Geometric Sequences

Question 1 of 3

Given the sequence

3, 6, 12, 24 \dots

$3,6,12,24…$ , find:

(i)

$(i)$ The

8 t h

$8th$ term

(i i)

$(ii)$ If

1536

$1536$ is part of the sequence

For part

i i

$ii$ , write

Y

$Y$ for yes and

N

$N$ for no

$(i)$ $(i)$ $U_{8} =$ $U_8=$ (384)

$(i i)$ $(ii)$ (Y, y)

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General Rule of a Geometric Sequence

U_{n} = a r^{n - 1}

$U_{\color{#9a00c7}{n}}=\color{#e65021}{a}\color{#00880A}{r}^{\color{#9a00c7}{n}-1}$

Common Ratio Formula

r = \frac{U_{2}}{U_{1}} = \frac{U_{3}}{U_{2}}

$\color{#00880A}{r}=\frac{U_2}{U_1}=\frac{U_3}{U_2}$

(i)

$(i)$ Finding the

8 t h

$8th$ term

First, solve for the value of $r$ $r$ .

$\color{#00880A}{r}$	$=$ $=$	$\frac{U_2}{U_1}$

	$=$ $=$	$\frac{6}{3}$	Substitute the first and second term

	$=$ $=$	$2$ $2$

Next, substitute the known values to the general rule

$Number of terms$ $\text(Number of terms)$ $[n]$ $[n]$	$=$ $=$	$8$ $8$
$First term$ $\text(First term)$ $[a]$ $[a]$	$=$ $=$	$3$ $3$
$\text(Common Ratio)$ $[r]$	$=$	$2$

$U_{\color{#9a00c7}{n}}$	$=$	$\color{#e65021}{a}\color{#00880A}{r}^{\color{#9a00c7}{n}-1}$

$U_{\color{#9a00c7}{8}}$	$=$	$\color{#e65021}{3}\cdot\color{#00880A}{2}^{\color{#9a00c7}{8}-1}$	Substitute known values

	$=$	$3\cdot(2^7)$	Evaluate
	$=$	$3\cdot128$
	$=$	$384$

$(ii)$ Finding if

$1536$ is part of the sequence

Next, substitute the known values to the general rule and solve for $n$

$\text(Nth term)$ $[U_n]$	$=$	$1536$
$\text(First term)$ $[a]$	$=$	$3$
$\text(Common Ratio)$ $[r]$	$=$	$2$

$U_{\color{#9a00c7}{n}}$	$=$	$\color{#e65021}{a}\color{#00880A}{r}^{\color{#9a00c7}{n}-1}$

$1536$	$=$	$\color{#e65021}{3}\cdot\color{#00880A}{2}^{\color{#9a00c7}{n}-1}$	Substitute known values

$1536$ $divide3$	$=$	$3(2^(n-1))$ $divide3$	Divide both sides by $3$
$512$	$=$	$2^(n-1)$
$2^9$	$=$	$2^(n-1)$	$512=2^9$
$9$	$=$	$n-1$	Equate the exponents
$9$ $+1$	$=$	$n-1$ $+1$	Add $1$ to both sides
$10$	$=$	$n$
$n$	$=$	$10$

$1536$ is the value of the

$10th$ term. Therefore, it is a part of the sequence

$(i) U_8=384$

$(ii) \text(Yes)$

Question 2 of 3

Find the value of

$n$

$6,3,1 1/2…3/(128)$

$n=$ (9)

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General Rule of a Geometric Sequence

$U_{\color{#9a00c7}{n}}=\color{#e65021}{a}\color{#00880A}{r}^{\color{#9a00c7}{n}-1}$

Common Ratio Formula

$\color{#00880A}{r}=\frac{U_2}{U_1}=\frac{U_3}{U_2}$

First, solve for the value of $r$ .

$\color{#00880A}{r}$	$=$	$\frac{U_2}{U_1}$

	$=$	$\frac{3}{6}$	Substitute the first and second term

	$=$	$1/2$

Next, substitute the known values to the general rule and solve for $n$

$\text(Nth term)$ $[U_n]$	$=$	$3/128$

$\text(First term)$ $[a]$	$=$	$6$

$\text(Common Ratio)$ $[r]$	$=$	$1/2$

$U_{\color{#9a00c7}{n}}$	$=$	$\color{#e65021}{a}\color{#00880A}{r}^{\color{#9a00c7}{n}-1}$

$\frac{3}{128}$	$=$	$\color{#e65021}{6}\cdot\color{#00880A}{\frac{1}{2}}^{\color{#9a00c7}{n}-1}$	Substitute known values

$3/128$ $times1/6$	$=$	$[6(1/2)^(n-1)]$ $times1/6$	Multiply both sides by $1/6$

$1/256$	$=$	$(1/2)^(n-1)$	$6/6=1$

$1/(2^8)$	$=$	$1/(2^(n-1))$	$256=2^8$

$8$	$=$	$n-1$	Equate the exponents
$8$ $+1$	$=$	$n-1$ $+1$	Add $1$ to both sides
$9$	$=$	$n$
$n$	$=$	$9$

$n=9$

Question 3 of 3

Find the

$8th$ term

$2/7+3/7+9/14…$

1. $4 448/53$
2. $4 395/448$
3. $5 53/448$
4. $4 448/395$

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General Rule of a Geometric Sequence

$U_{\color{#9a00c7}{n}}=\color{#e65021}{a}\color{#00880A}{r}^{\color{#9a00c7}{n}-1}$

Common Ratio Formula

$\color{#00880A}{r}=\frac{U_2}{U_1}=\frac{U_3}{U_2}$

First, solve for the value of $r$ .

$\color{#00880A}{r}$	$=$	$\frac{U_2}{U_1}$

	$=$	$\frac{\frac{3}{7}}{\frac{2}{7}}$	Substitute the first and second term

	$=$	$3/2$

Next, substitute the known values to the general rule

$\text(Number of terms)$ $[n]$	$=$	$8$

$\text(First term)$ $[a]$	$=$	$2/7$

$\text(Common Ratio)$ $[r]$	$=$	$3/2$

$U_{\color{#9a00c7}{n}}$	$=$	$\color{#e65021}{a}\color{#00880A}{r}^{\color{#9a00c7}{n}-1}$

$U_{\color{#9a00c7}{8}}$	$=$	$\color{#e65021}{\frac{2}{7}}\cdot\color{#00880A}{\frac{3}{2}}^{\color{#9a00c7}{8}-1}$	Substitute known values

	$=$	$\frac{2}{7}\cdot\left(\frac{3}{2}\right)^2$	Evaluate

	$=$	$\frac{2}{7}\cdot\frac{2187}{128}$

	$=$	$2187/448$

	$=$	$4 395/448$	Simplify

$U_8=4 395/448$

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Quiz summary

Information

1. Question

Hint

Correct!

General Rule of a Geometric Sequence

Common Ratio Formula

2. Question

Hint

Fantastic!

General Rule of a Geometric Sequence

Common Ratio Formula

3. Question

Hint

Excellent!

General Rule of a Geometric Sequence

Common Ratio Formula

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