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Question 1 of 5
Factorise.
21+43a+20a221+43a+20a2
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When factorising trinomials, use the Cross Method.
Use the cross method to factorise 21+43a+20a221+43a+20a2
Start by drawing a cross.
Now, find two values that will multiply into 2121 and write them on the left side of the cross.
77 and 33 fits this description.
Next, find two numbers that will multiply into 20a220a2 and, when cross-multiplied to the values to the left side, will add up to 43a43a.
|
Product |
Sum when Cross-Multiplied |
2a2a and 10a10a |
20a220a2 |
(3×2a)+(7×10a)=76a(3×2a)+(7×10a)=76a |
5a5a and 4a4a |
20a220a2 |
(3×5a)+(7×4a)=43a(3×5a)+(7×4a)=43a |
20a20a and 1a1a |
20a220a2 |
(3×20a)+(7×1a)=67a(3×20a)+(7×1a)=67a |
5a5a and 4a4a fits this description.
Now, write 5a5a and 4a4a on the right side of the cross.
Finally, group the values in a row with a bracket and combine the brackets.
Therefore, the factorised expression is (7+5a)(3+4a)(7+5a)(3+4a).
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Question 2 of 5
Factorise.
56+19y-10y256+19y−10y2
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When factorising trinomials, use the Cross Method.
Use the cross method to factorise 56+19y-10y2
Start by drawing a cross.
Now, find two values that will multiply into 56 and write them on the left side of the cross.
7 and 8 fits this description.
Next, find two numbers that will multiply into -10y2 and, when cross-multiplied to the values to the left side, will add up to 19y.
|
Product |
Sum when Cross-Multiplied |
-y and 10y |
-10y2 |
(8×-y)+(7×10y)=62y |
-2y and 5y |
-10y2 |
(8×-2y)+(7×5y)=19y |
-2y and 5y fits this description.
Now, write -2y and 5y on the right side of the cross.
Finally, group the values in a row with a bracket and combine the brackets.
Therefore, the factorised expression is (7-2y)(8+5y).
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Question 3 of 5
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When factorising trinomials, use the Cross Method.
Use the cross method to factorise x2+5xy+4y2
Start by drawing a cross.
Now, find two values that will multiply into x2 and write them on the left side of the cross.
x and x fits this description.
Next, find two numbers that will multiply into 4y2 and, when cross-multiplied to the values to the left side, will add up to 5xy.
|
Product |
Sum when Cross-Multiplied |
2y and 2y |
4y2 |
(x×2y)+(x×2y)=4xy |
4y and y |
4y2 |
(x×4y)+(x×y)=5xy |
4y and y fits this description.
Now, write 4y and y on the right side of the cross.
Finally, group the values in a row with a bracket and combine the brackets.
Therefore, the factorised expression is (x+4y)(x+y).
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Question 4 of 5
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When factorising trinomials, use the Cross Method.
Use the cross method to factorise 6x2+xy-2y2
Start by drawing a cross.
Now, find two values that will multiply into 6x2 and write them on the left side of the cross.
Either 6x and x or 2x and 3x fits this description. Try 2x and 3x first.
Next, find two numbers that will multiply into -2y2 and, when cross-multiplied to the values to the left side, will add up to xy.
|
Product |
Sum when Cross-Multiplied |
-2y and y |
-2y2 |
(3x×-2y)+(2x×y)=-4xy |
-y and 2y |
-2y2 |
(3x×-y)+(2x×2y)=xy |
-y and 2y fits this description.
Now, write -y and 2y on the right side of the cross.
Finally, group the values in a row with a bracket and combine the brackets.
Therefore, the factorised expression is (2x-y)(3x+2y).
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Question 5 of 5
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When factorising trinomials, use the Cross Method.
Use the cross method to factorise 28x2+xy-2y2
Start by drawing a cross.
Now, find two values that will multiply into -2y2 and write them on the left side of the cross.
-2y and y fits this description.
Next, find two numbers that will multiply into 28x2 and, when cross-multiplied to the values to the left side, will add up to xy.
|
Product |
Sum when Cross-Multiplied |
2x and 14x |
28x2 |
(2x×y)+(14x×-2y)=-26xy |
7x and 4x |
28x2 |
(7x×y)+(4x×-2y)=xy |
7x and 4x fits this description.
Now, write 7x and 4x on the right side of the cross.
Finally, group the values in a row with a bracket and combine the brackets.
Therefore, the factorised expression is (7x+2y)(4x-y).