One Step Equations – Add and Subtract 2

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Question 1 of 5

1. Question
Solve

$7 + y = 20$ $7+y=20$
- $y =$ $y=$ (13)
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Inverse Operations

When moving a term to the other side of an equation, the operation is inversed.

To solve for $y$ $y$ , it needs to be alone on one side.

Move $7$ $7$ to the other side by subtracting $7$ $7$ from both sides of the equation.

$7 +$ $7+$ $y$ $y$ $=$ $=$ $20$ $20$

$7 +$ $7+$ $y$ $y$ $- 7$ $-7$ $=$ $=$ $20$ $20$ $- 7$ $-7$

$y$ $y$ $=$ $=$ $13$ $13$ $7 - 7$ $7-7$ cancels out

Check our work

To confirm our answer, substitute $y = 13$ $y=13$ to the original equation.

$7 + y$ $7+y$ $=$ $=$ $20$ $20$

$7 + 13$ $7+13$ $=$ $=$ $20$ $20$ Substitute $y = 13$ $y=13$

$20$ $20$ $=$ $=$ $20$ $20$

Since the equation is true, the answer is correct.

$y = 13$ $y=13$
Question 2 of 5

2. Question
Solve

$a - 4 = 11$ $a-4=11$
- $a =$ $a=$ (15)
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Inverse Operations

When moving a term to the other side of an equation, the operation is inversed.

To solve for $a$ $a$ , it needs to be alone on one side.

Move $4$ $4$ to the other side by adding $4$ $4$ to both sides of the equation.

$a$ $a$ $- 4$ $-4$ $=$ $=$ $11$ $11$

$a$ $a$ $- 4$ $-4$ $+ 4$ $+4$ $=$ $=$ $11$ $11$ $+ 4$ $+4$

$a$ $a$ $=$ $=$ $15$ $15$ $- 4 + 4$ $-4+4$ cancels out

Check our work

To confirm our answer, substitute $a = 15$ $a=15$ to the original equation.

$a - 4$ $a-4$ $=$ $=$ $11$ $11$

$15 - 4$ $15-4$ $=$ $=$ $11$ $11$ Substitute $a = 15$ $a=15$

$11$ $11$ $=$ $=$ $11$ $11$

Since the equation is true, the answer is correct.

$a = 15$ $a=15$
Question 3 of 5

3. Question
Solve for $m$ $m$

$m + 5 = 15$ $m+5=15$
- $m =$ $m=$ (10)
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Isolate the $m$ $m$ variable on one side of the equation

$m + 5$ $m+5$ $- 5$ $-5$ $=$ $=$ $15$ $15$ $- 5$ $-5$ Subtract $5$ $5$ from both sides

$m$ $m$ $+ 5$ $+5$ $- 5$ $-5$ $=$ $=$ $15$ $15$ $- 5$ $-5$ $5 - 5$ $5-5$ cancels out

$m$ $m$ $=$ $=$ $10$ $10$

$m = 10$ $m=10$
Question 4 of 5

4. Question
Solve for $x$ $x$

$x + 12 = 16$ $x+12=16$
- $x =$ $x=$ (4)
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Isolate the $x$ $x$ variable on one side of the equation

$x + 12$ $x+12$ $- 12$ $-12$ $=$ $=$ $16$ $16$ $- 12$ $-12$ Subtract $12$ $12$ from both sides

$x$ $x$ $+ 12$ $+12$ $- 12$ $-12$ $=$ $=$ $16$ $16$ $- 12$ $-12$ $12 - 12$ $12-12$ cancels out

$x$ $x$ $=$ $=$ $4$ $4$

$x = 4$ $x=4$
Question 5 of 5

5. Question
Solve for $y$ $y$

$y - 3 = 9$ $y-3=9$
- $y =$ $y=$ (12)
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Isolate the $y$ $y$ variable on one side of the equation

$y - 3$ $y-3$ $+ 3$ $+3$ $=$ $=$ $9$ $9$ $+ 3$ $+3$ Add $3$ $3$ to both sides

$y$ $y$ $- 3$ $-3$ $+ 3$ $+3$ $=$ $=$ $9$ $9$ $+ 3$ $+3$ $- 3 + 3$ $-3+3$ cancels out

$y$ $y$ $=$ $=$ $12$ $12$

$y = 12$ $y=12$

One Step Equations – Add and Subtract 2

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Quiz summary

Information

1. Question

Hint

Excellent!

Inverse Operations

2. Question

Hint

Fantastic!

Inverse Operations

3. Question

Hint

Correct!

4. Question

Hint

Excellent!

5. Question

Hint

Nice Job!

Quizzes

$7 +$ $7+$ $y$ $y$	$=$ $=$	$20$ $20$
$7 +$ $7+$ $y$ $y$ $- 7$ $-7$	$=$ $=$	$20$ $20$ $- 7$ $-7$
$y$ $y$	$=$ $=$	$13$ $13$	$7 - 7$ $7-7$ cancels out

$7 + y$ $7+y$	$=$ $=$	$20$ $20$
$7 + 13$ $7+13$	$=$ $=$	$20$ $20$	Substitute $y = 13$ $y=13$
$20$ $20$	$=$ $=$	$20$ $20$

$a$ $a$ $- 4$ $-4$	$=$ $=$	$11$ $11$
$a$ $a$ $- 4$ $-4$ $+ 4$ $+4$	$=$ $=$	$11$ $11$ $+ 4$ $+4$
$a$ $a$	$=$ $=$	$15$ $15$	$- 4 + 4$ $-4+4$ cancels out

$a - 4$ $a-4$	$=$ $=$	$11$ $11$
$15 - 4$ $15-4$	$=$ $=$	$11$ $11$	Substitute $a = 15$ $a=15$
$11$ $11$	$=$ $=$	$11$ $11$

$m + 5$ $m+5$ $- 5$ $-5$	$=$ $=$	$15$ $15$ $- 5$ $-5$	Subtract $5$ $5$ from both sides
$m$ $m$ $+ 5$ $+5$ $- 5$ $-5$	$=$ $=$	$15$ $15$ $- 5$ $-5$	$5 - 5$ $5-5$ cancels out
$m$ $m$	$=$ $=$	$10$ $10$

$x + 12$ $x+12$ $- 12$ $-12$	$=$ $=$	$16$ $16$ $- 12$ $-12$	Subtract $12$ $12$ from both sides
$x$ $x$ $+ 12$ $+12$ $- 12$ $-12$	$=$ $=$	$16$ $16$ $- 12$ $-12$	$12 - 12$ $12-12$ cancels out
$x$ $x$	$=$ $=$	$4$ $4$

$y - 3$ $y-3$ $+ 3$ $+3$	$=$ $=$	$9$ $9$ $+ 3$ $+3$	Add $3$ $3$ to both sides
$y$ $y$ $- 3$ $-3$ $+ 3$ $+3$	$=$ $=$	$9$ $9$ $+ 3$ $+3$	$- 3 + 3$ $-3+3$ cancels out
$y$ $y$	$=$ $=$	$12$ $12$