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Find the Fraction of a Quantity: Word Problems>
Find the Fraction of a Quantity: Word Problems 3Find the Fraction of a Quantity: Word Problems 3
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Question 1 of 5
1. Question
Jack brings $40 to the cinema. He spends 14 of that amount on one movie ticket and 35 on snacks. What is the remaining amount of money?- $ (6)
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To multiply fractions, simply multiply the numerators and denominators separately.First, find the fraction for the money spent by adding the two given fractions.Fraction for snacks: 35Fraction for ticket: 1435+14 = (3×4)+(1×5)5×4 = 12+520 = 1720 Proceed to compute for the actual money that Jack spentTo get a fraction of a quantity, simply multiply the fraction to the quantity.Fraction of money spent: 1720Total money: $401720×40 = 1720×401 = 1720÷20×40÷201 Reduce the fractions = 171×21 = 341 = $34 Jack spent $34 in the cinema.Finally, subtract the money spent from the total money to get the remaining amount.$40−$34 = $6 There is $6 left from Jack’s money.$6 -
Question 2 of 5
2. Question
A petrol tank has a capacity of 60L. It is currently 13 full. How many more litres need to be added before the tank becomes full?- (40)L
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To multiply fractions, simply multiply the numerators and denominators separately.First, compute for the exact amount of fuel in the tank at the momentTo get a fraction of a quantity, simply multiply the fraction to the quantity.Fraction of current fuel amount: 13Total tank capacity: 60L13×60 = 13×601 = 13÷3×60÷31 Reduce the fractions = 11×201 = 201 = 20L The tank currently contains 20L of petrol.Finally, subtract the current amount of petrol from the total capacity to get how much petrol needs to be added.60L−20L = 40L 40L of petrol needs to be added for the tank to be full.40L -
Question 3 of 5
3. Question
A 1 metre pole is placed in a pond. 15 of it is in the ground and 23 of it is in the water. What fraction of the pole is above the water?Write fractions in the format “a/b”- (2/15)
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Subtract the given fractions from the full length of the pole.Length of the pole: 1mLength of pole in water: 23Length of pole in the ground: 151−(23+15) = 1−(2×5)+(1×3)3×5 Use cross method to add the fractions = 1−10+315 = 1515−1315 = 215 215 of the pole is above water.215 -
Question 4 of 5
4. Question
From a squad of 15 players, 13 are injured. How many are not injured?- (10) players
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To multiply fractions, simply multiply the numerators and denominators separately.First, get the fraction of players that are not injured.Total squad of players: 33Fraction of injured players: 1333−13 = 23 23 of the players are not injured.To get a fraction of a quantity, simply multiply the fraction to the quantity.Fraction of injured players: 23Total no. of players: 1523×15 = 23×151 = 23÷3×15÷31 Reduce the fractions = 21×51 = 101 = 10 players 10 players in the squad are not injured.10 players -
Question 5 of 5
5. Question
Jason buys eight 500g cans of dog food. Eventually, 115kg worth is eaten. How much dog food remains?- 1.
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145kg -
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425kg -
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512kg
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To multiply fractions, simply multiply the numerators and denominators separately.Transforming a Fraction from Mixed to Improper
= (c×a)+bc Transforming an Improper to Mixed Fraction
bc=QRc(b÷c)=Q and R is the remainderTo get a fraction of a quantity, simply multiply the fraction to the quantity.1 can of dog food: 500g or 12kgNo. of cans: 8kg12×8 = 12×81 = 82 = 8÷2 = 4kg Jason bought 4kg of dog food in totalSubtract the amount of eaten dog food from the total amount of dog food.Total amount: 4kgAmount eaten: 115kg4−115 Convert the fraction from mixed to improper = 4−(5×1)+15 = 4−5+15 = 4−65 = 205−65 Reduce the fractions = 145 Convert the fraction from improper to mixed by dividing the numerator by the denominatorArrange the numbers for long division5 goes into 14 once. So write 2 above the line.Multiply 2 to 5 and write the answer below 14Subtract 10 from 14 and write the answer one line belowSince 5 cannot go into 4 anymore, 4 is left as the Remainder and 2 is the QuotientSubstitute values into the given formulabc = QRc 145 = 245 245kg of dog food remains.245kg
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