Odd and Even Functions 2
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Question 1 of 5
1. Question
Identify if the curve `f(x)=-5x` is an odd or even functionHint
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Excellent!
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Even Functions
`f(-x)=f(x)`Odd Functions
`f(-x)=-f(x)`Substitute negative `x` to the function`f(x)` `=` `-5x` `f(-x)` `=` `-5(-x)` `f(-x)` `=` `5x` `f(-x)` `=` `-f(x)` `-f(x)=5x` Since `f(-x)=-f(x)`, `f(x)=-5x` is an odd function`\text(Odd Function)` -
Question 2 of 5
2. Question
Identify if the curve `f(x)=2-x` is an odd or even functionHint
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Nice Job!
Incorrect
Even Functions
`f(-x)=f(x)`Odd Functions
`f(-x)=-f(x)`Substitute negative `x` to the function`f(x)` `=` `2-x` `f(-x)` `=` `2-(-x)` `f(-x)` `=` `2+x` Since the curve does not satisfy both condition, `f(x)=x^2+2x` is neither odd nor even function`\text(Neither)` -
Question 3 of 5
3. Question
Identify if the curve is an odd or even function
Hint
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Well Done!
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Even Functions
`f(-x)=f(x)`Odd Functions
`f(-x)=-f(x)`Odd and even functions are symmetric on the point of origin and the y-axisRotate the curve and check if it is symmetric to either the point of origin or the y-axisRotated on the origin
Rotated on the y-axis
Since the curve does not satisfy both conditions, it is neither odd nor even function`\text(Neither)` -
Question 4 of 5
4. Question
Identify if the curve is an odd or even function
Hint
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Fantastic!
Incorrect
Even Functions
`f(-x)=f(x)`Odd Functions
`f(-x)=-f(x)`Odd and even functions are symmetric on the point of origin and the y-axisRotate the curve and check if it is symmetric to either the point of origin or the y-axisRotated on the origin
Rotated on the y-axis
Since the curve is symmetric to the y-axis, it is an even function`\text(Even Function)` -
Question 5 of 5
5. Question
Identify if the curve is an odd or even function
Hint
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Exceptional!
Incorrect
Even Functions
`f(-x)=f(x)`Odd Functions
`f(-x)=-f(x)`Odd and even functions are symmetric on the point of origin and the y-axisRotate the curve and check if it is symmetric to either the point of origin or the y-axisRotated on the origin
Rotated on the y-axis
Since the curve is symmetric to the point of origin, it is an odd function`\text(Odd Function)`