Compass Bearings and True Bearings 2

Years

Year 11

Bearings

Compass Bearings and True Bearings

Compass Bearings and True Bearings 2

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Question 1 of 4

1. Question
Find the compass bearing and true bearing of $A$ $A$ from $O$ $O$
- $(i)$ $(i)$ Compass Bearing $=$ $=$ (S) (66) $°$ $°$ (E)
  
  $(i i)$ $(ii)$ True Bearing $=$ $=$ (114) $° T$ $°T$
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To get a compass bearing, take the compass quadrant where the direction belongs to, then get the angle from the vertical line around to the required direction.

Compass Bearing Quadrants

Northwest Quadrant $= N$ $=N$ __ $W$ $W$

Northeast Quadrant $= N$ $=N$ __ $E$ $E$

Southwest Quadrant $= S$ $=S$ __ $W$ $W$

Southeast Quadrant $= S$ $=S$ __ $E$ $E$

The blank is filled with the distance of the bearing from the North-South (vertical) line

A true bearing is an angle measured clockwise from the True North around to the required direction.

$(i)$ $(i)$ $Compass Bearing$ $\text(Compass Bearing)$

Notice that line $A$ $A$ is located on the Southeast Quadrant.

Using the chart, we can write the compass bearing of $A$ $A$ from $O$ $O$ by using $S$ $S$ __ $E$ $E$ . Then get the angle that spans from the vertical line ( $N$ $N$ ) to $A$ $A$ .

Notice that line $E$ $E$ and line $S$ $S$ form a complementary angle. Therefore, we can find the value of the angle by subtracting $24 °$ $24°$ from the value of a complementary angle, which is $90 °$ $90°$ .

$90 ° - 24 °$ $90°-24°$ $=$ $=$ $66 °$ $66°$

Therefore, the compass bearing of $A$ $A$ from $O$ $O$ is $S 66 ° E$ $S 66° E$

$(i i)$ $(ii)$ $True Bearing$ $\text(True Bearing)$

Notice that when starting from North and heading to East, it forms a complementary angle.

Since a complementary angle is equal to $90 °$ $90°$ , we can simply add the measure of $∠ E O A$ $angle E O A$ , which is $24 °$ $24°$ , to $90 °$ $90°$ to get the bearing of $A$ $A$ from $O$ $O$ .

Don’t forget to add $T$ $T$ to the bearing to indicate that it’s True North.

$90 ° + 24 °$ $90°+24°$ $=$ $=$ $114 ° T$ $114°T$

$(i)$ $(i)$ Compass Bearing $= S 66 ° E$ $= S 66° E$

$(i i)$ $(ii)$ True Bearing $= 114 ° T$ $=114°T$
Question 2 of 4

2. Question
Find the compass bearing and true bearing of $A$ $A$ from $O$ $O$
- $(i)$ $(i)$ Compass Bearing $=$ $=$ (S) (49) $°$ $°$ (W)
  
  $(i i)$ $(ii)$ True Bearing $=$ $=$ (229) $° T$ $°T$
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To get a compass bearing, take the compass quadrant where the direction belongs to, then get the angle from the vertical line around to the required direction.

Compass Bearing Quadrants

Northwest Quadrant $= N$ $=N$ __ $W$ $W$

Northeast Quadrant $= N$ $=N$ __ $E$ $E$

Southwest Quadrant $= S$ $=S$ __ $W$ $W$

Southeast Quadrant $= S$ $=S$ __ $E$ $E$

The blank is filled with the distance of the bearing from the North-South (vertical) line

A true bearing is an angle measured clockwise from the True North around to the required direction.

$(i)$ $(i)$ $Compass Bearing$ $\text(Compass Bearing)$

Notice that line $A$ $A$ is located on the Southwest Quadrant.

Using the chart, we can write the compass bearing of $A$ $A$ from $O$ $O$ by using $S$ $S$ __ $W$ $W$ . Then get the angle that spans from the vertical line ( $N$ $N$ ) to $A$ $A$ , which is $49 °$ $49°$

Therefore, the compass bearing of $A$ $A$ from $O$ $O$ is $S 49 ° W$ $S 49° W$

$(i i)$ $(ii)$ $True Bearing$ $\text(True Bearing)$

Notice that when starting from North and heading to South, it forms a supplementary angle.

Since a supplementary angle is equal to $180 °$ $180°$ , we can simply add the measure of $∠ S O A$ $angle S O A$ , which is $49 °$ $49°$ , to $180 °$ $180°$ to get the bearing of $A$ $A$ from $O$ $O$ .

Don’t forget to add $T$ $T$ to the bearing to indicate True North.

$180 ° + 49 °$ $180°+49°$ $=$ $=$ $229 ° T$ $229°T$

$(i)$ $(i)$ Compass Bearing $= S 49 ° W$ $= S 49° W$

$(i i)$ $(ii)$ True Bearing $= 229 ° T$ $=229°T$
Question 3 of 4

3. Question
Find the compass bearing and true bearing of $A$ $A$ from $O$ $O$
- $(i)$ $(i)$ Compass Bearing $=$ $=$ (S) (40) $°$ $°$ (W)
  
  $(i i)$ $(ii)$ True Bearing $=$ $=$ (220) $° T$ $°T$
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To get a compass bearing, take the compass quadrant where the direction belongs to, then get the angle from the vertical line around to the required direction.

Compass Bearing Quadrants

Northwest Quadrant $= N$ $=N$ __ $W$ $W$

Northeast Quadrant $= N$ $=N$ __ $E$ $E$

Southwest Quadrant $= S$ $=S$ __ $W$ $W$

Southeast Quadrant $= S$ $=S$ __ $E$ $E$

The blank is filled with the distance of the bearing from the North-South (vertical) line

A true bearing is an angle measured clockwise from the True North around to the required direction.

$(i)$ $(i)$ $Compass Bearing$ $\text(Compass Bearing)$

Notice that line $A$ $A$ is located on the Southwest Quadrant.

Using the chart, we can write the compass bearing of $A$ $A$ from $O$ $O$ by using $S$ $S$ __ $W$ $W$ . Then get the angle that spans from the vertical line ( $N$ $N$ ) to $A$ $A$ .

Notice that line $N$ $N$ and line $S$ $S$ form a supplementary angle. Therefore, we can find the value of the angle by subtracting the value of a complementary angle, which is $90 °$ $90°$ , from $220 °$ $220°$ .

$220 ° - 180 °$ $220°-180°$ $=$ $=$ $40 °$ $40°$

Therefore, the compass bearing of $A$ $A$ from $O$ $O$ is $S 40 ° W$ $S 40° W$

$(i i)$ $(ii)$ $True Bearing$ $\text(True Bearing)$

Starting clockwise from North, line $A$ $A$ gives us $168 °$ $168°$ .

Therefore, the true bearing of $A$ $A$ from $O$ $O$ is $220 ° T$ $220°T$

$(i)$ $(i)$ Compass Bearing $= S 40 ° W$ $= S 40° W$

$(i i)$ $(ii)$ True Bearing $= 220 ° T$ $=220°T$
Question 4 of 4

4. Question
Find the compass bearing and true bearing of $A$ $A$ from $O$ $O$
- $(i)$ $(i)$ Compass Bearing $=$ $=$ (S) (52) $°$ $°$ (W)
  
  $(i i)$ $(ii)$ True Bearing $=$ $=$ (232) $° T$ $°T$
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To get a compass bearing, take the compass quadrant where the direction belongs to, then get the angle from the vertical line around to the required direction.

Compass Bearing Quadrants

Northwest Quadrant $= N$ $=N$ __ $W$ $W$

Northeast Quadrant $= N$ $=N$ __ $E$ $E$

Southwest Quadrant $= S$ $=S$ __ $W$ $W$

Southeast Quadrant $= S$ $=S$ __ $E$ $E$

The blank is filled with the distance of the bearing from the North-South (vertical) line

A true bearing is an angle measured clockwise from the True North around to the required direction.

$(i)$ $(i)$ $Compass Bearing$ $\text(Compass Bearing)$

Notice that line $A$ $A$ is located on the Southwest Quadrant.

Using the chart, we can write the compass bearing of $A$ $A$ from $O$ $O$ by using $S$ $S$ __ $W$ $W$ . Then get the angle that spans from the vertical line ( $N$ $N$ ) to $A$ $A$ .

Notice that line $S$ $S$ and line $W$ $W$ form a supplementary angle. Therefore, we can find the value of the angle by subtracting $38 °$ $38°$ from the value of a complementary angle, which is $90 °$ $90°$ .

$90 ° - 38 °$ $90°-38°$ $=$ $=$ $52 °$ $52°$

Therefore, the compass bearing of $A$ $A$ from $O$ $O$ is $S 52 ° W$ $S 52° W$

$(i i)$ $(ii)$ $True Bearing$ $\text(True Bearing)$

Notice that when starting from North and heading to South, it forms a supplementary angle.

Since a supplementary angle is equal to $180 °$ $180°$ , we can simply add the measure of $∠ S O A$ $angle S O A$ , which is $52 °$ $52°$ , to $180 °$ $180°$ to get the bearing of $A$ $A$ from $O$ $O$ .

Don’t forget to add $T$ $T$ to the bearing to indicate True North.

$180 ° + 52 °$ $180°+52°$ $=$ $=$ $232 ° T$ $232°T$

$(i)$ $(i)$ Compass Bearing $= S 52 ° W$ $= S 52° W$

$(i i)$ $(ii)$ True Bearing $= 232 ° T$ $=232°T$

Compass Bearings and True Bearings 2

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1. Question

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Compass Bearing Quadrants

2. Question

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Compass Bearing Quadrants

3. Question

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Compass Bearing Quadrants

4. Question

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Compass Bearing Quadrants

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