Area of Composite Shapes
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Question 1 of 5
1. Question
Find the area of the shape.
The given measurements are in centimetres- `\text(Area )=` (420) `\text(cm)^2`
Hint
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Well Done!
Incorrect
Area of a Rectangle Formula
`\text(Area )=\text(length) times \text(width)`Identify the known lengths
`\text(length)` (Larger Rectangle)`=22``\text(width)` (Larger Rectangle)`=10``\text(length)` (Smaller Rectangle)`=10``\text(width)` (Smaller Rectangle)`=30-10=20`First, solve for the area of the Larger Rectangle using the formula`\text(Area)``\text(Larger Rectangle)` `=` `\text(length)``times``\text(width)` Area of a Rectangle Formula `=` `10``times``22` Plug in the known values `\text(Area)``\text(Larger Rectangle)` `=` `220 \text(cm)^2` Next, solve for the area of the Smaller Rectangle using the formula`\text(Area)``\text(Smaller Rectangle)` `=` `\text(length)``times``\text(width)` Area of a Rectangle Formula `=` `10``times``20` Plug in the known values `\text(Area)``\text(Smaller Rectangle)` `=` `200 \text(cm)^2` Finally, get the final area by adding the area of the
Smaller Rectangle to the area of the Larger Rectangle$$\text{Total Area}$$ `=` `220``+``200` Plug in the known values `=` `420 \text(cm)^2` The given measurements are in centimetres, so the area is measured as square centimetres`\text(Area)=420 \text(cm)^2` -
Question 2 of 5
2. Question
Find the area of the shape.
The given measurements are in metres- `\text(Area )=` (156) `\text(m)^2`
Hint
Help VideoCorrect
Nice Job!
Incorrect
Area of a Rectangle Formula
`\text(Area )=\text(length) times \text(width)`Identify the known lengths
`\text(length)` (Larger Rectangle)`=20``\text(width)` (Larger Rectangle)`=5``\text(length)` (Smaller Rectangle)`=4``\text(width)` (Smaller Rectangle)`=14`First, solve for the area of the Larger Rectangle using the formula`\text(Area)``\text(Larger Rectangle)` `=` `\text(length)``times``\text(width)` Area of a Rectangle Formula `=` `20``times``5` Plug in the known values `\text(Area)``\text(Larger Rectangle)` `=` `100 \text(m)^2` Next, solve for the area of the Smaller Rectangle using the formula`\text(Area)``\text(Smaller Rectangle)` `=` `\text(length)``times``\text(width)` Area of a Rectangle Formula `=` `4``times``14` Plug in the known values `\text(Area)``\text(Smaller Rectangle)` `=` `56 \text(m)^2` Finally, get the final area by adding the area of the
Smaller Rectangle to the area of the Larger Rectangle$$\text{Total Area}$$ `=` `100``+``56` Plug in the known values `=` `156 \text(m)^2` The given measurements are in metres, so the area is measured as square metres`\text(Area)=156 \text(m)^2` -
Question 3 of 5
3. Question
Find the area of the shape.
The given measurements are in centimetres- `\text(Area )=` (10000) `\text(cm)^2`
Hint
Help VideoCorrect
Excellent!
Incorrect
Area of a Rectangle Formula
`\text(Area )=\text(length) times \text(width)`Identify the known lengths
`\text(length)` (Larger Rectangles)`=100``\text(width)` (Larger Rectangles)`=40``\text(length)` (Smaller Rectangle)`=100-2(30)=40``\text(width)` (Smaller Rectangle)`=50`First, solve for the area of the two Larger Rectangles using the formula`\text(Area)``\text(Larger Rectangles)` `=` `\text(length)``times``\text(width)` Area of a Rectangle Formula `=` `100``times``40` Plug in the known values `\text(Area)``\text(Larger Rectangles)` `=` `4000 \text(cm)^2` Next, solve for the area of the Smaller Rectangle using the formula`\text(Area)``\text(Smaller Rectangle)` `=` `\text(length)``times``\text(width)` Area of a Rectangle Formula `=` `40``times``50` Plug in the known values `\text(Area)``\text(Smaller Rectangle)` `=` `2000 \text(cm)^2` Finally, get the final area by adding the area of the
Smaller Rectangle to the area of the two Larger Rectangles$$\text{Total Area}$$ `=` `2(``4000``)+``2000` Plug in the known values `=` `10 000 \text(cm)^2` The given measurements are in centimetres, so the area is measured as square centimetres`\text(Area)=10 000 \text(cm)^2` -
Question 4 of 5
4. Question
Find the area of the shape.
The given measurements are in centimetres- `\text(Area )=` (800) `\text(cm)^2`
Hint
Help VideoCorrect
Fantastic!
Incorrect
Area of a Rectangle Formula
`\text(Area )=``\text(length)``times``\text(width)`Area of a Triangle Formula
`\text(Area )=1/2times``\text(base)``times``\text(height)`Identify the known lengths
`\text(length)` (Rectangle)`=30``\text(width)` (Rectangle)`=20``\text(base)` (Triangle)`=20``\text(height)` (Triangle)`=10`First, solve for the area of the Rectangle using the formula`\text(Area)``\text(Rectangle)` `=` `\text(length)``times``\text(width)` Area of a Rectangle Formula `=` `30``times``20` Plug in the known values `\text(Area)``\text(Rectangle)` `=` `600 \text(cm)^2` Next, solve for the area of the Triangles using the formula`\text(Area)``\text(Triangle)` `=` `1/2``\text(base)``times``\text(height)` Area of a Rectangle Formula `=` `1/2``20``times``10` Plug in the known values `\text(Area)``\text(Triangle)` `=` `100 \text(cm)^2` Finally, get the final area by adding the area of the
two Triangles to the area of the Rectangle$$\text{Total Area}$$ `=` `600``+2(``100``)` Plug in the known values `=` `800 \text(cm)^2` The given measurements are in centimetres, so the area is measured as square centimetres`\text(Area)=800 \text(cm)^2` -
Question 5 of 5
5. Question
Find the area of the shape.
The given measurements are in metres
Round your answer to two decimal paces- `\text(Area )=` (199.23) `\text(m)^2`
Hint
Help VideoCorrect
Exceptional!
Incorrect
Area of a Rectangle Formula
`\text(Area )=``\text(length)``times``\text(width)`Area of a Semicircle Formula
`\text(Area )=1/2 times pi times``\text(radius)^2`Identify the known lengths
`\text(length)` (Rectangle)`=18``\text(width)` (Rectangle)`=4``\text(radius)` (Triangle)`=18divide2=9`First, solve for the area of the Rectangle using the formula`\text(Area)``\text(Rectangle)` `=` `\text(length)``times``\text(width)` Area of a Rectangle Formula `=` `18``times``4` Plug in the known values `\text(Area)``\text(Rectangle)` `=` `72 \text(m)^2` Next, solve for the area of the Semicircle using the formula`\text(Area)``\text(Semicircle)` `=` `1/2 times pi times``\text(radius)^2` Area of a Rectangle Formula `=` `1/2 times pi times``\text(9)^2` Plug in the known values `\text(Area)``\text(Triangle)` `=` `127.23 \text(m)^2` Rounded to two decimal places Finally, get the final area by adding the area of the
Semicircle to the area of the Rectangle$$\text{Total Area}$$ `=` `72``+``127.23` Plug in the known values `=` `199.23 \text(m)^2` The given measurements are in metres, so the area is measured as square metres`\text(Area)=199.23 \text(m)^2`