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Question 1 of 4
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Use the following laws to simplify the logarithmic expression
logbxp |
= |
plogbx |
logbb |
= |
1 |
|
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log5125-3log525 |
|
= |
log5 53 -3log525 |
125=53 |
|
= |
log553-3log5 52 |
25=52 |
|
= |
3log55-3(2)log55 |
logbxp=plogbx |
|
= |
3(1)-6(1) |
logbb=1 |
|
= |
3-6 |
|
= |
-3 |
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Question 2 of 4
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Remove the coefficients from the logarithms so they can be combined
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3log102+log1012.5 |
= |
log1023+log1012.5 |
logbxp=plogbx |
= |
log108+log1012.5 |
Next, compare the given expression to one of the laws of logarithms and identify corresponding components
logbx |
+ |
logby |
log108 |
+ |
log1012.5 |
Substitute the components into the law of logarithms
logbx+logby |
= |
logbxy |
log108+log1012.5 |
= |
log10(8)(12.5) |
|
= |
log10100 |
|
|
log10100 |
|
= |
log10102 |
100=102 |
|
= |
2log1010 |
logbxp=plogbx |
|
= |
2(1) |
logbb=1 |
|
= |
2 |
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Question 3 of 4
Incorrect
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Use the following laws to simplify the logarithmic expression
logbxp |
= |
plogbx |
logbb |
= |
1 |
|
|
2log33√3+log3√27 |
|
= |
2log33√3+log3√33 |
27=33 |
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= |
2log3313+log3332 |
Change the surds into exponents |
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|
= |
13(2)log33+ 32log33 |
logbxp=plogbx |
|
|
= |
23log33+32log33 |
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|
= |
23×1+32×1 |
logbb=1 |
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|
= |
23+32 |
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= |
46+96 |
Find the common denominator |
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|
= |
136 |
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= |
216 |
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Question 4 of 4
Solve
loga(x3x+2)+loga(x+2)
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First, compare the given expression to one of the laws of logarithms and identify corresponding components
logbx |
+ |
logby |
|
logax3x+2 |
+ |
loga(x+2) |
Substitute the components into the law of logarithms
logbx+logby |
= |
logbxy |
|
logax3x+2+loga(x+2) |
= |
logax3x+2×x+2 |
|
|
= |
logax3 |
x+2x+2=1 |
logax3 |
= |
3logax |
logbxp=plogbx |