Simpsons Rule
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Question 1 of 7
1. Question
Find the area under the curve y=x24- Area= (4.6667) square units
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Simpsons Rule
∫baf(x)dx≈b-a6[f(a)+4f(a+b2)+f(b)]First, construct a table of values for both x and y given the equation.y=x24x 2 3 4 y Substitute x=2 into the given equation.y = 224 Substitute the value of x = 44 Simplify y = 1 f(a) = 1 x 2 3 4 y 1 Substitute x=3 into the given equation.y = 324 Substitute the value of x y = 94 Simplify f(a+b2) = 94 x 2 3 4 y 1 94 Repeat this process for each x-valuex 2 3 4 y 1 94 4 Apply Simpsons RuleA ≈ ∫baf(x)dx ≈ b−a6[f(a)+4f(a+b)2+f(b)] Simpsons Rule formula ≈ 4−26[1+4(94)+4] Substitute known values ≈ 26[5+364] Simplify ≈ 13[14] ≈ 143 ≈ 4.6667 4.6667 square units -
Question 2 of 7
2. Question
Find the area under the curve y=2x- Area= (43.333)
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Simpsons Rule
∫baf(x)dx≈h3[y0+yL+2(y2+y4+…)+4(y1+y3+…)]First, find the values of a, b and n from the given equation∫51y = 2x a=1(lower limit)b=5(upper limit)n=4(number of strips in given diagram)Solve for hh = b−an = 5−14 Substitute values of a, b, and n = 44 Simplify h = 1 First, construct a table of values for both x and y given the equation.y=2xx 1 2 3 4 5 y Substitute x=1 into the given equation.y = 21 Substitute the value of x = 21 Simplify y0 = 2 x 1 2 3 4 5 y 2 Substitute x=2 into the given equation.y = 22 Substitute the value of x y1 = 4 Simplify x 1 2 3 4 5 y 2 4 Repeat this process for each x-valuex 1 2 3 4 5 y 2 4 8 16 32 Apply Simpsons RuleA ≈ ∫baf(x)dx ≈ h3[y0+yL+2(y2+y4+…)+4(y1+y3+…)] Simpsons Rule formula ≈ 13[2+32+2(8)+4(4+16)] Substitute known values ≈ 13[34+16+80] Simplify ≈ 13[130] ≈ 1303 ≈ 43.333 43.333 -
Question 3 of 7
3. Question
Find the area under the curve y=6x- Area= (4.159)
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Simpsons Rule
∫baf(x)dx≈h3[y0+yL+2(y2+y4+…)+4(y1+y3+…)]First, find the values of a, b and n from the given equation∫63y = 6x a=3(lower limit)b=6(upper limit)n=6(number of strips in given diagram)Solve for hh = b−an = 6−36 Substitute values of a, b, and n = 36 Simplify h = 12 First, construct a table of values for both x and y given the equation.y=2xx 3 3.5 4 4.5 5 5.5 6 y Substitute x=3 into the given equation.y = 63 Substitute the value of x = 2 Simplify y0 = 2 x 3 3.5 4 4.5 5 5.5 6 y 2 Substitute x=3.5 into the given equation.y = 63.5 Substitute the value of x y1 = 63.5 Simplify x 3 3.5 4 4.5 5 5.5 6 y 2 63.5 Repeat this process for each x-valuex 3 3.5 4 4.5 5 5.5 6 y 2 63.5 64 64.5 65 65.5 1 Apply Simpsons RuleA ≈ ∫baf(x)dx ≈ h3[y0+yL+2(y2+y4+…)+4(y1+y3+…)] Simpsons Rule formula ≈ 123[2+1+2(64+65)+4(63.5+64.5+65.5)] Substitute known values ≈ 16[3+2(2710)+4(4.1385)] Simplify ≈ 16[3+5410+16.554113] ≈ 16(24.954113) ≈ 4.159 4.159 -
Question 4 of 7
4. Question
Find and estimate the area of the orange parcel of land.- Area= (1960) m2
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Simpsons Rule
∫baf(x)dx≈h3[y0+yL+2(y2+y4+…)+4(y1+y3+…)]First, find the value of h from the given illustration.h = 20 m Next, identify the values for substitution into Simpsons Rule.y0 y1 y2 y3 yL 21.5 24 22.5 28 19.5 Apply Simpsons RuleA ≈ h3[y0+yL+2(y2+y4+…)+4(y1+y3+…)] Simpsons Rule formula ≈ 203[21.5+19.5+2(22.5)+4(24+28)] Substitute known values ≈ 203[41+45+208] Simplify ≈ 203[294] ≈ 1960 1960 m2 -
Question 5 of 7
5. Question
Find and estimate the area of the huge block of land.- Area= (251333 1/3, 251333.33, 251333.3333) m2
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Simpsons Rule
∫baf(x)dx≈h3[y0+yL+2(y2+y4+…)+4(y1+y3+…)]First, find the value of h from the given illustration.h = 200 m Next, identify the values for substitution into Simpsons Rule.y0 y1 y2 y3 y4 y5 yL 0 150 290 320 210 180 170 Apply Simpsons RuleA ≈ h3[y0+yL+2(y2+y4+…)+4(y1+y3+…)] Simpsons Rule formula ≈ 2003[0+170+2(290+210)+4(150+320+180)] Substitute known values ≈ 2003[170+1000+4(2600)] Simplify ≈ 2003[3770] ≈ 25133313 25133313 m2 -
Question 6 of 7
6. Question
Find and estimate the area of the yellow parcel of land.- Area= (45000) m2
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Simpsons Rule
∫baf(x)dx≈h3[y0+yL+2(y2+y4+…)+4(y1+y3+…)]First, find the value of h from the given illustration.h = 4004 h = 100 m Next, identify the values for substitution into Simpsons Rule.y0 y1 y2 y3 yL 110 98 102 124 148 Apply Simpsons RuleA ≈ h3[y0+yL+2(y2+y4+…)+4(y1+y3+…)] Simpsons Rule formula ≈ 1003[110+148+2(102)+4(98+124)] Substitute known values ≈ 1003[258+204+888] Simplify ≈ 1003[1350] ≈ 45000 45000 m2 -
Question 7 of 7
7. Question
Find and estimate the area of the irregular piece of land.- Area= (5558 2/3) m2
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Simpsons Rule
∫baf(x)dx≈h3[df+4dm+dL]First, find the value of h from the given illustration.h = 22 m Next, identify the values for substitution into Simpsons Rule.df dm dL 0 49 68 df dm dL 68 88 74 Apply Simpsons Rule to find A1A1 ≈ h3[df+4dm+dL] Simpsons Rule formula ≈ 223[0+4(49)+68] Substitute known values ≈ 223[68+196] Simplify ≈ 223[264] A1 ≈ 1936 m2 Apply Simpsons Rule to find A2A2 ≈ h3[df+4dm+dL] Simpsons Rule formula ≈ 223[68+4(88)+74] Substitute known values ≈ 223[142+352] Simplify ≈ 223[494] A2 ≈ 362223 m2 Add A1 and A2A ≈ A1+A2 Combine the areas ≈ 1936+362223 ≈ 555823 555823 m2
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