Decimal Word Problems: Division 1

Years

Year 10

Decimals

Decimal Word Problems: Division

Decimal Word Problems: Division 1

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Question 1 of 5

1. Question
Susie wants to paint an area of $270 m^{2}$ $270 \text(m)^2$ . If one can of paint covers $50 m^{2}$ $50 \text(m)^2$ , how many cans of paint will she need?
- (6) $cans of paint$ $\text(cans of paint)$
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First, list down the given values in the problem.

$1$ $1$ can of paint: $50 m^{2}$ $50 \text(m)^2$

$?$ $?$ cans of paint: $270 m^{2}$ $270 \text(m)^2$

To find $?$ $?$ , simply divide $270$ $270$ by $50$ $50$

Proceed with dividing the two numbers

Arrange the values for long division

Divide both divisor and dividend by $10$ $10$ for simpler computation

This means both zeroes at the end would be cancelled

$5$ $5$ does not go into $2$ $2$ but instead goes into $27$ $27$ five times. So write $5$ $5$ above the line.

Multiply $5$ $5$ to $5$ $5$ and write the answer below $27$ $27$

Subtract $25$ $25$ from $27$ $27$ and write the answer one line below

Since $5$ $5$ does not go into $2$ $2$ , add a zero after $27$ $27$ and bring it down beside $2$ $2$ . Also, place a decimal point after $5$ $5$ .

$5$ $5$ goes into $20$ $20$ four times. So write $4$ $4$ above the line.

Multiply $4$ $4$ to $5$ $5$ and write the answer below $20$ $20$

Since $4 \times 5 = 20$ $4xx5=20$ , there are no more remainders.

Therefore, if $270 \div 50 = 5.4$ $270-:50=5.4$ , Susie will need $6$ $6$ cans of paint.

$6 cans of paint$ $6 \text(cans of paint)$
Question 2 of 5

2. Question
There is a $1.1 litre$ $1.1 \text(litre)$ bottle of orange juice. How many glasses can it fill if each glass has a capacity of $0.2 litre$ $0.2 \text(litre)$ ?
- (5.5) $glasses$ $\text(glasses)$
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First, list down the given values in the problem.

Amount of orange juice: $1.1 litres$ $1.1 \text(litres)$

Capacity of each glass: $0.2 litre$ $0.2 \text(litre)$

To find how many glasses can be filled, divide the amount of orange juice by the capacity of each glass.

First, turn the divisor into a whole number by multiplying both values by $10$ $10$

Since the decimal is being multiplied by $10$ $10$ , simply move the decimal point $1$ $1$ place to the right.

$1.1$ $1.1$

$0.2$ $0.2$

$1.1 \times 10$ $1.1xx10$ $=$ $=$ $11$ $11$

$0.2 \times 10$ $0.2xx10$ $=$ $=$ $2$ $2$

Proceed with dividing the two numbers

Arrange the values for long division

$2$ $2$ does not go into $1$ $1$ but instead goes into $11$ $11$ five times. So write $5$ $5$ above the line.

Multiply $5$ $5$ to $2$ $2$ and write the answer below $11$ $11$

Subtract $10$ $10$ from $11$ $11$ and write the answer one line below

Since $2$ $2$ does not go into $1$ $1$ , add a zero after $1$ $1$ place a decimal point after $5$ $5$ .

$5$ $5$ goes into $10$ $10$ five times. So write $5$ $5$ above the line.

Multiply $5$ $5$ to $2$ $2$ and write the answer below $10$ $10$

Since $5 \times 2 = 10$ $5xx2=10$ , there are no more remainders.

Therefore, a bottle with $1.1 litres$ $1.1 \text(litres)$ of orange juice can fill up $5.5$ $5.5$ glasses.

$5.5 glasses$ $5.5 \text(glasses)$
Question 3 of 5

3. Question
What is $8 cm$ $8 \text(cm)$ of $4 m$ $4 \text(m)$ ?
- (0.02) $cm$ $\text(cm)$
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First, convert the metres into centimetres.

$1 m = 100 cm$ $1 \text(m)=100 \text(cm)$

$4 m \times \frac{100 cm}{1 m}$ $4 \text(m)xx(100 \text(cm))/(1 \text(m))$ $=$ $=$ $400 cm$ $400 \text(cm)$

Proceed with dividing the $8 cm$ $8 \text(cm)$ by $400 cm$ $400 \text(cm)$

Arrange the values for long division

$8$ $8$ cannot be divided by $400$ $400$ . In this case, add a $0$ $0$ next to $8$ $8$ and add a decimal point above the line

$80$ $80$ still cannot be divided by $400$ $400$ . In this case, add another $0$ $0$ next to $80$ $80$ and also add a $0$ $0$ above the line, after the decimal point

$400$ $400$ goes into $800$ $800$ two times. So write $2$ $2$ above the line.

Multiply $2$ $2$ to $4000$ $4000$ and write the answer below $800$ $800$

Since $2 \times 400 = 800$ $2xx400=800$ , there are no remainders in this division.

Therefore, $8 cm$ $8 \text(cm)$ of $4 m$ $4 \text(m)$ is $0.02 cm$ $0.02 \text(cm)$ .

$0.02 cm$ $0.02 \text(cm)$
Question 4 of 5

4. Question
A case of bottles weighs $6 kg$ $6 \text(kg)$ . If each bottle weighs $0.5 kg$ $0.5 \text(kg)$ , how many bottles are in the case?
- (12) $bottles$ $\text(bottles)$
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First, list down the given values in the problem.

Weight of case: $6 kg$ $6 \text(kg)$

Weight per bottle: $0.5 kg$ $0.5 \text(kg)$

To find how many bottle are in the case, divide the weight of the case by the weight per bottle.

First, turn the divisor into a whole number by multiplying both values by $10$ $10$

Since the decimal is being multiplied by $10$ $10$ , simply move the decimal point $1$ $1$ place to the right.

$0.5$ $0.5$

$6 \times 10$ $6xx10$ $=$ $=$ $60$ $60$

$0.5 \times 10$ $0.5xx10$ $=$ $=$ $5$ $5$

Proceed with dividing the two numbers

Arrange the values for long division

$5$ $5$ goes into $60$ $60$ twelve times. So write $12$ $12$ above the line.

Multiply $12$ $12$ to $5$ $5$ and write the answer below $60$ $60$

Since $12 \times 5 = 60$ $12xx5=60$ , there are no more remainders.

Therefore, there are $12$ $12$ bottles in the case.

$12 bottles$ $12 \text(bottles)$
Question 5 of 5

5. Question
A car travels $97.2 km$ $97.2 \text(km)$ with $9 litres$ $9 \text(litres)$ of fuel. How far can it travel with $1 litre$ $1 \text(litre)$ of fuel?
- (10.8) $km$ $\text(km)$
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First, list down the given values in the problem.

Distance traveled: $97.2 km$ $97.2 \text(km)$

Fuel used: $9 litres$ $9 \text(litres)$

To find how many glasses can be filled, divide the distance traveled by the amount of fuel used.

Ignore the decimal point and proceed with dividing the two numbers

Arrange the values for long division

$9$ $9$ goes into $97$ $97$ ten times. So write $10$ $10$ above the line.

Multiply $10$ $10$ to $9$ $9$ and write the answer below $97$ $97$

Subtract $90$ $90$ from $97$ $97$ and write the answer one line below and bring down the remaining digit $2$ $2$

$9$ $9$ goes into $72$ $72$ eight times. So write $8$ $8$ above the line.

Multiply $8$ $8$ to $9$ $9$ and write the answer below $20$ $20$

Since $8 \times 9 = 72$ $8xx9=72$ , there are no more remainders.

Finally, count how many place values from the decimal point to the right of the two values.

$97.2 =$ $97.2 =$ $1 place$ $1 \text(place)$

Get the final quotient by moving the decimal point of the initial quotient $1$ $1$ place to the left.

Therefore, the car can travel $10.8 km$ $10.8 \text(km)$ with $1 litre$ $1 \text(litre)$ of fuel.

$10.8 km$ $10.8 \text(km)$

Decimal Word Problems: Division 1

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Quiz summary

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1. Question

Hint

Great Work!

2. Question

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Correct!

3. Question

Hint

Keep Going!

4. Question

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Fantastic!

5. Question

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Excellent!

Quizzes

$1.1 \times 10$ $1.1xx10$	$=$ $=$	$11$ $11$
$0.2 \times 10$ $0.2xx10$	$=$ $=$	$2$ $2$

$6 \times 10$ $6xx10$	$=$ $=$	$60$ $60$
$0.5 \times 10$ $0.5xx10$	$=$ $=$	$5$ $5$