Compass Bearings and True Bearings 1

Years

Year 11

Bearings

Compass Bearings and True Bearings

Compass Bearings and True Bearings 1

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Question 1 of 5

1. Question
Using the image below, find the value of the following:
- $(i)$ $(i)$ Bearing of A from O $=$ $=$ (60) $°$ $°$
  
  $(i i)$ $(ii)$ Bearing of B from O $=$ $=$ (199) $°$ $°$
  
  $(i i i)$ $(iii)$ Bearing of C from O $=$ $=$ (328) $°$ $°$
Hint

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Correct

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Incorrect

When solving for bearings, start from North and move clockwise.

$(i)$ $(i)$    Bearing of $A$ $A$ from $O$ $O$

Notice that when starting from North and heading to East, the two lines form a complementary angle.

Since complementary angles add up to $90 °$ $90°$ , we can simply subtract the measure of $∠ A O E$ $angle A O E$ , which is $30 °$ $30°$ , to get the bearing of $A$ $A$ from $O$ $O$ .

$90 ° - 30 °$ $90°-30°$ $=$ $=$ $60 °$ $60°$

$(i i)$ $(ii)$    Bearing of $B$ $B$ from $O$ $O$

Notice that when starting from North and heading to South, the two lines form a supplementary angle.

Since supplementary angles add up to $180 °$ $180°$ , we can simply add the measure of $∠ S O B$ $angle S O B$ , which is $19 °$ $19°$ , to get the bearing of $B$ $B$ from $O$ $O$ .

$180 ° + 19 °$ $180°+19°$ $=$ $=$ $199 °$ $199°$

$(i i i)$ $(iii)$    Bearing of $C$ $C$ from $O$ $O$

Notice that when starting from North and heading all the way back to North, it forms a revolution.

Since a revolution is equal to $360 °$ $360°$ , we can simply subtract the measure of $∠ C O N$ $angle C O N$ , which is $32 °$ $32°$ , to get the bearing of $C$ $C$ from $O$ $O$ .

$360 ° - 32 °$ $360°-32°$ $=$ $=$ $328 °$ $328°$

$(i) 60 °$ $(i) 60°$

$(i i) 199 °$ $(ii) 199°$

$(i i i) 328 °$ $(iii) 328°$
Question 2 of 5

2. Question
Find the compass bearing and true bearing of $A$ $A$ from $O$ $O$
- $(i)$ $(i)$ Compass Bearing $=$ $=$ (N) (19) $°$ $°$ (E)
  
  $(i i)$ $(ii)$ True Bearing $=$ $=$ (19) $° T$ $°T$
Hint

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Correct

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To get a compass bearing, take the compass quadrant where the direction belongs to, then get the angle from the vertical line around to the required direction.

Compass Bearing Quadrants

Northwest Quadrant $= N$ $=N$ __ $W$ $W$

Northeast Quadrant $= N$ $=N$ __ $E$ $E$

Southwest Quadrant $= S$ $=S$ __ $W$ $W$

Southeast Quadrant $= S$ $=S$ __ $E$ $E$

The blank is filled with the distance of the bearing from the North-South (vertical) line

A true bearing is an angle measured clockwise from the True North around to the required direction.

$(i)$ $(i)$ $Compass Bearing$ $\text(Compass Bearing)$

Notice that line $A$ $A$ is located on the Northeast Quadrant.

Using the chart, we can write the compass bearing of $A$ $A$ from $O$ $O$ by using $N$ $N$ __ $E$ $E$ . Then get the angle that spans from the vertical line ( $N$ $N$ ) to $A$ $A$ , which is $19 °$ $19°$

Therefore, the compass bearing of $A$ $A$ from $O$ $O$ is $N 19 ° E$ $N 19° E$

$(i i)$ $(ii)$ $True Bearing$ $\text(True Bearing)$

Notice that line $A$ $A$ is $19 °$ $19°$ from the starting point, which is from the North line.

That means that the true bearing of $A$ $A$ from $O$ $O$ is simply $19 ° T$ $19°T$ .

$T$ $T$ stands for True North.

$(i)$ $(i)$ Compass Bearing $= N 19 ° E$ $= N 19° E$

$(i i)$ $(ii)$ True Bearing $= 19 ° T$ $=19°T$
Question 3 of 5

3. Question
Find the compass bearing and true bearing of $A$ $A$ from $O$ $O$
- $(i)$ $(i)$ Compass Bearing $=$ $=$ (N) (34) $°$ $°$ (W)
  
  $(i i)$ $(ii)$ True Bearing $=$ $=$ (326) $° T$ $°T$
Hint

Help Video

Correct

Excellent!

Incorrect

To get a compass bearing, take the compass quadrant where the direction belongs to, then get the angle from the vertical line around to the required direction.

Compass Bearing Quadrants

Northwest Quadrant $= N$ $=N$ __ $W$ $W$

Northeast Quadrant $= N$ $=N$ __ $E$ $E$

Southwest Quadrant $= S$ $=S$ __ $W$ $W$

Southeast Quadrant $= S$ $=S$ __ $E$ $E$

The blank is filled with the distance of the bearing from the North-South (vertical) line

A true bearing is an angle measured clockwise from the True North around to the required direction.

$(i)$ $(i)$ $Compass Bearing$ $\text(Compass Bearing)$

Notice that line $A$ $A$ is located on the Northwest Quadrant.

Using the chart, we can write the compass bearing of $A$ $A$ from $O$ $O$ by using $N$ $N$ __ $W$ $W$ . Then get the angle that spans from the vertical line ( $N$ $N$ ) to $A$ $A$ , which is $34 °$ $34°$

Therefore, the compass bearing of $A$ $A$ from $O$ $O$ is $N 34 ° W$ $N 34° W$

$(i i)$ $(ii)$ $True Bearing$ $\text(True Bearing)$

Notice that when starting from North and heading all the way back to North, it forms a revolution.

Since a revolution is equal to $360 °$ $360°$ , we can simply subtract the measure of $∠ A O N$ $angle A O N$ , which is $34 °$ $34°$ , to get the bearing of $A$ $A$ from $O$ $O$ .

Don’t forget to add $T$ $T$ to the bearing to indicate True North.

$360 ° - 34 °$ $360°-34°$ $=$ $=$ $326 ° T$ $326°T$

$(i)$ $(i)$ Compass Bearing $= N 34 ° W$ $= N 34° W$

$(i i)$ $(ii)$ True Bearing $= 326 ° T$ $=326°T$
Question 4 of 5

4. Question
Find the compass bearing and true bearing of $A$ $A$ from $O$ $O$
- $(i)$ $(i)$ Compass Bearing $=$ $=$ (N) (73) $°$ $°$ (W)
  
  $(i i)$ $(ii)$ True Bearing $=$ $=$ (287) $° T$ $°T$
Hint

Help Video

Correct

Correct!

Incorrect

To get a compass bearing, take the compass quadrant where the direction belongs to, then get the angle from the vertical line around to the required direction.

Compass Bearing Quadrants

Northwest Quadrant $= N$ $=N$ __ $W$ $W$

Northeast Quadrant $= N$ $=N$ __ $E$ $E$

Southwest Quadrant $= S$ $=S$ __ $W$ $W$

Southeast Quadrant $= S$ $=S$ __ $E$ $E$

The blank is filled with the distance of the bearing from the North-South (vertical) line

A true bearing is an angle measured clockwise from the True North around to the required direction.

$(i)$ $(i)$ $Compass Bearing$ $\text(Compass Bearing)$

Notice that line $A$ $A$ is located on the Northwest Quadrant.

Using the chart, we can write the compass bearing of $A$ $A$ from $O$ $O$ by using $N$ $N$ __ $W$ $W$ . Then get the angle that spans from the vertical line ( $N$ $N$ ) to $A$ $A$ .

Notice that line $N$ $N$ and line $W$ $W$ form a complementary angle. Therefore, we can find the value of the angle by subtracting $17 °$ $17°$ from the value of a complementary angle, which is $90 °$ $90°$ .

$90 ° - 17 °$ $90°-17°$ $=$ $=$ $73 °$ $73°$

Therefore, the compass bearing of $A$ $A$ from $O$ $O$ is $N 73 ° W$ $N 73° W$

$(i i)$ $(ii)$ $True Bearing$ $\text(True Bearing)$

Notice that when starting from North and heading all the way back to North, it forms a revolution.

Since a revolution is equal to $360 °$ $360°$ , we can simply subtract the measure of $∠ A O N$ $angle A O N$ , which is $73 °$ $73°$ , to get the bearing of $A$ $A$ from $O$ $O$ .

Don’t forget to add $T$ $T$ to the bearing to indicate True North.

$360 ° - 73 °$ $360°-73°$ $=$ $=$ $287 ° T$ $287°T$

Alternatively, we can add the value of $3$ $3$ quadrants and $17 °$ $17°$ to get the same value.

$(3 \times 90 °) + 17 °$ $(3xx90°)+17°$ $=$ $=$ $270 ° + 17 °$ $270°+17°$

$=$ $=$ $287 ° T$ $287°T$

$(i)$ $(i)$ Compass Bearing $= N 73 ° W$ $= N 73° W$

$(i i)$ $(ii)$ True Bearing $= 287 ° T$ $=287°T$
Question 5 of 5

5. Question
Find the compass bearing and true bearing of $A$ $A$ from $O$ $O$
- $(i)$ $(i)$ Compass Bearing $=$ $=$ (S) (12) $°$ $°$ (E)
  
  $(i i)$ $(ii)$ True Bearing $=$ $=$ (168) $° T$ $°T$
Hint

Help Video

Correct

Nice Job!

Incorrect

To get a compass bearing, take the compass quadrant where the direction belongs to, then get the angle from the vertical line around to the required direction.

Compass Bearing Quadrants

Northwest Quadrant $= N$ $=N$ __ $W$ $W$

Northeast Quadrant $= N$ $=N$ __ $E$ $E$

Southwest Quadrant $= S$ $=S$ __ $W$ $W$

Southeast Quadrant $= S$ $=S$ __ $E$ $E$

The blank is filled with the distance of the bearing from the North-South (vertical) line

A true bearing is an angle measured clockwise from the True North around to the required direction.

$(i)$ $(i)$ $Compass Bearing$ $\text(Compass Bearing)$

Notice that line $A$ $A$ is located on the Southeast Quadrant.

Using the chart, we can write the compass bearing of $A$ $A$ from $O$ $O$ by using $S$ $S$ __ $E$ $E$ . Then get the angle that spans from the vertical line ( $N$ $N$ ) to $A$ $A$ .

Notice that line $N$ $N$ and line $W$ $W$ form a supplementary angle. Therefore, we can find the value of the angle by subtracting $168 °$ $168°$ from the value of a supplementary angle, which is $180 °$ $180°$ .

$180 ° - 168 °$ $180°-168°$ $=$ $=$ $12 °$ $12°$

Therefore, the compass bearing of $A$ $A$ from $O$ $O$ is $S 12 ° E$ $S 12° E$

$(i i)$ $(ii)$ $True Bearing$ $\text(True Bearing)$

Starting clockwise from North, line $A$ $A$ gives us $168 °$ $168°$ .

Therefore, the true bearing of $A$ $A$ from $O$ $O$ is $168 ° T$ $168°T$

$(i)$ $(i)$ Compass Bearing $= S 12 ° E$ $= S 12° E$

$(i i)$ $(ii)$ True Bearing $= 168 ° T$ $=168°T$

Compass Bearings and True Bearings 1

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Quiz summary

Information

1. Question

Hint

Fantastic!

2. Question

Hint

Keep Going!

Compass Bearing Quadrants

3. Question

Hint

Excellent!

Compass Bearing Quadrants

4. Question

Hint

Correct!

Compass Bearing Quadrants

5. Question

Hint

Nice Job!

Compass Bearing Quadrants

Quizzes

$(3 \times 90 °) + 17 °$ $(3xx90°)+17°$	$=$ $=$	$270 ° + 17 °$ $270°+17°$
	$=$ $=$	$287 ° T$ $287°T$