Deductive Geometry (Reasoning) 2
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Question 1 of 3
1. Question
Find the value of `a`- `a=` (35)
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An Isosceles Triangle has two congruent sides (the two sides with dashes) and the two base angles are equal.The sum of the interior angles in a triangle is 180°Supplementary angles are when two angles have a sum of `180°.` Typically, these angles lie on a straight line.To find the value of `a`, first find its supplementary angles and set their sum to `180°`First, note that the two missing interior angles are base angles in an isosceles triangle. Hence, they are equal.Let their value be `x`Next, since the interior angles of a triangle add to `180°,` add the angle measures and set their sum to `180°.` Then, solve for `x`.`x+x+40` `=` `180` `2x+40` `=` `180` Simplify `2x+40` `-40` `=` `180` `-40` Subtract `40` from both sides `2x` `=` `140` `2x` `divide2` `=` `140` `divide2` Divide both sides by `2` `x` `=` `70°` Now, let the alternate angle of `40°` be `y`. Since they are alternate angles, they are equal.Therefore, `/_ y=40°`Finally, we can see from the diagram that the exterior angles `2a`, `y=40°` and the interior angle `x=70°` lie on a straight line. Therefore, they are supplementary anglesSince supplementary angles add to `180°,` add the angle measures and set their sum to `180°.` Then, solve for the value of `a`.`2a+x+y` `=` `180` `2a+70+40` `=` `180` Plug in the known values `2a+110` `=` `180` Simplify `2a+110` `-110` `=` `180` `-110` Subtract `110` from both sides `2a` `=` `70` `2a` `divide2` `=` `70` `divide2` Divide both sides by `2` `a` `=` `35°` `/_ a=35°` -
Question 2 of 3
2. Question
If the triangle is equally divided in half by `MQ`, find the value of `/_MPQ`- `/_MPQ=` (39)`°`
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An exterior angle of a triangle is equal to the sum of two interior angles opposite of it.To solve for `/_MPQ`, add it to the value of `/_PQR`, then set their sum to be the exterior angle `145°`First, we can see in the diagram that the interior angles `92°` and `/_MQR` are opposite to the exterior angle `145°`Since the exterior angles of a triangle is equal to the sum of the two opposite interior angles, add the interior angle measures and set their sum to `145°.` Then, solve for `/_MQR`.`/_MQR+92` `=` `145` `/_MQR+92` `-92` `=` `145` `-92` Subtract `92` from both sides `/_MQR` `=` `53°` Next, we can see from the diagram that line `MQ` divides the triangle equallyTherefore, `/_MQR` and `/_MQP` will also be equal, which is `53°`Finally, we can see in the diagram that the interior angles `/_MPQ` and `/_PQR` are opposite to the exterior angle `145°`Since the exterior angles of a triangle is equal to the sum of the two opposite interior angles, add the interior angle measures and set their sum to `145°.` Then, solve for `/_MPQ`.`/_PQR=/_MQR+/_MQP``/_MPQ+/_PQR` `=` `145` `/_MPQ+(53+53)` `=` `145` Plug in the known values `/_MPQ+106` `=` `145` Simplify `/_MPQ+106` `-106` `=` `145` `-106` Subtract `106` from both sides `/_MPQ` `=` `39°` `/_ MPQ=39°` -
Question 3 of 3
3. Question
Find the value of `/_BDC`- `/_BDC=` (133)`°`
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The sum of the interior angles in a triangle is 180°Derive the equation for the interior angles of the larger triangle and use that equation to solve for `/_BDC`First, consider that the interior angles of the larger triangle add to `180°`.Add the angle measures of this larger triangle and set their sum to `180°.` Then, simplify the equation.`/_ABC+/_ACB+86` `=` `180` `(m+m)+(n+n)+86` `=` `180` Plug in the known values `2m+2n+86` `=` `180` Simplify `2m+2n+86` `-86` `=` `180` `-86` Subtract `86` from both sides `2m+2n` `=` `94` `(2m+2n)``divide2` `=` `94` `divide2` Divide both sides by `2` `m+n` `=` `47°` Now, consider that the interior angles of the smaller triangle add to `180°`.Add the angle measures of the smaller triangle and set their sum to `180°.` Then, solve for `/_BDC`.Note that `m+n=47°``m+n` `+/_BDC` `=` `180` `47` `+/_BDC` `=` `180` Plug in the known values `47+/_BDC` `-47` `=` `180` `-47` Subtract `47` from both sides `/_BDC` `=` `133°` `/_ BDC=133°`
Quizzes
- Complementary and Supplementary Angles 1
- Complementary and Supplementary Angles 2
- Complementary and Supplementary Angles 3
- Vertical, Revolution and Reflex Angles 1
- Vertical, Revolution and Reflex Angles 2
- Alternate, Corresponding and Co-Interior Angles 1
- Alternate, Corresponding and Co-Interior Angles 2
- Alternate, Corresponding and Co-Interior Angles 3
- Angles and Parallel Lines
- Triangle Geometry 1
- Triangle Geometry 2
- Triangle Geometry 3
- Quadrilateral Geometry 1
- Quadrilateral Geometry 2
- Congruent Triangles 1
- Congruent Triangles 2
- Deductive Geometry (Reasoning) 1
- Deductive Geometry (Reasoning) 2