Equation Problems (Geometry) 1
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Question 1 of 5
1. Question
Find x- x= (11)
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Inverse Operations
When moving a term to the other side of an equation, the operation is inversed.Notice that the full angle has a square marker, which means it is a right angle and measures 90°.Form an equation knowing that the two smaller angles are complementary and add up to 90°.Right Angle=90°Small Angle 1=4x°Small Angle 2=46°Small Angle 1 +Small Angle 2 = Right Angle 4x +46 = 90 Substitute the values To solve for x, it needs to be alone on one side.Start by moving 46 to the other side by subtracting 46 from both sides of the equation.4x +46 = 90 4x +46 -46 = 90 -46 4x = 44 46-46 cancels out Finally, remove 4 by dividing both sides of the equation by 4.4x = 44 4x÷4 = 44÷4 x = 11 4÷4 cancels out Check our workTo confirm our answer, substitute x=11 to the formed equation.4x+46 = 90 4(11)+46 = 90 Substitute x=11 44+46 = 90 90 = 90 Since the equation is true, the answer is correct.x=11 -
Question 2 of 5
2. Question
Find x- x= (16)
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Inverse Operations
When moving a term to the other side of an equation, the operation is inversed.A straight angle measures 180°.Form an equation knowing that the two smaller angles are supplementary and add up to 180°.Straight Angle=180°Small Angle 1=148°Small Angle 2=2x°Small Angle 1 +Small Angle 2 = Straight Angle 148 +2x = 180 Substitute the values 2x+148 = 180 To solve for x, it needs to be alone on one side.Start by moving 148 to the other side by subtracting 148 from both sides of the equation.2x +148 = 180 2x +148 -148 = 180 -148 2x = 32 148-148 cancels out Finally, remove 2 by dividing both sides of the equation by 2.2x = 32 2x÷2 = 32÷2 x = 16 2÷2 cancels out Check our workTo confirm our answer, substitute x=16 to the formed equation.2x+148 = 180 2(16)+148 = 180 Substitute x=16 32+148 = 180 180 = 180 Since the equation is true, the answer is correct.x=16 -
Question 3 of 5
3. Question
Find x- x= (28)
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Chapters- Chapters
Inverse Operations
When moving a term to the other side of an equation, the operation is inversed.A straight angle measures 180°.Form an equation knowing that the three angles are supplementary and add up to 180°.Straight Angle=180°Angle 1=50°Angle 2=3x°Angle 3=(2x-10)°Angle 1 +Angle 2 +Angle 3 = Straight Angle 50 +3x +(2x-10) = 180 Substitute the values 5x+40 = 180 Simplify To solve for x, it needs to be alone on one side.Start by moving 40 to the other side by subtracting 40 from both sides of the equation.5x +40 = 180 5x +40 -40 = 180 -40 5x = 140 40-40 cancels out Finally, remove 5 by dividing both sides of the equation by 5.5x = 140 5x÷5 = 140÷5 x = 28 5÷5 cancels out Check our workTo confirm our answer, substitute x=28 to the formed equation.50+3x+(2x-10) = 180 50+3(28)+(2(28)-10) = 180 Substitute x=28 50+84+(56-10) = 180 50+84+46 = 180 180 = 180 Since the equation is true, the answer is correct.x=28 -
Question 4 of 5
4. Question
Find x- x= (80)
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Chapters- Chapters
Inverse Operations
When moving a term to the other side of an equation, the operation is inversed.Vertically Opposite Angles
Alternate Angles
Corresponding Angles
Form an equation knowing that vertically opposite angles are equal.2x-30 = x+50 To solve for x, it needs to be alone on one side.Start by moving x to the other side by subtracting x from both sides of the equation.2x -30 = x +50 2x -30 -x = x +50 -x x -30 = 50 x-x cancels out Finally, move 30 to the other side by adding 30 to both sides of the equation.x -30 = 50 x -30 +30 = 50 +30 x = 80 -30+30 cancels out Check our workTo confirm our answer, substitute x=80 to the formed equation.2x-30 = x+50 2(80)-30 = 80+50 Substitute x=80 160-30 = 130 130 = 130 Since the equation is true, the answer is correct.x=80 -
Question 5 of 5
5. Question
Find x- x= (64)
Hint
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Need TextPlayCurrent Time 0:00/Duration Time 0:00Remaining Time -0:00Stream TypeLIVELoaded: 0%Progress: 0%0:00Fullscreen00:00MutePlayback Rate1x- 2x
- 1.5x
- 1.25x
- 1x
- 0.75x
- 0.5x
Subtitles- subtitles off
Captions- captions off
- English
Chapters- Chapters
Inverse Operations
When moving a term to the other side of an equation, the operation is inversed.A revolution measures 360°.Form an equation knowing that the three angles form a revolution.Revolution=360°Angle 1=x°Angle 2=3x°Angle 3=(x+40)°Angle 1 +Angle 2 +Angle 3 = Revolution x +3x +(x+40) = 360 Substitute the values 5x+40 = 360 Simplify To solve for x, it needs to be alone on one side.Start by moving 40 to the other side by subtracting 40 from both sides of the equation.5x +40 = 360 5x +40 -40 = 360 -40 5x = 320 40-40 cancels out Finally, remove 5 by dividing both sides of the equation by 5.5x = 320 5x÷5 = 320÷5 x = 64 5÷5 cancels out Check our workTo confirm our answer, substitute x=64 to the formed equation.x+3x+(x+40) = 360 64+3(64)+(64+40) = 360 Substitute x=64 64+192+104 = 360 360 = 360 Since the equation is true, the answer is correct.x=64
Quizzes
- One Step Equations – Add and Subtract 1
- One Step Equations – Add and Subtract 2
- One Step Equations – Add and Subtract 3
- One Step Equations – Add and Subtract 4
- One Step Equations – Multiply and Divide 1
- One Step Equations – Multiply and Divide 2
- One Step Equations – Multiply and Divide 3
- One Step Equations – Multiply and Divide 4
- Two Step Equations 1
- Two Step Equations 2
- Two Step Equations 3
- Two Step Equations 4
- Multi-Step Equations 1
- Multi-Step Equations 2
- Solve Equations using the Distributive Property 1
- Solve Equations using the Distributive Property 2
- Solve Equations using the Distributive Property 3
- Equations with Variables on Both Sides 1
- Equations with Variables on Both Sides 2
- Equations with Variables on Both Sides 3
- Equations with Variables on Both Sides (Fractions) 1
- Equations with Variables on Both Sides (Fractions) 2
- Solve Equations with Variables on Both Sides using the Distributive Property 1
- Solve Equations with Variables on Both Sides using the Distributive Property 2
- Solve Equations with Variables on Both Sides using the Distributive Property 3
- Solve Equations with Variables on Both Sides using the Distributive Property 4
- Equation Word Problems 1
- Equation Word Problems 2
- Equation Word Problems 3
- Equation Word Problems 4
- Equation Word Problems (Age)
- Equation Word Problems (Money)
- Equation Word Problems (Harder)
- Equation Problems with Substitution
- Equation Problems (Geometry) 1
- Equation Problems (Geometry) 2
- Equation Problems (Perimeter)
- Equation Problems (Area)
- Change the Subject of an Equation 1
- Change the Subject of an Equation 2
- Change the Subject of an Equation 3