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Question 1 of 4
44 less than xx is equal to 2222. Find xx.
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Word problems can be written as equations for easier solving.
First, write the word problem as an equation
44 less than xx |
is equal to |
2222 |
x-4x−4 |
== |
2222 |
x-4x−4 |
== |
2222 |
x-4x−4 +4+4 |
== |
2222 +4+4 |
Add 44 to both sides |
xx |
== |
2626 |
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Question 2 of 4
The product of 33 and 7y7y is 126126. Find yy.
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Word problems can be written as equations for easier solving.
First, write the word problem as an equation
The product of 33 and 7y7y |
is |
126126 |
3(7y)3(7y) |
== |
126126 |
3(7y)3(7y) |
== |
126126 |
21y21y |
== |
126126 |
21y21y÷21÷21 |
== |
126126÷21÷21 |
Divide both sides by 2121 |
yy |
== |
66 |
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Question 3 of 4
1212 less than 5a5a is equal to 8383. Find aa
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Word problems can be written as equations for easier solving.
First, write the word problem as an equation
1212 less than 5a5a |
is equal to |
8383 |
5a-125a−12 |
== |
8383 |
5a-125a−12 |
== |
8383 |
5a-125a−12 +12+12 |
== |
8383 +12+12 |
Add 1212 to both sides |
5a5a |
== |
9595 |
5a5a÷5÷5 |
== |
9595÷5÷5 |
Divide both sides by 55 |
aa |
== |
1919 |
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Question 4 of 4
What are three consecutive numbers whose sum is 7272?
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Consecutive numbers are numbers that go up by 11.
First, write the word problem as an equation
11st number: xx
22nd number: x+1x+1
33rd number: x+2x+2
The sum of three consecutive numbers |
is equal to |
7272 |
xx +(+(x+1x+1)+()+(x+2x+2)) |
== |
7272 |
xx +(+(x+1x+1)+()+(x+2x+2)) |
== |
7272 |
3x+33x+3 |
== |
7272 |
3x+33x+3 -3−3 |
== |
7272 -3−3 |
Subtract 33 from both sides |
3x3x |
== |
6969 |
3x3x÷3÷3 |
== |
6969÷3÷3 |
Divide both sides by 33 |
xx |
== |
2323 |
11st number |
|
|
x+1x+1 |
|
== |
23+123+1 |
Substitute xx |
|
== |
2424 |
22nd number |
|
|
x+2x+2 |
|
== |
23+223+2 |
Substitute xx |
|
== |
1414 |
33rd number |
Check our work
Slot in the numbers
xx+(+(x+1x+1)+()+(x+2x+2)) |
== |
7272 |
2323++2424++2525 |
== |
7272 |
7272 |
== |
7272 |
Since this is true, the three numbers are correct