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Question 1 of 4
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Substitute the known values and solve for θθ
ll |
== |
rrθθ |
88 |
== |
88θθ |
Substitute known values |
88÷8÷8 |
== |
8θ8θ÷8÷8 |
Divide both sides by 88 |
11 |
== |
θθ |
θθ |
== |
11 |
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Question 2 of 4
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Substitute the known values and solve for θθ
ll |
== |
rrθθ |
99 |
== |
55θθ |
Substitute known values |
99÷5÷5 |
== |
5θ5θ÷5÷5 |
Divide both sides by 55 |
1.81.8 |
== |
θθ |
θθ |
== |
1.81.8 |
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Question 3 of 4
Find the value of θθ
Use π=3.14π=3.14
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First, substitute the known values and solve for angle of the shaded region
ll |
== |
rrθθ |
4444 |
== |
1010θθ |
Substitute known values |
4444÷10÷10 |
== |
10θ10θ÷10÷10 |
Divide both sides by 1010 |
4.44.4 |
== |
θθ |
θθ |
== |
4.44.4 |
Angle of the shaded region |
Finally, subtract the angle of the shaded region from the total angle of a circle (2π)(2π) to get the value of θθ
2π-2π−4.44.4 |
== |
(2×3.14)-4.4(2×3.14)−4.4 |
|
== |
6.28-4.46.28−4.4 |
|
== |
1.881.88 |
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Question 4 of 4
Given that A=300cm2A=300cm2, find the value of θθ in degrees
Use π=3.1415π=3.1415
Round your answer to one decimal place
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Arc Length Formula
ll==rrθθ
Area of a Circle Formula
A=πr2A=πr2
Converting Radian to Degrees
degrees=radian×180°πdegrees=radian×180°π
First, use the area of a circle formula and solve for rr
AreaArea |
== |
πr2πr2 |
300300 |
== |
πr2πr2 |
Substitute known values |
300300÷π÷π |
== |
πr2πr2÷π÷π |
Divide both sides by ππ |
|
√300π√300π |
== |
√r2√r2 |
Find the square root of both sides |
|
9.7729.772 |
== |
rr |
rr |
== |
9.7729.772 |
Next, substitute the known values and solve for θθ
ll |
== |
2.52.5 |
rr |
== |
9.7729.772 |
ll |
== |
rrθθ |
2.52.5 |
== |
9.7729.772θθ |
Substitute known values |
2.52.5÷9.772÷9.772 |
== |
9.772θ9.772θ÷9.772÷9.772 |
Divide both sides by 9.7729.772 |
0.25580.2558 |
== |
θθ |
θθ |
== |
0.25580.2558 |
Finally, convert the radian to degrees
degreesdegrees |
== |
radians×180°πradians×180°π |
|
|
== |
0.2558×180°π0.2558×180°π |
|
|
== |
46.044°3.141546.044°3.1415 |
Use π=3.1415π=3.1415 |
|
|
== |
14.7° |
Rounded to one decimal place |