Equation Word Problems (Money)
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Question 1 of 3
1. Question
Greg earns `$20` per hour for the first `3` hours and `$15` per hour after that. How many hours should he work to earn `$135`?- (8) hours
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Exceptional!
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Inverse Operations
When moving a term to the other side of an equation, the operation is inversed.Keywords for Word Problems Keyword Meaning Certain number Unknown variable (`x,y,z,` etc) is the same as, The answer is, is equal `=` sum, and, plus, more than `+` subtracted, less, minus `-` times, product, multiplied, twice `times` half of, divide by `divide` First, label the values and form an equation using the information given.Extra hours needed to earn `$135=h``$20` per hour for `3` hours and `$15` per hour for the extra hours should make `$135` `3(20)` `+` `15h` `=` `135` Simplify the equation:`3(20)+15h` `=` `135` `60+15h` `=` `135` To solve for `h`, it needs to be alone on one side.Start by moving `60` to the other side by subtracting `60` from both sides of the equation.`60+15``h` `=` `135` `60+15``h` `-60` `=` `135` `-60` `15``h` `=` `75` `60-60` cancels out Next, remove `15` by dividing both sides of the equation by `15`.`15``h` `=` `75` `15``h``divide15` `=` `75``divide15` `h` `=` `5` `15divide15` cancels out Add `h=5` to the first `3` hours.Total hours needed `=` `3+``h` `=` `3+``5` `=` `5` Greg needs to work `8` hours to earn `$135`.`8` hours -
Question 2 of 3
2. Question
A set of `4` new tires and a `$90`-wheel alignment costs `$898` in total. How much does each tire cost?- `$` (202)
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Fantastic!
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Inverse Operations
When moving a term to the other side of an equation, the operation is inversed.Keywords for Word Problems Keyword Meaning Certain number Unknown variable (`x,y,z,` etc) is the same as, The answer is, is equal `=` sum, and, plus, more than `+` subtracted, less, minus `-` times, product, multiplied, twice `times` half of, divide by `divide` First, label the values and form an equation using the information given.Cost of each tire`=t``4` tires and a `$90`-wheel alignment costs `$898` `4t` `+` `90` `=` `898` To solve for `t`, it needs to be alone on one side.Start by moving `90` to the other side by subtracting `90` from both sides of the equation.`4``t` `+90` `=` `898` `4``t` `+90` `-90` `=` `898` `-90` `4``t` `=` `808` `90-90` cancels out Next, remove `4` by dividing both sides of the equation by `4`.`4``t` `=` `808` `4``t``divide4` `=` `808``divide4` `t` `=` `$202` `4divide4` cancels out Each tire costs `$202`.`$202` -
Question 3 of 3
3. Question
A hire car costs `$95` per day plus `80¢` per kilometre it is driven. If the total cost of hiring the car was `$175`, how many kilometres was it driven?- (100) kilometres
Hint
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Good Job!
Incorrect
Inverse Operations
When moving a term to the other side of an equation, the operation is inversed.Keywords for Word Problems Keyword Meaning Certain number Unknown variable (`x,y,z,` etc) is the same as, The answer is, is equal `=` sum, and, plus, more than `+` subtracted, less, minus `-` times, product, multiplied, twice `times` half of, divide by `divide` First, make sure all units are the same. Convert the cents to dollars knowing that `$1=100¢`.Cost of each kilometre the car is driven `=` `80¢` `=` `80¢divide100¢` `=` `$0.8` Now, label the values and form an equation using the information given.Number of kilometres driven`=x`A hire car costs `$95` per day plus `80¢` per kilometre. The total cost of hiring the car was `$175` `95` `+` `0.8x` `=` `175` To solve for `x`, it needs to be alone on one side.Start by moving `95` to the other side by subtracting `95` from both sides of the equation.`95+0.8``x` `=` `175` `95+0.8``x` `-95` `=` `175` `-95` `0.8``x` `=` `80` `95-95` cancels out Next, remove `0.8` by dividing both sides of the equation by `0.8`.`0.8``x` `=` `80` `0.8``x``divide0.8` `=` `80``divide0.8` `x` `=` `100` `0.8divide0.8` cancels out The hire car was driven for `100` kilometres.`100` kilometres
Quizzes
- One Step Equations – Add and Subtract 1
- One Step Equations – Add and Subtract 2
- One Step Equations – Add and Subtract 3
- One Step Equations – Add and Subtract 4
- One Step Equations – Multiply and Divide 1
- One Step Equations – Multiply and Divide 2
- One Step Equations – Multiply and Divide 3
- One Step Equations – Multiply and Divide 4
- Two Step Equations 1
- Two Step Equations 2
- Two Step Equations 3
- Two Step Equations 4
- Multi-Step Equations 1
- Multi-Step Equations 2
- Solve Equations using the Distributive Property 1
- Solve Equations using the Distributive Property 2
- Solve Equations using the Distributive Property 3
- Equations with Variables on Both Sides 1
- Equations with Variables on Both Sides 2
- Equations with Variables on Both Sides 3
- Equations with Variables on Both Sides (Fractions) 1
- Equations with Variables on Both Sides (Fractions) 2
- Solve Equations with Variables on Both Sides using the Distributive Property 1
- Solve Equations with Variables on Both Sides using the Distributive Property 2
- Solve Equations with Variables on Both Sides using the Distributive Property 3
- Solve Equations with Variables on Both Sides using the Distributive Property 4
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- Equation Word Problems 2
- Equation Word Problems 3
- Equation Word Problems 4
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- Equation Word Problems (Money)
- Equation Word Problems (Harder)
- Equation Problems with Substitution
- Equation Problems (Geometry) 1
- Equation Problems (Geometry) 2
- Equation Problems (Perimeter)
- Equation Problems (Area)
- Change the Subject of an Equation 1
- Change the Subject of an Equation 2
- Change the Subject of an Equation 3