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Decimal Word Problems: Multiplication>
Decimal Word Problems: Multiplication 2Decimal Word Problems: Multiplication 2
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Question 1 of 4
1. Question
At work Max earns `$17.30` per hour. How much money will he earn if he works for `8` hours?- `$` (138.40)
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First, list down the given values in the problem.Earnings per hour: `$17.30`Hours of work: `8`To find the amount of money Max will earn, multiply the earnings per hour by the hours of work.Start by ignoring the decimal points and multiply them normally`17.30` `=` `1730` `1730xx8` `=` `13840` Next, count how many place values there are from the decimal point to the right of the two factors.`17.30 = ``2 \text(places)`
There are a total of `2` place value movements to the right of the decimal point.Get the final product by moving the decimal point of the initial product `2` places to the left.
Therefore, Max will earn `$138.40` for `8` hours of work.`$138.40` -
Question 2 of 4
2. Question
Each pen costs `$3.55` and each stapler costs `$11.95`. If there are `6` pens and `3` staplers, how much does it all cost?- `$` (57.15)
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First, list down the given values in the problem.Cost of pen: `$3.55`Cost of stapler: `$11.95`Amount of pens: `6`Amount of staplers: `3`To find the total cost of the items, multiply the cost of the items by their amount, then get the sum of their products.First, get the total cost of the pens. Since there are `6` pens, multiply the cost of one to `6`Start by ignoring the decimal points and multiply them normally`3.55` `=` `355` `355xx6` `=` `2130` Then, count how many place values there are from the decimal point to the right of the two factors.`3.55 = ``2 \text(places)`
There are a total of `2` place value movements to the right of the decimal point.Get the final product by moving the decimal point of the initial product `2` places to the left.
The total cost of the pens is `$21.30`Next, get the total cost of the staplers. Since there are `3` staplers, multiply the cost of one to `3`Start by ignoring the decimal points and multiply them normally`11.95` `=` `1195` `1195xx3` `=` `3585` Then, count how many place values there are from the decimal point to the right of the two factors.`11.95 = ``2 \text(places)`
There are a total of `2` place value movements to the right of the decimal point.Get the final product by moving the decimal point of the initial product `2` places to the left.
The total cost of the staplers is `$35.85`Finally, add the two products to get the total cost. Line up the decimal points (point over point).If there are any blank values to the right of the decimal point, write `0`.Carry Overs `1` `+` `2` `1` `.` `3` `0` `+` `3` `5` `.` `8` `5` `5` `7` `.` `1` `5` Therefore, the total cost of the items is `$57.15``$57.15` -
Question 3 of 4
3. Question
Liam purchased `50 \text(litres)` of fuel for `159.8¢` per litre. How much did he spend in dollars?- `$` (79.90)
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First, list down the given values in the problem.Cost per litre of fuel: `159.8¢`Total litres bought: `50`To find the total cost of the fuel, multiply the cost per litre of fuel by the total litres bought, then convert the product from cents to dollars.First, start by ignoring the decimal points and multiply them normally`159.8` `=` `1598` `1598xx50` `=` `79900` Next, count how many place values there are from the decimal point to the right of the two factors.`159.8 = ``1 \text(place)`
There is a total of `1` place value movement to the right of the decimal point.Get the final product by moving the decimal point of the initial product `1` place to the left.
Finally, to convert cents into dollars, move the decimal point `2` places to the left
Therefore, Liam spent a total of `$79.90` on fuel.`$79.90` -
Question 4 of 4
4. Question
A timber crate weighing `2.5` kilograms can hold `10` bottles of wine. If each bottle of wine weighs `1.2` kilograms, what would the total weight of the crate and the wine bottles be?- (14.5) `\text(kg)`
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When multiplying decimals to values like `10, 100, 1000…`, simply move the decimal point to the right by the number of zeroes.First, list down the given values in the problem.Wine case: `2.5 \text(kg)`Wine bottle: `1.2 \text(kg)`Number of bottles: `10`To find the total weight of the objects, multiply the weight of the wine bottle by the number of wine bottles, then add the weight of the wine case.Start by multiplying the weight of the wine bottle by the number of wine bottles.Since the decimal is being multiplied by `10`, simply move the decimal point `1` place to the right.
Therefore, the total weight of the wine bottles is `12 \text(kg)`Finally, add the product to the weight of the wine case. Line up the decimal points (point over point).If there are any blank values to the right of the decimal point, write `0`.`2` `.` `5` `+` `1` `2` `.` `0` `1` `4` `.` `5` Therefore, the total weight of the objects is `14.5 \text(kg)``14.5 \text(kg)`
Quizzes
- Decimal Place Values 1
- Decimal Place Values 2
- Expressing Decimals as a Fraction 1
- Expressing Decimals as a Fraction 2
- Expressing Decimals as a Fraction 3
- Converting Decimals Involving Money (Cents and Dollars) 1
- Converting Decimals Involving Money (Cents and Dollars) 2
- Converting Decimals Involving Money (Cents and Dollars) 3
- Add and Subtract Decimals 1
- Add and Subtract Decimals 2
- Add and Subtract Decimals 3
- Add and Subtract Decimals 4
- Multiply Decimals 1
- Multiply Decimals 2
- Multiply Decimals 3
- Divide Decimals 1
- Divide Decimals 2
- Divide Decimals 3
- Divide Decimals 4
- Converting Fractions to Decimals 1
- Converting Fractions to Decimals 2
- Converting Fractions to Decimals 3
- Rounding Whole Numbers
- Rounding Decimals 1
- Rounding Decimals 2
- Rounding Decimals 3
- Decimal Word Problems: Addition and Subtraction 1
- Decimal Word Problems: Addition and Subtraction 2
- Decimal Word Problems: Addition and Subtraction 3
- Decimal Word Problems: Multiplication 1
- Decimal Word Problems: Multiplication 2
- Decimal Word Problems: Multiplication 3
- Decimal Word Problems: Division 1
- Decimal Word Problems: Division 2