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Compass Bearings and True Bearings 2Compass Bearings and True Bearings 2
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Question 1 of 4
1. Question
Find the compass bearing and true bearing of `A` from `O`
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`(i)` Compass Bearing `=` (S) (66)`°` (E)`(ii)` True Bearing `=` (114)`°T`
Hint
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Great Work!
Incorrect
To get a compass bearing, take the compass quadrant where the direction belongs to, then get the angle from the vertical line around to the required direction.
Compass Bearing Quadrants
Northwest Quadrant`=N` __ `W`Northeast Quadrant`=N` __ `E`Southwest Quadrant`=S` __ `W`Southeast Quadrant`=S` __ `E`The blank is filled with the distance of the bearing from the North-South (vertical) lineA true bearing is an angle measured clockwise from the True North around to the required direction.`(i)` `\text(Compass Bearing)`Notice that line `A` is located on the Southeast Quadrant.
Using the chart, we can write the compass bearing of `A` from `O` by using `S` __ `E`. Then get the angle that spans from the vertical line (`N`) to `A`.Notice that line `E` and line `S` form a complementary angle. Therefore, we can find the value of the angle by subtracting `24°` from the value of a complementary angle, which is `90°`.`90°-24°` `=` `66°` Therefore, the compass bearing of `A` from `O` is `S 66° E`
`(ii)` `\text(True Bearing)`Notice that when starting from North and heading to East, it forms a complementary angle.
Since a complementary angle is equal to `90°`, we can simply add the measure of `angle E O A`, which is `24°`, to `90°` to get the bearing of `A` from `O`.Don’t forget to add `T` to the bearing to indicate that it’s True North.`90°+24°` `=` `114°T` 
`(i)` Compass Bearing `= S 66° E``(ii)` True Bearing `=114°T` -
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Question 2 of 4
2. Question
Find the compass bearing and true bearing of `A` from `O`
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`(i)` Compass Bearing `=` (S) (49)`°` (W)`(ii)` True Bearing `=` (229)`°T`
Hint
Help VideoCorrect
Well Done!
Incorrect
To get a compass bearing, take the compass quadrant where the direction belongs to, then get the angle from the vertical line around to the required direction.Compass Bearing Quadrants
Northwest Quadrant`=N` __ `W`Northeast Quadrant`=N` __ `E`Southwest Quadrant`=S` __ `W`Southeast Quadrant`=S` __ `E`The blank is filled with the distance of the bearing from the North-South (vertical) lineA true bearing is an angle measured clockwise from the True North around to the required direction.`(i)` `\text(Compass Bearing)`Notice that line `A` is located on the Southwest Quadrant.
Using the chart, we can write the compass bearing of `A` from `O` by using `S` __ `W`. Then get the angle that spans from the vertical line (`N`) to `A`, which is `49°`Therefore, the compass bearing of `A` from `O` is `S 49° W``(ii)` `\text(True Bearing)`Notice that when starting from North and heading to South, it forms a supplementary angle.
Since a supplementary angle is equal to `180°`, we can simply add the measure of `angle S O A`, which is `49°`, to `180°` to get the bearing of `A` from `O`.Don’t forget to add `T` to the bearing to indicate True North.`180°+49°` `=` `229°T` 
`(i)` Compass Bearing `= S 49° W``(ii)` True Bearing `=229°T` -
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Question 3 of 4
3. Question
Find the compass bearing and true bearing of `A` from `O`
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`(i)` Compass Bearing `=` (S) (40)`°` (W)`(ii)` True Bearing `=` (220)`°T`
Hint
Help VideoCorrect
Great Work!
Incorrect
To get a compass bearing, take the compass quadrant where the direction belongs to, then get the angle from the vertical line around to the required direction.Compass Bearing Quadrants
Northwest Quadrant`=N` __ `W`Northeast Quadrant`=N` __ `E`Southwest Quadrant`=S` __ `W`Southeast Quadrant`=S` __ `E`The blank is filled with the distance of the bearing from the North-South (vertical) lineA true bearing is an angle measured clockwise from the True North around to the required direction.`(i)` `\text(Compass Bearing)`Notice that line `A` is located on the Southwest Quadrant.
Using the chart, we can write the compass bearing of `A` from `O` by using `S` __ `W`. Then get the angle that spans from the vertical line (`N`) to `A`.Notice that line `N` and line `S` form a supplementary angle. Therefore, we can find the value of the angle by subtracting the value of a complementary angle, which is `90°`, from `220°`.`220°-180°` `=` `40°` Therefore, the compass bearing of `A` from `O` is `S 40° W`
`(ii)` `\text(True Bearing)`Starting clockwise from North, line `A` gives us `168°`.
Therefore, the true bearing of `A` from `O` is `220°T``(i)` Compass Bearing `= S 40° W``(ii)` True Bearing `=220°T` -
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Question 4 of 4
4. Question
Find the compass bearing and true bearing of `A` from `O`
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`(i)` Compass Bearing `=` (S) (52)`°` (W)`(ii)` True Bearing `=` (232)`°T`
Hint
Help VideoCorrect
Correct!
Incorrect
To get a compass bearing, take the compass quadrant where the direction belongs to, then get the angle from the vertical line around to the required direction.Compass Bearing Quadrants
Northwest Quadrant`=N` __ `W`Northeast Quadrant`=N` __ `E`Southwest Quadrant`=S` __ `W`Southeast Quadrant`=S` __ `E`The blank is filled with the distance of the bearing from the North-South (vertical) lineA true bearing is an angle measured clockwise from the True North around to the required direction.`(i)` `\text(Compass Bearing)`Notice that line `A` is located on the Southwest Quadrant.
Using the chart, we can write the compass bearing of `A` from `O` by using `S` __ `W`. Then get the angle that spans from the vertical line (`N`) to `A`.Notice that line `S` and line `W` form a supplementary angle. Therefore, we can find the value of the angle by subtracting `38°` from the value of a complementary angle, which is `90°`.`90°-38°` `=` `52°` Therefore, the compass bearing of `A` from `O` is `S 52° W`
`(ii)` `\text(True Bearing)`Notice that when starting from North and heading to South, it forms a supplementary angle.
Since a supplementary angle is equal to `180°`, we can simply add the measure of `angle S O A`, which is `52°`, to `180°` to get the bearing of `A` from `O`.Don’t forget to add `T` to the bearing to indicate True North.`180°+52°` `=` `232°T` 
`(i)` Compass Bearing `= S 52° W``(ii)` True Bearing `=232°T` -