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Question 1 of 4
Simplify
7x+6y2-3+y2-5x7x+6y2โ3+y2โ5x
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When simplifying expressions, like terms can be combined or operated on.
There are two terms that both have the variable y2y2, so we can combine them.
Note that variables without constants have 11 as a constant.
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7x+67x+6y2y2 -3+โ3+y2y2 -5xโ5x |
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(6+1)(6+1)y2y2+7x-3-5x+7xโ3โ5x |
Solve the constants of like terms |
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== |
7y2+7x-3-5x7y2+7xโ3โ5x |
There are also two terms that both have the variable xx, so we can combine them.
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7y2+77y2+7xx -3-5โ3โ5xx |
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== |
7y2+(7-5)7y2+(7โ5)xx -3โ3 |
Solve the constants of like terms |
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== |
7y2+2x-37y2+2xโ3 |
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Question 2 of 4
Simplify
3b2-9+2b-b2+4b-2a3b2โ9+2bโb2+4bโ2a
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When simplifying expressions, like terms can be combined or operated on.
There are two terms that both have the variable b2b2, so we can combine them.
Note that variables without constants have 11 as a constant.
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33b2b2 -9+2b-โ9+2bโb2b2 +4b-2a+4bโ2a |
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== |
(3-1)(3โ1)b2b2 -9+2b+4b-2aโ9+2b+4bโ2a |
Solve the constants of like terms |
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== |
2b2-9+2b+4b-2a2b2โ9+2b+4bโ2a |
There are also two terms that both have the variable bb, so we can combine them.
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2b2-9+22b2โ9+2bb +4+4bb -2aโ2a |
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2b2-9+(2+4)2b2โ9+(2+4)bb -2aโ2a |
Solve the constants of like terms |
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2b2+6b-2a-9 |
Rearrange the values further |
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Question 3 of 4
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When simplifying expressions, like terms can be combined or operated on.
There are two terms that both have the variable ab, so we can combine them.
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7ab +4bc-3ab -cb |
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(7-3)ab +4bc-cb |
Solve the constants of like terms |
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= |
4ab+4bc-cb |
The variable cb can also be written as bc, and can be combined to another similar term.
Note that variables without constants have 1 as a constant.
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4ab+4bc -cb |
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4ab+4bc-bc |
cb=bc |
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= |
4ab+(4-1)bc |
Solve the constants of like terms |
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= |
4ab+3bc |
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Question 4 of 4
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When simplifying expressions, like terms can be combined or operated on.
There are two terms that both have the variable a2, so we can combine them.
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9a2 +3ab+2ba+4a2 |
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(9+4)a2 +3ab+2ba |
Solve the constants of like terms |
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= |
13a2+3ab+2ba |
The variable ba can also be written as ab, and can be combined to another similar term.
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= |
13a2+3ab +2ba |
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13a2+3ab +2ab |
ba=ab |
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= |
13a2+(3+2)ab |
Solve the constants of like terms |
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= |
13a2+5ab |