Money Word Problems
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Question 1 of 7
1. Question
Frank earns $14$14 per hour for the first 33 hours of work and $12.50$12.50 an hour after that. How many hours did he work to earn $117$117?- x=x= (6)
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A word problem can be drawn as a diagram and then translated into an equation for easier solving.First, draw a diagram of the problem in order to understand it betternumber of hours worked after 33hrs: xxTranslate the problem into an equation based on the diagram3($14)+x($12.50)3($14)+x($12.50) == $117$117 Solve for xx3($14)+x($12.50)3($14)+x($12.50) == $117$117 42+12.5x42+12.5x == 117117 42+12.5x42+12.5x -42−42 == 117117 -42−42 Subtract 4242 from both sides 12.5x12.5x == 7575 12.5x12.5x÷12.5÷12.5 == 7575÷12.5÷12.5 Divide both sides by 12.512.5 xx == 66 x=6x=6 -
Question 2 of 7
2. Question
A school concert was attended by adults and students. The tickets cost $15$15 per adult and $6$6 per student. The total ticket sales was $2235$2235. If 9595 adults attended the concert, how many students were there?- (135)
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A word problem can be drawn as a diagram and then translated into an equation for easier solving.First, draw a diagram of the problem in order to understand it betternumber of students in the concert: nnTranslate the problem into an equation based on the diagram95($15)+n($6)95($15)+n($6) == $2235$2235 Solve for nn95($15)+n($6)95($15)+n($6) == $2235$2235 1425+6n1425+6n == 22352235 1425+6n1425+6n -1425−1425 == 22352235 -1425−1425 Subtract 14251425 from both sides 6n6n == 810810 6n6n÷6÷6 == 810810÷6÷6 Divide both sides by 66 nn == 135135 135135 -
Question 3 of 7
3. Question
I have 6060 coins. Some are 10¢ and the rest are 20¢ coins. Altogether, they total $10.80. How many of each of the coins do I have?-
Number of 10¢ coins: (12)Number of 20¢ coins: (48)
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A word problem can be drawn as a diagram and then translated into an equation for easier solving.First, draw a diagram of the problem in order to understand it betternumber of 10¢ coins: nnumber of 20¢ coins: 60-nTranslate the problem into an equation based on the diagram and make sure all values are in the same units10¢(n)+20¢(60-n) = $10.80 10¢(n)+20¢(60-n) = 1080¢ Solve for n10¢(n)+20¢(60-n) = 1080¢ 10n+1200-20n = 1080 1200-10n = 1080 1200-10n -1200 = 1080 -1200 Subtract 1200 from both sides -10n = -120 -10n÷(-10) = -120÷(-10) Divide both sides by -10 n = 12 number of 10¢ coins Solve for 60-n60-n = 60-12 Substitute n = 48 number of 20¢ coins Number of 10¢ coins: 12Number of 20¢ coins: 48 -
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Question 4 of 7
4. Question
A bank teller orders a payroll in $20 and $50 notes. She needs 82 notes totalling $2450. Calculate how many of each note she must order.-
Number of $20 notes: (55)Number of $50 notes: (27)
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A word problem can be drawn as a diagram and then translated into an equation for easier solving.First, draw a diagram of the problem in order to understand it betternumber of $20 notes: xnumber of $50 notes: 82-xTranslate the problem into an equation based on the diagram$20(x)+$50(82-x) = $2450 Solve for x$20(x)+$50(82-x) = $2450 20x+4100-50x = 2450 4100-30x = 2450 4100-30x -4100 = 2450 -4100 Subtract 4100 from both sides -30x = -1650 -30x÷(-30) = -1650÷(-30) Divide both sides by -30 x = 55 number of $20 notes Solve for 82-x82-x = 82-55 Substitute x = 27 number of $50 notes Number of $20 notes: 55Number of $50 notes: 27 -
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Question 5 of 7
5. Question
Anna has $8 more than Julie, and Pina has $15 less than Anna. If they have $37 altogether, how much does each person have?-
Anna: $ (20)Julie: $ (12)Pina: $ (5)
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A word problem can be drawn as a diagram and then translated into an equation for easier solving.First, draw a diagram of the problem in order to understand it betterAnna: xJulie: x-8Pina: x-15Translate the problem into an equation based on the diagramx+(x-8)+(x-15) = $37 Solve for xx+(x-8)+(x-15) = $37 3x-23 = 37 3x-23 +23 = 37 +23 Add 23 to both sides 3x = 60 3x÷3 = 60÷3 Divide both sides by 3 x = $20 Anna’s money Solve for x-8x-8 = 20-8 Substitute x = $12 Julie’s money Solve for x-15x-15 = 20-15 Substitute x = $5 Pina’s money Anna: $20Julie: $12Pina: $5 -
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Question 6 of 7
6. Question
James earns $20 a day more than Tom and $27 a day less than Bob. The 3 friends’ total earnings for one day is $733. Find the daily earning of each friend.-
James: $ (242)Tom: $ (222)Bob: $ (269)
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A word problem can be drawn as a diagram and then translated into an equation for easier solving.First, draw a diagram of the problem in order to understand it betterJames: xTom: x-20Bob: x+27Translate the problem into an equation based on the diagramx+(x-20)+(x+27) = $733 Solve for xx+(x-20)+(x+27) = $733 3x+7 = 733 3x+7 -7 = 733 -7 Subtract 7 from both sides 3x = 726 3x÷3 = 726÷3 Divide both sides by 3 x = $242 James’ daily earnings Solve for x-20x-20 = 242-20 Substitute x = $222 Tom’s daily earnings Solve for x+27x+27 = 242+27 Substitute x = $269 Bob’s daily earnings James: $242Tom: $222Bob: $269 -
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Question 7 of 7
7. Question
Zoe has a certain number of 10¢ coins and 4 times that number are her 50¢ coins. The total value of all her coins is $37.80. How many of each coin does she have?-
number of 10¢ coins: (18)number of 50¢ coins: (72)
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A word problem can be drawn as a diagram and then translated into an equation for easier solving.First, draw a diagram of the problem in order to understand it betternumber of 10¢ coins: nTranslate the problem into an equation based on the diagram, then make sure all units are the same10¢(n)+50¢(4n) = $37.80 10¢(n)+50¢(4n) = 3780¢ Solve for n10¢(n)+50¢(4n) = 3780¢ 10n+200n = 3780 210n = 3780 210n÷210 = 3780÷210 Divide both sides by 210 n = 18 number of 10¢ coins Solve for 4n4n = 4(18) Substitute n = 72 number of 50¢ coins number of 10¢ coins: 18number of 50¢ coins: 72 -