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Fraction Word Problems: Multiplication and Division>
Fraction Word Problems: Multiplication and DivisionFraction Word Problems: Multiplication and Division
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Question 1 of 6
1. Question
How many 116 sections of rope are there in a total length of 42m?- (36)
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Transforming a Fraction from Mixed to Improper
= (c×A)+bc First, list down the values stated in the problemTotal length of the rope = 42m Sections it will be cut into = 116=(6×1)+16=6+16=76 Divide the two values42÷76 = 421×67 Reciprocate the divisor and change the operation to multiplication = 7×61×67×1 42 and 7 are both multiples of 7 = 7×61×67×1 Cancel diagonally = 61×61 = 361 = 36 36 -
Question 2 of 6
2. Question
A race track is 323km long per lap. How many laps will a racer need to make in order to complete a 77km race?- (21) laps
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Transforming a Fraction from Mixed to Improper
= (c×A)+bc First, list down the values stated in the problemTotal length of the race = 77km Length of a lap = 323km Divide the two valuesStart by converting the mixed fraction to an improper fraction77÷323 = 771÷(3×3)+23 = 771÷9+23 = 771÷113 Get the reciprocal (flip) of the divisor113 becomes 311 Proceed with multiplying this to the dividend.771÷113 = 771×311 = 77÷111×311÷11 Reduce the fractions = 71×31 = 211 = 21 laps 21 laps -
Question 3 of 6
3. Question
How many 20-minute periods are there in 5 hours?- (15) periods
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To divide fractions, flip the divisor and then multiply as normalMethod OneUse an illustration to represent the problem1 circle represents 1 hour or 60 minutes, so 5 circles are drawn.Since there are three 20 minutes in 60 minutes, each circle is divided into 3 parts.Count the total number of parts5 circles ×3 parts = 15 There are 15 20-minute periods in 5 hours15 periodsMethod TwoFirst, list down the values stated in the problemTotal no. of hours = 5 hours Length of a period
(in hours)= 20 minutes ÷60 minutes=2060=13 Divide the two valuesStart by getting the reciprocal (flip) of the divisor13 becomes 31 Proceed with multiplying this to the dividend.5÷13 = 51×31 = 151 = 15 There are 15 20-minute periods in 5 hours15 periods -
Question 4 of 6
4. Question
Bill swims for exactly the same amount of time each day. If he swims for a total of 712 hours in 5 days, for how long did he swim each day?- 1.
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113
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Transforming a Fraction from Mixed to Improper
= (c×A)+bc Transforming an Improper to Mixed Fraction
bc=QRc(b÷c)=Q and R is the remainderFirst, list down the values stated in the problemTotal no. of
swimming hours= 712 hours No. of days = 5 days Divide the two valuesStart by converting the mixed fraction to an improper fraction712÷5 = (2×7)+12÷51 = 14+12÷51 = 152÷51 Get the reciprocal (flip) of the divisor51 becomes 15 Proceed with multiplying this to the dividend.152÷51 = 152×15 = 15÷52×15÷5 Reduce the fractions = 32×11 = 32 Convert the fraction from improper to mixedStart by dividing the numerator by the denominatorArrange the numbers for long division2 goes into 3 once. So write 1 above the line.Multiply 1 to 2 and write the answer below 3Subtract 2 from 3 and write the answer one line belowSince 2 cannot go into 1 anymore, 1 is left as the Remainder and 1 is the QuotientSubstitute values into the given formulabc = QRc 32 = 112 Bill swam for 112 hours per day.112 hours -
Question 5 of 6
5. Question
How many 113m sections of cable can be cut from a 72m roll?- (54) sections
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Transforming a Fraction from Mixed to Improper
= (c×A)+bc First, list down the values stated in the problemTotal length of the rope = 72m Sections it will be cut into = 113=(3×1)+13=3+13=43 Divide the two values72÷43 = 721×34 Reciprocate the divisor and change the operation to multiplication = 72÷41×34÷4 Reduce the fractions = 181×31 Cancel diagonally = 541 = 54 A 72m roll of cable can have 54 sections of 113m.54 -
Question 6 of 6
6. Question
A $1600 TV has a 15 off discount. Find the following:-
(i) Discount: $ (320)(ii) Sale Price: $ (1280)
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To multiply fractions, simply multiply the numerators and denominators separately.(i) Find the discount price of the TV.First, list down the values stated in the problemOriginal Price = $1600 Discount Rate = 15 Multiply the two values1600×15 = 16001×15 = 16005 = 1600÷5 = $320 The discount price is $320(ii) Find the sale price of the TV.First, list down the known values in the problemOriginal Price = $1600 Discount Price = $320 Subtract the two valuesOriginal price − Discount price = Sale price $1600 − $320 = $1280 The sale price is $1280(i) $320(ii) $1280 -
Quizzes
- Shaded Fractions 1
- Shaded Fractions 2
- Equivalent Fractions 1
- Equivalent Fractions 2
- Equivalent Fractions 3
- Equivalent Fractions 4
- Simplify Fractions 1
- Simplify Fractions 2
- Simplify Fractions 3
- Find the Lowest Common Denominator
- Comparing Fractions 1
- Comparing Fractions 2
- Comparing Fractions 3
- Mixed and Improper Fractions 1
- Mixed and Improper Fractions 2
- Mixed and Improper Fractions 3
- Add and Subtract Fractions 1
- Add and Subtract Fractions 2
- Add and Subtract Fractions 3
- Add and Subtract Fractions 4
- Multiply and Divide Fractions 1
- Multiply and Divide Fractions 2
- Multiply and Divide Fractions 3
- Add and Subtract Mixed Numbers 1
- Add and Subtract Mixed Numbers 2
- Add and Subtract Mixed Numbers 3
- Multiply and Divide Mixed Numbers 1
- Multiply and Divide Mixed Numbers 2
- Multiply and Divide Mixed Numbers 3
- Multiply and Divide Mixed Numbers 4
- Fraction Word Problems: Addition and Subtraction 1
- Fraction Word Problems: Addition and Subtraction 2
- Fraction Word Problems: Addition and Subtraction 3
- Fraction Word Problems: Addition and Subtraction 4
- Fraction Word Problems: Multiplication and Division
- Find the Fraction of a Quantity
- Find the Quantity of a Quantity 1
- Find the Quantity of a Quantity 2
- Find the Fraction of a Quantity: Word Problems 1
- Find the Fraction of a Quantity: Word Problems 2
- Find the Fraction of a Quantity: Word Problems 3
- Find the Fraction of a Quantity: Word Problems 4
- Find the Quantity of a Quantity: Word Problems
- Order of Operations Involving Fractions 1
- Order of Operations Involving Fractions 2