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Decimal Word Problems: Multiplication>
Decimal Word Problems: Multiplication 3Decimal Word Problems: Multiplication 3
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Question 1 of 3
1. Question
Electricity costs `20.52¢` per unit. How much would `500` units cost in dollars?- `$` (102.60, 102.6)
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First, list down the given values in the problem.Cost per unit: `20.52¢`Total units: `500`To find the total cost of electricity, multiply the cost per unit by the total units, then convert the product from cents to dollars.First, start by ignoring the decimal points and multiply them normally`20.52` `=` `2052` `2052xx500` `=` `1026000` Next, count how many place values there are from the decimal point to the right of the two factors.`20.52 = ``2 \text(places)`
There is a total of `2` place value movements to the right of the decimal point.Get the final product by moving the decimal point of the initial product `2` places to the left.
Finally, to convert cents into dollars, move the decimal point `2` places to the left
Therefore, the total cost of electricity for `500` units is `$102.60`.`$102.60` -
Question 2 of 3
2. Question
Each can of paint costs `$35.25`. If `6` cans are needed to paint the whole area, what will the total cost be?- `$` (211.50)
Hint
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First, list down the given values in the problem.Price per can of paint: `$35.25`Cans of paint needed: `6`To find the total cost for the cans of paint, multiply the price per can of paint by the amount of cans of paint needed.Start by ignoring the decimal points and multiply them normally`35.25` `=` `3525` `3525xx6` `=` `21150` Next, count how many place values there are from the decimal point to the right of the two factors.`35.25 = ``2 \text(places)`
There are a total of `2` place value movements to the right of the decimal point.Get the final product by moving the decimal point of the initial product `2` places to the left.
Therefore, `6` cans of paint will cost `$211.50``$211.50` -
Question 3 of 3
3. Question
On a map, the distance between two locations is `5.3 \text(cm)`. If the scale of the map is `1 \text(cm):100 \text(km)`, what is the actual distance between the two locations?- (530) `\text(km)`
Hint
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First, list down the given values in the problem.Distance between the locations: `5.3 \text(cm)`Scale on map: `1 \text(cm):100 \text(km)`To find actual distance of the location, multiply the distance between the locations by the actual size on the scale, which is `100`.Since the decimal is being multiplied by `100`, simply move the decimal point `2` places to the right.
Therefore, the actual distance between the two locations is `530 \text(km)`.`530 \text(km)`
Quizzes
- Decimal Place Values 1
- Decimal Place Values 2
- Expressing Decimals as a Fraction 1
- Expressing Decimals as a Fraction 2
- Expressing Decimals as a Fraction 3
- Converting Decimals Involving Money (Cents and Dollars) 1
- Converting Decimals Involving Money (Cents and Dollars) 2
- Converting Decimals Involving Money (Cents and Dollars) 3
- Add and Subtract Decimals 1
- Add and Subtract Decimals 2
- Add and Subtract Decimals 3
- Add and Subtract Decimals 4
- Multiply Decimals 1
- Multiply Decimals 2
- Multiply Decimals 3
- Divide Decimals 1
- Divide Decimals 2
- Divide Decimals 3
- Divide Decimals 4
- Converting Fractions to Decimals 1
- Converting Fractions to Decimals 2
- Converting Fractions to Decimals 3
- Rounding Whole Numbers
- Rounding Decimals 1
- Rounding Decimals 2
- Rounding Decimals 3
- Decimal Word Problems: Addition and Subtraction 1
- Decimal Word Problems: Addition and Subtraction 2
- Decimal Word Problems: Addition and Subtraction 3
- Decimal Word Problems: Multiplication 1
- Decimal Word Problems: Multiplication 2
- Decimal Word Problems: Multiplication 3
- Decimal Word Problems: Division 1
- Decimal Word Problems: Division 2