Finding Missing Ratios (Proportions) 2

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Question 1 of 4

Jane invested

$ 9000

$$9000$ for a business while Lorraine invested

$ 5000

$$5000$ . If Jane’s profit was

$ 3600

$$3600$ , how much would Lorraine’s profit be?

$$$ $$$ (2000)

Question 2 of 4

2. Question
A shop sold shoes at a ratio of $4$ $4$ to males and $7$ $7$ to females. If the total pairs of shoes sold to females was $28$ $28$ , how many were sold to males?
- (16)
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A ratio compares quantities of the same type given in the same units.

Write the problem in equation form and let $x$ $x$ be the unknown value

$4 : 7$ $4:7$ $=$ $=$ $x : 28$ $x:28$

Convert the ratios into fraction form and solve for $x$ .

$4:7$ $=$ $x:28$

$4/7$ $=$ $x/(28)$ Convert to fraction form

$7(x)$ $=$ $4(28)$ Cross multiply

$7x$ $divide7$ $=$ $112$ $divide7$ Divide both sides by $7$

$x$ $=$ $16$

$16$
Question 3 of 4

3. Question
A sum of money is divided to a ratio of $3:4:5$ . If the largest amount is $$20$ , how much would the smallest amount be?
- $$$ (12)
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A ratio compares quantities of the same type given in the same units.

We are given the largest amount of money, which is $$20$

Divide this value by the number of parts of its ratio, which is $5$

$20divide5$ $=$ $4$

This would be the value of each part.

Multiply this value by the number of parts of the smallest ratio, which is $3$ .

$3xx4$ $=$ $12$

Therefore, the smallest amount in the ratio would be $$12$ .

$$12$
Question 4 of 4

4. Question
The proper mixture of concrete requires $13$ parts cement, $16$ parts sand and $10$ parts water. If the sand needed is $96 \text(kg),$ then how much cement and water is needed?
- $\text(Cement)=$ (78) $\text(kg)$
  
  $\text(Water)=$ (60) $\text(kg)$
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A ratio compares quantities of the same type given in the same units.

The amount of sand needed for the mixture is $96 \text(kg)$ .

Divide this value by the number of parts of its ratio, which is $16$ .

$96divide16$ $=$ $6$

This would be the value of each part.

Multiply this value by the number of parts of both cement and water.

Cement:

$13xx6$ $=$ $78$

Water:

$10xx6$ $=$ $60$

$\text(Cement)=78 \text(kg)$

$\text(Water)=60 \text(kg)$

$9000 : 5000$ $9000:5000$	$=$ $=$	$3600 : x$ $3600:x$

$\frac{9000}{5000}$ $9000/5000$	$=$ $=$	$\frac{3600}{x}$ $(3600)/x$	Convert to fraction form

$\frac{9}{5}$ $9/5$	$=$ $=$	$\frac{3600}{x}$ $(3600)/x$	Simplify

$9 (x)$ $9(x)$	$=$ $=$	$3600 (5)$ $3600(5)$	Cross multiply
$9 x$ $9x$ $\div 9$ $divide9$	$=$ $=$	$18000$ $18000$ $\div 9$ $divide9$	Divide both sides by $9$ $9$
$x$ $x$	$=$ $=$	$2000$ $2000$

Finding Missing Ratios (Proportions) 2

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1. Question

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2. Question

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3. Question

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4. Question

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Quizzes

$4:7$	$=$	$x:28$

$4/7$	$=$	$x/(28)$	Convert to fraction form

$7(x)$	$=$	$4(28)$	Cross multiply
$7x$ $divide7$	$=$	$112$ $divide7$	Divide both sides by $7$
$x$	$=$	$16$