Rationalising the Denominator 4
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Question 1 of 6
1. Question
Rationalise the denominator:
√6+√32√6
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Division Property of Square Roots
√ab=√a√bFor the answer to be in simplest form, the denominator should be a rational number.Multiply the numerator and the denominator by √6√6+√32√6 = √6+√32√6×√6√6 = (√6+√3)×√62×(√6×√6) = √6× √6+√3×√62×(√6×√6) Apply Distributive Property of Multiplication = √36+√182×√36 Apply the Multiplication Property = 6+3√212 √36=6 and √18=3√2 = 2+√24 Simplify 2+√24 -
Question 2 of 6
2. Question
Rationalise the denominator:
√10–√55√10
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Division Property of Square Roots
√ab=√a√bFor the answer to be in simplest form, the denominator should be a rational number.Multiply the numerator and the denominator by √10√10–√55√10 = √10–√55√10×√10√10 = (√10–√5)×√105×(√10×√10) = √10× √10-√5×√105×(√10×√10) Apply Distributive Property of Multiplication = √100–√505×√100 Apply the Multiplication Property = 10–5√250 √100=10 and √50=5√2 = 2-√210 Simplify 2-√210 -
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Question 3 of 6
3. Question
Rationalise the denominator:23-√2-
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For the answer to be in simplest form, the denominator should be a rational number.Since the denominator is a binomial, multiply the numerator and the denominator by 3+√2This is simply the denominator but with the opposite operation23-√2 = 23-√2×3+√23+√2 = 2×(3+√2)(3-√2)×(3+√2) = 6+2√29-2 Apply Multiplication Property = 6+2√29-2 Apply Multiplication Property = 6+2√27 6+2√27 -
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Question 4 of 6
4. Question
Rationalise the denominator:2√3-1-
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For the answer to be in simplest form, the denominator should be a rational number.Multiply the numerator and the denominator by √3+12√3-1 = 2√3-1×√3+1√3+1 = 2×(√3+1)(√3-1)×(√3+1) = 2√3+2√9+√3-√3-1 Expand the brackets = 2√3+23-1 √9=3 = 2√3+22 = √3+1 √3+1 -
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Question 5 of 6
5. Question
Rationalise the denominator:√6+1√6+√2-
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For the answer to be in simplest form, the denominator should be a rational number.Multiply the numerator and the denominator by √6-√2√6+1√6+√2 = √6+1√6+√2×√6-√2√6-√2 = (√6+1)(√6-√2)(√6+√2)(√6-√2) = 6-√12+√6-√26-2 Expand the brackets = 6-2√3+√6-√24 6-2√3+√6-√24 -
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Question 6 of 6
6. Question
Rationalise the denominator:√5-√2√5+√2-
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For the answer to be in simplest form, the denominator should be a rational number.Multiply the numerator and the denominator by √5-√2√5-√2√5+√2 = √5-√2√5+√2×√5-√2√5-√2 = (√5-√2)(√5-√2)(√5+√2)(√5-√2) = 5-√10-√10+25-2 Expand the brackets = 7-2√103 7-2√103 -
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Quizzes
- Simplify Square Roots 1
- Simplify Square Roots 2
- Simplify Square Roots 3
- Simplify Square Roots 4
- Simplify Surds with Variables 1
- Simplify Surds with Variables 2
- Simplify Surds with Variables 3
- Rewriting Entire and Mixed Surds 1
- Rewriting Entire and Mixed Surds 2
- Add and Subtract Surd Expressions (Basic) 1
- Add and Subtract Surd Expressions (Basic) 2
- Add and Subtract Surd Expressions (Basic) 3
- Add and Subtract Surd Expressions 1
- Add and Subtract Surd Expressions 2
- Add and Subtract Surd Expressions 3
- Multiply Surd Expressions 1
- Multiply Surd Expressions 2
- Multiply Surd Expressions 3
- Multiply Surd Expressions 4
- Divide Surd Expressions 1
- Divide Surd Expressions 2
- Divide Surd Expressions 3
- Multiply and Divide Surd Expressions
- Simplify Surd Expressions using the Distributive Property 1
- Simplify Surd Expressions using the Distributive Property 2
- Simplify Surd Expressions using the Distributive Property 3
- Simplify Binomial Surd Expressions using the FOIL Method 1
- Simplify Binomial Surd Expressions using the FOIL Method 2
- Rationalising the Denominator 1
- Rationalising the Denominator 2
- Rationalising the Denominator 3
- Rationalising the Denominator 4
- Rationalising the Denominator using Conjugates