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Question 1 of 4
Add the following:
312+515
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A mixed number consists of a whole number and a fraction.
First, add the whole numbers
Notice that the fractions have different denominators.
Find the LCD of 2 and 5 so we can add the fractions.
Proceed with adding the fractions
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12+15 |
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= |
(10÷2)+(10÷5)10 |
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= |
5+210 |
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= |
710 |
Finally, combine the sum of the whole numbers and the sum of the fractions
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Question 2 of 4
Add the following:
435+518
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A mixed number consists of a whole number and a fraction.
First, add the whole numbers
Add the fractions using cross method.
Start by multiplying the two denominators. Use the product as a denominator for a new fraction.
To get the numerator, cross multiply the given addition problem and add the products.
35+18 |
= |
(3×8)+(5×1)40 |
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= |
24+540 |
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= |
2940 |
Finally, combine the sum of the whole numbers and the sum of the fractions
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Question 3 of 4
Subtract the following:
3110-114
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First, transform the mixed fractions to improper fractions
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3110−114 |
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= |
(10×3)+110−(4×1)+14 |
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= |
30+110−4+14 |
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= |
3110−54 |
Notice that the fractions have different denominators.
Find the LCD of 10 and 4 so we can subtract the fractions.
Multiples of 10:
10203040
Multiples of 4:
4812162024
The LCD of 10 and 4 is 20
Next, we get the same denominator and subtract the fractions
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3110-54 |
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= |
31×210×2−5×54×5 |
Multiply each fraction so that the denominator becomes 20 |
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= |
6220−2520 |
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= |
3720 |
Transform the fraction back to a mixed fraction
Start by dividing the numerator by the denominator
Arrange the numbers for long division
20 goes into 37 once. So write 1 above the line.
Multiply 1 to 20 and write the answer below 37
Subtract 20 from 37 and write the answer one line below
Since 20 cannot go into 17 anymore, 17 is left as the Remainder and 1 is the Quotient
Substitute values into the given formula
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Question 4 of 4
Subtract the following:
12-8310
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First, transform the mixed fractions to improper fractions
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12−8310 |
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= |
121−(10×8)+310 |
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= |
121−80+310 |
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= |
121−8310 |
Use cross method to subtract the fractions.
Start by multiplying the two denominators. Use the product as a denominator for a new fraction.
To get the numerator, cross multiply the given addition problem and subtract the products.
121−8310 |
= |
(12×10)−(1×83)10 |
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= |
120-8310 |
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= |
3710 |
Transform the fraction back to a mixed fraction
Start by dividing the numerator by the denominator
Arrange the numbers for long division
10 goes into 37 three times. So write 3 above the line.
Multiply 3 to 10 and write the answer below 37
Subtract 30 from 37 and write the answer one line below
Since 10 cannot go into 7 anymore, 7 is left as the Remainder and 3 is the Quotient
Substitute values into the given formula