Equation Word Problems 2
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Question 1 of 5
1. Question
The product of 33 and aa is divided by 44 and is equal to twice the sum of aa and 1010. Solve for aa.- a=a= (-16)
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Inverse Operations
When moving a term to the other side of an equation, the operation is inversed.Distributive Property
aa(b+c)=(b+c)=aab+b+aaccKeywords for Word Problems Keyword Meaning Certain number Unknown variable (x,y,z,x,y,z, etc) is the same as, The answer is, is equal == sum, and, plus, more than ++ subtracted, less, minus -− times, product, multiplied, twice ×× half of, divide by ÷÷ First, form an equation using the information given.The product of 33 and aa is divided by 44 and is equal to twice the sum of aa and 1010 3×a3×a ÷÷ 44 == 2×2× a+10a+10 Simplify the equation:(3×a)÷4(3×a)÷4 == 2×(a+10)2×(a+10) 3a43a4 == 2(a+10)2(a+10) To solve for aa, it needs to be alone on one side.Start by removing 1414 by multiplying both sides of the equation by 44.3a43a4 == 2(2(aa +10)+10) 3a4×43a4×4 == 2(2(aa +10)+10)×4×4 33aa == 8(8(aa +10)+10) 14×414×4 cancels out Next, expand the right side of the equation using the Distributive Property.33aa == 88((aa +10)+10) 33aa == 88aa ++88(10)(10) 33aa == 88aa +80+80 Now, move 8a8a to the other side by subtracting 8a8a from both sides of the equation.33aa == 88aa +80+80 33aa -8a−8a == 88aa +80+80 -8a−8a -5−5aa == 8080 8a-8a8a−8a cancels out Finally, remove -5−5 by dividing both sides of the equation by -5−5.-5−5aa == 8080 -5−5aa÷-5÷−5 == 8080÷-5÷−5 aa == -16−16 -5÷-5−5÷−5 cancels out a=-16a=−16 -
Question 2 of 5
2. Question
33 times a number plus 77 is the same as 55 times the number minus 99. What is the number?- (8)
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Chapters- Chapters
Inverse Operations
When moving a term to the other side of an equation, the operation is inversed.Keywords for Word Problems Keyword Meaning Certain number Unknown variable (x,y,z,x,y,z, etc) is the same as, The answer is, is equal == sum, and, plus, more than ++ subtracted, less, minus -− times, product, multiplied, twice ×× half of, divide by ÷÷ First, label the values and form an equation using the information given.Number=n=n33 times a number plus 77 is the same as 55 times the number minus 99 33 ×× nn ++ 77 == 55 ×× nn -− 99 Simplify the equation:(3×n)+7(3×n)+7 == (5×n)-9(5×n)−9 3n+73n+7 == 5n-95n−9 To solve for nn, it needs to be alone on one side.Start by moving 3n3n to the other side by subtracting 3n3n from both sides of the equation.33nn +7+7 == 55nn -9−9 33nn +7+7 -3n−3n == 55nn -9−9 -3n−3n 77 == 22nn -9−9 3n-3n3n−3n cancels out Next, move 99 to the other side by adding 99 to both sides of the equation.77 == 22nn -9−9 77 +9+9 == 22nn -9−9 +9+9 1616 == 22nn -9+9−9+9 cancels out Finally, remove 22 by dividing both sides of the equation by 22.1616 == 22nn 1616÷2÷2 == 22nn÷2÷2 88 == nn 2÷22÷2 cancels out nn == 88 The number is 88.Check our workTo confirm our answer, substitute n=8n=8 to the original equation.3n+73n+7 == 5n-95n−9 3(8)+73(8)+7 == 5(8)-95(8)−9 Substitute n=8n=8 24+724+7 == 40-940−9 3131 == 3131 Since the equation is true, the answer is correct.88 -
Question 3 of 5
3. Question
A number divided by 44 plus 66 equals twice the number minus 1515. What is the number?- (12)
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Chapters- Chapters
Inverse Operations
When moving a term to the other side of an equation, the operation is inversed.Distributive Property
aa(b+c)=(b+c)=aab+b+aaccKeywords for Word Problems Keyword Meaning Certain number Unknown variable (x,y,z,x,y,z, etc) is the same as, The answer is, is equal == sum, and, plus, more than ++ subtracted, less, minus -− times, product, multiplied, twice ×× half of, divide by ÷÷ First, label the values and form an equation using the information given.Number=x=xA number divided by 44 plus 66 equals twice the number minus 1515 xx ÷÷ 44 ++ 66 == 2×2× xx -− 1515 Simplify the equation:(x÷4)+6(x÷4)+6 == (2×x)-15(2×x)−15 x4+6x4+6 == 2x-152x−15 To solve for xx, it needs to be alone on one side.Start by removing 1414 by multiplying both sides of the equation by 44.x4+6x4+6 == 22xx -15−15 (x4+6)×4(x4+6)×4 == (2(2xx -15)−15)×4×4 xx +24+24 == 4(24(2xx -15)−15) 14×414×4 cancels out Next, expand the right side of the equation using the Distributive Property.xx +24+24 == 44(2(2xx -15)−15) xx +24+24 == 44(2(2xx)+)+44(-15)(−15) xx +24+24 == 88xx -60−60 Now, move xx to the other side by subtracting xx from both sides of the equation.xx +24+24 == 88xx -60−60 xx +24+24 -x−x == 88xx -60−60 -x−x 2424 == 77xx -60−60 x-xx−x cancels out Then, move 6060 to the other side by adding 6060 to both sides of the equation.2424 == 77xx -60 24 +60 = 7x -60 +60 84 = 7x -60+60 cancels out Finally, remove 7 by dividing both sides of the equation by 7.84 = 7x 84÷7 = 7x÷7 12 = x 7÷7 cancels out x = 12 The number is 12.12 -
Question 4 of 5
4. Question
The sum of a number and 6 when multiplied by 4 equals 3 times the sum of 9 and that number. What is the number?- (3)
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Chapters- Chapters
Inverse Operations
When moving a term to the other side of an equation, the operation is inversed.Distributive Property
a(b+c)=ab+acKeywords for Word Problems Keyword Meaning Certain number Unknown variable (x,y,z, etc) is the same as, The answer is, is equal = sum, and, plus, more than + subtracted, less, minus - times, product, multiplied, twice × half of, divide by ÷ First, label the values and form an equation using the information given.Number=xThe sum of a number and 6 when multiplied by 4 equals 3 times the sum of 9 and that number x+6 × 4 = 3× 9+x Simplify the equation:(x+6)×4 = 3×(9+x) 4(x+6) = 3(9+x) To solve for x, it needs to be alone on one side.Start by expanding both sides of the equation by using the Distributive Property.4(x +6) = 3(9+x) 4x +4(6) = 3(9)+3x 4x +24 = 27+3x Now, move 3x to the other side by subtracting 3x from both sides of the equation.4x +24 = 27+3x 4x +24 -3x = 27+3x -3x x +24 = 27 3x-3x cancels out Finally, move 24 to the other side by subtracting 24 from both sides of the equation.x +24 = 27 x +24 -24 = 27 -24 x = 3 24-24 cancels out The number is 3.Check our workTo confirm our answer, substitute x=3 to the original equation.4(x+6) = 3(9+x) 4(3+6) = 3(9+3) Substitute x=3 4(9) = 3(12) 36 = 36 Since the equation is true, the answer is correct.3 -
Question 5 of 5
5. Question
24 plus 3 times a number equals 4 divided into the sum of 7 times the number plus 1. What is the number?- (-19)
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Chapters- Chapters
Inverse Operations
When moving a term to the other side of an equation, the operation is inversed.Distributive Property
a(b+c)=ab+acKeywords for Word Problems Keyword Meaning Certain number Unknown variable (x,y,z, etc) is the same as, The answer is, is equal = sum, and, plus, more than + subtracted, less, minus - times, product, multiplied, twice × half of, divide by ÷ First, label the values and form an equation using the information given.Number=n24 plus 3 times a number equals 4 divided into the sum of 7 times the number plus 1 24 + 3 × n = [(7×n)+1]÷4 Simplify the equation:24+(3×n) = [(7×n)+1]÷4 24+3n = 7n+14 To solve for n, it needs to be alone on one side.Start by removing 14 by multiplying both sides of the equation by 4.24+3n = 7n+14 (24+3n)×4 = 7n+14×4 4(24+3n) = 7n +1 14×4 cancels out Next, expand the left side of the equation using the Distributive Property.4(24+3n) = 7n +1 4(24)+4(3n) = 7n +1 96+12n = 7n +1 Now, move 7n to the other side by subtracting 7n from both sides of the equation.96+12n = 7n +1 96+12n -7n = 7n +1 -7n 96+5n = 1 7n-7n cancels out Then, move 96 to the other side by subtracting 96 from both sides of the equation.96+5n = 1 96+5n -96 = 1 -96 5n = -95 96-96 cancels out Finally, remove 5 by dividing both sides of the equation by 5.5n = -95 5n÷5 = -95÷5 n = -19 5÷5 cancels out The number is -19.Check our workTo confirm our answer, substitute n=-19 to the original equation.24+3n = 7n+14 24+3(-19) = 7(-19)+14 Substitute n=-19 24-57 = -133+14 -33 = -1324 -33 = -33 Since the equation is true, the answer is correct.-19
Quizzes
- One Step Equations – Add and Subtract 1
- One Step Equations – Add and Subtract 2
- One Step Equations – Add and Subtract 3
- One Step Equations – Add and Subtract 4
- One Step Equations – Multiply and Divide 1
- One Step Equations – Multiply and Divide 2
- One Step Equations – Multiply and Divide 3
- One Step Equations – Multiply and Divide 4
- Two Step Equations 1
- Two Step Equations 2
- Two Step Equations 3
- Two Step Equations 4
- Multi-Step Equations 1
- Multi-Step Equations 2
- Solve Equations using the Distributive Property 1
- Solve Equations using the Distributive Property 2
- Solve Equations using the Distributive Property 3
- Equations with Variables on Both Sides 1
- Equations with Variables on Both Sides 2
- Equations with Variables on Both Sides 3
- Equations with Variables on Both Sides (Fractions) 1
- Equations with Variables on Both Sides (Fractions) 2
- Solve Equations with Variables on Both Sides using the Distributive Property 1
- Solve Equations with Variables on Both Sides using the Distributive Property 2
- Solve Equations with Variables on Both Sides using the Distributive Property 3
- Solve Equations with Variables on Both Sides using the Distributive Property 4
- Equation Word Problems 1
- Equation Word Problems 2
- Equation Word Problems 3
- Equation Word Problems 4
- Equation Word Problems (Age)
- Equation Word Problems (Money)
- Equation Word Problems (Harder)
- Equation Problems with Substitution
- Equation Problems (Geometry) 1
- Equation Problems (Geometry) 2
- Equation Problems (Perimeter)
- Equation Problems (Area)
- Change the Subject of an Equation 1
- Change the Subject of an Equation 2
- Change the Subject of an Equation 3