14+12-4$ $m$	$=$	$4$ $m$
$3$ $m$ $+26$	$=$	$4$ $m$

$3$ $m$ $+26$	$=$	$4$ $m$
$3$ $m$ $+26$ $-3m$	$=$	$4$ $m$ $-3m$
$26$	$=$	$m$	$3m-3m$ cancels out
$m$	$=$	$26$

$7(m+2)+2(6-2m)$	$=$	$4m$
$7(26+2)+2(6-2(26))$	$=$	$4(26)$	Substitute $m=26$
$7(28)+2(6-52)$	$=$	$104$
$196+2(-46)$	$=$	$104$
$196-92$	$=$	$104$
$104$	$=$	$104$

$2$ $($ $y$ $+3)+$ $5$ $($ $y$ $+2)$	$=$	$4$ $(9-4$ $y$ $)-$ $3$ $(16-3$ $y$ $)$
$2$ $y$ $+$ $2$ $(3)+$ $5$ $y$ $+$ $5$ $(2)$	$=$	$4$ $(9)-$ $4$ $(4$ $y$ $)-$ $3$ $(16)-$ $3$ $(-3$ $y$ $)$
$2$ $y$ $+6+5$ $y$ $+10$	$=$	$36-16$ $y$ $-48+9$ $y$
$7$ $y$ $+16$	$=$	$-7$ $y$ $-12$

$7$ $y$ $+16$	$=$	$-7$ $y$ $-12$
$7$ $y$ $+16$ $-16$	$=$	$-7$ $y$ $-12$ $-16$
$7$ $y$	$=$	$-7$ $y$ $-28$	$16-16$ cancels out

Solve Equations with Variables on Both Sides using the Distributive Property 2

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Quiz summary

Information

1. Question

Hint

Excellent!

Inverse Operations

Distributive Property

2. Question

Hint

Fantastic!

Inverse Operations

Distributive Property

3. Question

Hint

Correct!

4. Question

5. Question

Well Done!

Quizzes

$7$ $y$	$=$	$-7$ $y$ $-28$
$7$ $y$ $+7y$	$=$	$-7$ $y$ $-28$ $+7y$
$14$ $y$	$=$	$-28$	$-7y+7y$ cancels out

$14$ $y$	$=$	$-28$
$14$ $y$ $-:14$	$=$	$-28$ $-:14$
$y$	$=$	$-2$	$14divide14$ cancels out

$2(y+3)+5(y+2)$	$=$	$4(9-4y)-3(16-3y)$
$2(-2+3)+5(-2+2)$	$=$	$4(9-4(-2))-3(16-3(-2))$	Substitute $y=-2$
$2(1)+5(0)$	$=$	$4(9+8)-3(16+6)$
$2+0$	$=$	$4(17)-3(22)$
$2$	$=$	$68-66$
$2$	$=$	$2$

$6$ $(x+2)$ $-4$ $(x-1)$	$=$	$20$

$6$ $(x+2)$	$=$	$(x xx$ $6$ $)+(2xx$ $6$ $)$
	$=$	$6x+12$

$-4$ $(x-1)$	$=$	$(x xx$ $(-4)$ $)+(-1xx$ $(-4)$ $)$
	$=$	$-4x+4$

$(6x+12)$ $+$ $(-4x+4)$	$=$	$20$
$2x+16$	$=$	$20$

$2x+16$ $-16$	$=$	$20$ $-16$
$2x$ $+16$ $-16$	$=$	$20$ $-16$	$16-16$ cancels out
$2x$	$=$	$4$
$2x$ $divide2$	$=$	$4$ $divide2$	Divide both sides by $2$
$2$ $x$ $divide2$	$=$	$4$ $divide2$	$times2divide2$ cancels out
$x$	$=$	$2$

$-8v$ $+7$ $(v+8)$	$=$	$32-7v$
$-8v+((v xx$ $7$ $)+(8xx$ $7$ $))$	$=$	$32-7v$
$-8v+7v+56$	$=$	$32-7v$
$-v+56$	$=$	$32-7v$

$-v+56$ $+7v$	$=$	$32-7v$ $+7v$	Add $7v$ to both sides
$-v+56$ $+7v$	$=$	$32$ $-7v$ $+7v$	$-7v+7v$ cancels out
$6v+56$	$=$	$32$
$6v+56$ $-56$	$=$	$32$ $-56$	Subtract $56$ from both sides
$6v$ $+56$ $-56$	$=$	$32$ $-56$	$56-56$ cancels out
$6v$	$=$	$-24$
$6v$ $-:6$	$=$	$-24$ $-:6$	Divide both sides by $6$
$6$ $v$ $-:6$	$=$	$-24$ $-:6$	$times6divide6$ cancels out
$v$	$=$	$-4$

$11-5k$	$=$	$4$ $+7$ $(1-5k)$
$11-5k$	$=$	$4+((1 xx$ $7$ $)+(-5k xx$ $7$ $))$
$11-5k$	$=$	$4+7-35k$
$11-5k$	$=$	$11-35k$

$11-5k$ $+5k$	$=$	$11-35k$ $+5k$	Add $5k$ to both sides
$11$ $-5k$ $+5k$	$=$	$11-35k$ $+5k$	$-5k+5k$ cancels out
$11$	$=$	$11-30k$
$11$ $-11$	$=$	$11-30k$ $-11$	Subtract $11$ from both sides
$11$ $-11$	$=$	$11$ $-30k$ $-11$	$11-11$ cancels out on both sides
$0$	$=$	$-30k$
$0$ $-:(-30)$	$=$	$30k$ $-:(-30)$	Divide both sides by $-30$
$0$ $-:(-30)$	$=$	$30$ $k$ $-:(-30)$	$times(-30)divide(-30)$ cancels out
$0$	$=$	$k$
$k$	$=$	$0$