Area of Shapes 1
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Question 1 of 5
1. Question
Find the area of the Square
- `\text(Area )=` (36) `m^2`
Hint
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Incorrect
Area of a Square Formula
`\text(Area )=``\text(side)``times``\text(side)`In a regular square, all sides are equal
Identify the known lengths
`\text(side)=6`Solve for the area using the Area of a Square formula`\text(Area)` `=` `\text(side)``times``\text(side)` Area of a Square formula `=` `6``times``6` Plug in the known lengths `=` `36` The given measurements are in metres, so the area is measured as square metres`\text(Area)=36 m^2` -
Question 2 of 5
2. Question
Find the area of the Triangle
- `\text(Area )=` (36) `m^2`
Hint
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Area of a Triangle Formula
`\text(Area )=1/2 times``\text(base)``times``\text(height)`Identify the known lengths
`\text(base)=8``\text(height)=9`
Solve for the area using the Area of a Triangle formula`\text(Area)` `=` `1/2 times``\text(base)``times``\text(height)` Area of a Triangle formula `=` `1/2 times ``8``times``9` Plug in the known lengths `=` `36 m^2` The given measurements are in metres, so the area is measured as square metres`\text(Area)=36 m^2` -
Question 3 of 5
3. Question
Find the area of the Parallelogram
The given measurements are in centimetres- `\text(Area )=` (40) `cm^2`
Hint
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Area of a Parallelogram Formula
`\text(Area )=``\text(base)``times``\text(height)`Identify the known lengths
`\text(base)=8``\text(height)=5`
Solve for the area using the Area of a Parallelogram formula`\text(Area)` `=` `\text(base)``times``\text(height)` Area of a Parallelogram formula `=` `8``times``5` Plug in the known lengths `=` `40 cm^2` The given measurements are in centimetres, so the area is measured as square centimetres`\text(Area)=40 cm^2` -
Question 4 of 5
4. Question
Find the area of the Trapezium
The given measurements are in metres- `\text(Area )=` (36) `m^2`
Hint
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Incorrect
Area of a Trapezium Formula
`\text(Area)=1/2 times``\text(height)``times (``\text(base)_1``+``\text(base)_2``)`Identify the known lengths
`\text(height)=4``\text(base)_1=6``\text(base)_2=12`
Solve for the area using the Area of a Trapezium formula`\text(Area)` `=` `1/2 times``\text(height)``times (``\text(base)_1``+``\text(base)_2``)` Area of a Trapezium formula `=` `1/2 times``4``times (``6``+``12``)` Plug in the known lengths `=` `36 m^2` The given measurements are in metres, so the area is measured as square metres`\text(Area)=36 m^2` -
Question 5 of 5
5. Question
Find the area of the Kite
- `\text(Area )=` (850) `cm^2`
Hint
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Correct!
Incorrect
Area of a Kite Formula
`\text(Area)= 1/2 times``x``times``y`Identify the known lengths
`x=85``y=20`
Solve for the area using the Area of a Kite formula`\text(Area)` `=` `1/2 times``x``times``y` Area of a Kite formula `=` `1/2 times ``85``times``20` Plug in the known lengths `=` `850 cm^2` The given measurements are in centimetres, so the area is measured as square centimetres`\text(Area)=850 cm^2`