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Question 1 of 5
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Inverse Operations
When moving a term to the other side of an equation, the operation is inversed.
To solve for yy, it needs to be alone on one side.
Remove -3−3 by dividing both sides of the equation by -3−3.
-3−3yy |
== |
-415−415 |
|
-3−3yy |
== |
-215−215 |
Turn the mixed number into an improper fraction |
|
-3−3yy÷(-3)÷(−3) |
== |
-215−215÷(-3)÷(−3) |
|
yy |
== |
-215−215×1-3×1−3 |
-3÷-3−3÷−3 cancels out |
|
yy |
== |
-21-15−21−15 |
Simplify |
|
yy |
== |
7575 |
|
yy |
== |
125125 |
Turn the improper fraction back to a mixed number |
Check our work
To confirm our answer, substitute y=125y=125 to the original equation.
-3y−3y |
== |
-415−415 |
|
-3(125)−3(125) |
== |
-415−415 |
Substitute y=125y=125 |
|
-3(75)−3(75) |
== |
-415−415 |
Turn the mixed number into an improper fraction |
|
-215−215 |
== |
-415−415 |
|
-415−415 |
== |
-415−415 |
Turn the improper fraction back to a mixed number |
Since the equation is true, the answer is correct.
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Question 2 of 5
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Inverse Operations
When moving a term to the other side of an equation, the operation is inversed.
To solve for xx, it needs to be alone on one side.
Remove 1-81−8 by multiplying both sides of the equation by -8−8.
-15−15 |
== |
x−8x−8 |
|
-15−15×(-8)×(−8) |
== |
x−8×(−8)x−8×(−8) |
|
120120 |
== |
xx |
1-8×(-8)1−8×(−8) cancels out |
xx |
== |
120120 |
Check our work
To confirm our answer, substitute x=120x=120 to the original equation.
-15−15 |
== |
x-8x−8 |
|
-15−15 |
== |
120-8120−8 |
Substitute x=120x=120 |
|
-15−15 |
== |
-15−15 |
Since the equation is true, the answer is correct.
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Question 3 of 5
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Inverse Operations
When moving a term to the other side of an equation, the operation is inversed.
To solve for mm, it needs to be alone on one side.
Remove -19−19 by multiplying both sides of the equation by -9−9.
−m9−m9 |
== |
-4−4 |
|
−m9×(−9)−m9×(−9) |
== |
-4−4×(-9)×(−9) |
|
9m99m9 |
== |
3636 |
|
mm |
== |
3636 |
9999 cancels out |
Check our work
To confirm our answer, substitute m=36m=36 to the original equation.
-m9−m9 |
== |
-4−4 |
|
-369−369 |
== |
-4−4 |
Substitute m=36m=36 |
|
-4−4 |
== |
-4−4 |
Since the equation is true, the answer is correct.
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Question 4 of 5
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Inverse Operations
When moving a term to the other side of an equation, the operation is inversed.
First, make sure that the variable is not a denominator by multiplying both sides of the equation by uu.
−70u−70u |
== |
55 |
|
−70u×u−70u×u |
== |
55 ×u×u |
|
-70−70 |
== |
55uu |
1u×u1u×u cancels out |
To solve for uu, it needs to be alone on one side.
Remove 55 by dividing both sides of the equation by 55.
-70−70 |
== |
55uu |
-70−70÷5÷5 |
== |
55uu÷5÷5 |
-14−14 |
== |
uu |
5÷55÷5 cancels out |
uu |
== |
-14−14 |
Check our work
To confirm our answer, substitute u=-14u=−14 to the original equation.
-70u−70u |
== |
55 |
|
-70-14−70−14 |
== |
55 |
Substitute u=-14u=−14 |
|
55 |
== |
55 |
Since the equation is true, the answer is correct.
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Question 5 of 5
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Inverse Operations
When moving a term to the other side of an equation, the operation is inversed.
First, make sure that the variable is not a denominator by multiplying both sides of the equation by aa.
12a12a |
== |
-6−6 |
|
12a×a12a×a |
== |
-6−6 ×a×a |
|
1212 |
== |
-6−6aa |
1a×a1a×a cancels out |
To solve for aa, it needs to be alone on one side.
Remove 55 by dividing both sides of the equation by 55.
1212 |
== |
-6−6aa |
1212÷(-6)÷(−6) |
== |
-6−6aa÷(-6)÷(−6) |
-2−2 |
== |
aa |
(-6)÷(-6)(−6)÷(−6) cancels out |
aa |
== |
-2−2 |
Check our work
To confirm our answer, substitute a=-2a=−2 to the original equation.
12a12a |
== |
-6−6 |
|
12-212−2 |
== |
-6−6 |
Substitute a=-2a=−2 |
|
-6−6 |
== |
-6−6 |
Since the equation is true, the answer is correct.