Area of Shapes 1

Years

Year 10

Area

Area of Shapes

Area of Shapes 1

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Question 1 of 5

1. Question
Find the area of the Square
- $\text(Area )=$ (36) $m^2$
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Area of a Square Formula

$\text(Area )=$ $\text(side)$ $times$ $\text(side)$

In a regular square, all sides are equal

Identify the known lengths

$\text(side)=6$

Solve for the area using the Area of a Square formula

$\text(Area)$ $=$ $\text(side)$ $times$ $\text(side)$ Area of a Square formula

$=$ $6$ $times$ $6$ Plug in the known lengths

$=$ $36$

The given measurements are in metres, so the area is measured as square metres

$\text(Area)=36 m^2$
Question 2 of 5

2. Question
Find the area of the Triangle
- $\text(Area )=$ (36) $m^2$
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Area of a Triangle Formula

$\text(Area )=1/2 times$ $\text(base)$ $times$ $\text(height)$

Identify the known lengths

$\text(base)=8$

$\text(height)=9$

Solve for the area using the Area of a Triangle formula

$\text(Area)$ $=$ $1/2 times$ $\text(base)$ $times$ $\text(height)$ Area of a Triangle formula

$=$ $1/2 times$ $8$ $times$ $9$ Plug in the known lengths

$=$ $36 m^2$

The given measurements are in metres, so the area is measured as square metres

$\text(Area)=36 m^2$
Question 3 of 5

3. Question
Find the area of the Parallelogram

The given measurements are in centimetres
- $\text(Area )=$ (40) $cm^2$
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Area of a Parallelogram Formula

$\text(Area )=$ $\text(base)$ $times$ $\text(height)$

Identify the known lengths

$\text(base)=8$

$\text(height)=5$

Solve for the area using the Area of a Parallelogram formula

$\text(Area)$ $=$ $\text(base)$ $times$ $\text(height)$ Area of a Parallelogram formula

$=$ $8$ $times$ $5$ Plug in the known lengths

$=$ $40 cm^2$

The given measurements are in centimetres, so the area is measured as square centimetres

$\text(Area)=40 cm^2$

Question 4 of 5

Find the area of the Trapezium

The given measurements are in metres

$\text(Area )=$ (36) $m^2$

Question 5 of 5

5. Question
Find the area of the Kite
- $\text(Area )=$ (850) $cm^2$
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Area of a Kite Formula

$\text(Area)= 1/2 times$ $x$ $times$ $y$

Identify the known lengths

$x=85$

$y=20$

Solve for the area using the Area of a Kite formula

$\text(Area)$ $=$ $1/2 times$ $x$ $times$ $y$ Area of a Kite formula

$=$ $1/2 times$ $85$ $times$ $20$ Plug in the known lengths

$=$ $850 cm^2$

The given measurements are in centimetres, so the area is measured as square centimetres

$\text(Area)=850 cm^2$

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Quiz summary

Information

1. Question

Hint

Great Work!

Area of a Square Formula

Identify the known lengths

2. Question

Hint

Fantastic!

Area of a Triangle Formula

Identify the known lengths

3. Question

Hint

Nice Job!

Area of a Parallelogram Formula

Identify the known lengths

4. Question

Hint

Fantastic!

Area of a Trapezium Formula

Identify the known lengths

5. Question

Hint

Correct!

Area of a Kite Formula

Identify the known lengths

Quizzes

$\text(Area)$	$=$	$\text(side)$ $times$ $\text(side)$	Area of a Square formula
	$=$	$6$ $times$ $6$	Plug in the known lengths
	$=$	$36$

$\text(Area)$	$=$	$1/2 times$ $\text(base)$ $times$ $\text(height)$	Area of a Triangle formula

	$=$	$1/2 times$ $8$ $times$ $9$	Plug in the known lengths

	$=$	$36 m^2$

$\text(Area)$	$=$	$\text(base)$ $times$ $\text(height)$	Area of a Parallelogram formula
	$=$	$8$ $times$ $5$	Plug in the known lengths
	$=$	$40 cm^2$

$\text(Area)$	$=$	$1/2 times$ $\text(height)$ $times ($ $\text(base)_1$ $+$ $\text(base)_2$ $)$	Area of a Trapezium formula

	$=$	$1/2 times$ $4$ $times ($ $6$ $+$ $12$ $)$	Plug in the known lengths

	$=$	$36 m^2$

$\text(Area)$	$=$	$1/2 times$ $x$ $times$ $y$	Area of a Kite formula

	$=$	$1/2 times$ $85$ $times$ $20$	Plug in the known lengths

	$=$	$850 cm^2$