Area of Shapes 2
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Question 1 of 6
1. Question
Find the area of the Rectangle
- `\text(Area )=` (28.6) `cm^2`
Correct
Correct!
Incorrect
Area of a Rectangle Formula
`\text(Area )=``\text(base)``times``\text(height)`
Identify the known lengths
`\text(base)=6.5``\text(height)=4.4`Solve for the area using the Area of a Rectangle formula`\text(Area)` `=` `\text(base)``times``\text(height)` Area of a Rectangle formula `=` `6.5``times``4.4` Plug in the known lengths `=` `28.6 cm^2` The given measurements are in centimetres, so the area is measured as square centimetres`\text(Area)=28.6 cm^2` -
Question 2 of 6
2. Question
Find the area of the Triangle
The given measurements are in cm- `\text(Area )=` (48) `cm^2`
Hint
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Excellent!
Incorrect
Area of a Triangle Formula
`\text(Area )=1/2 times``\text(base)``times``\text(height)`Identify the known lengths
`\text(base)=12``\text(height)=8`
Solve for the area using the Area of a Triangle formula`\text(Area)` `=` `1/2 times``\text(base)``times``\text(height)` Area of a Triangle formula `=` `1/2 times ``12``times``8` Plug in the known lengths `=` `48 cm^2` The given measurements are in centimetres, so the area is measured as square centimetres`\text(Area)=48 cm^2` -
Question 3 of 6
3. Question
Find the area of the Parallelogram
- `\text(Area )=` (5.89) `cm^2`
Correct
Correct!
Incorrect
Area of a Parallelogram Formula
`\text(Area )=``\text(base)``times``\text(height)`Identify the known lengths
`\text(base)=3.1``\text(height)=1.9`
Solve for the area using the Area of a Parallelogram formula`\text(Area)` `=` `\text(base)``times``\text(height)` Area of a Parallelogram formula `=` `3.1``times``1.9` Plug in the known lengths `=` `5.89 cm^2` The given measurements are in centimetres, so the area is measured as square centimetres`\text(Area)=5.89 cm^2` -
Question 4 of 6
4. Question
Find the area of the Trapezium
- `\text(Area )=` (99) `cm^2`
Hint
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Well Done!
Incorrect
Area of a Trapezium Formula
`\text(Area)=1/2 times``\text(height)``times (``\text(base)_1``+``\text(base)_2``)`Identify the known lengths
`\text(height)=9``\text(base)_1=8``\text(base)_2=14`
Solve for the area using the Area of a Trapezium formula`\text(Area)` `=` `1/2 times``\text(height)``times (``\text(base)_1``+``\text(base)_2``)` Area of a Trapezium formula `=` `1/2 times``9``times (``8``+``14``)` Plug in the known lengths `=` `99 cm^2` The given measurements are in centimetres, so the area is measured as square centimetres`\text(Area)=99 cm^2` -
Question 5 of 6
5. Question
Find the area of the Kite
The given measurements are in centimetres- `\text(Area )=` (120) `cm^2`
Hint
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Well Done!
Incorrect
Area of a Kite Formula
`\text(Area)= 1/2 times``x``times``y`Identify the known lengths
`x=20``y=6``+``6``=``12`
Solve for the area using the Area of a Kite formula`\text(Area)` `=` `1/2 times``x``times``y` Area of a Kite formula `=` `1/2 times ``20``times``12` Plug in the known lengths `=` `120 cm^2` The given measurements are in centimetres, so the area is measured as square centimetres`\text(Area)=120 cm^2` -
Question 6 of 6
6. Question
Find the area of the Rhombus
The given measurements are in centimetres- `\text(Area )=` (75) `cm^2`
Hint
Help VideoCorrect
Great Work!
Incorrect
Area of a Rhombus Formula
`\text(Area)= 1/2 times``x``times``y`Identify the known lengths
`x=10``y=15`
Solve for the area using the Area of a Rhombus formula`\text(Area)` `=` `1/2 times``x``times``y` Area of a Rhombus formula `=` `1/2 times ``10``times``15` Plug in the known lengths `=` `75 cm^2` The given measurements are in centimetres, so the area is measured as square centimetres`\text(Area)=75 cm^2`